Skip to content

Ideal Bose Gas

The ideal Bose gas is a free many-body model in which bosonic occupation statistics, together with the infrared structure of a specified one-particle spectrum, determine equilibrium thermodynamics and whether an excited-state capacity limit permits macroscopic occupation of a lowest mode.

This dossier fixes the model data, solvability claim, important limits, observables, and validation targets. The Ideal Bose Gas teaching article owns the full box calculation, density-of-states derivation, and equation of state. Bose–Einstein Condensation owns the general condensate criterion and transition analysis.

Unless a variant is named explicitly, this dossier uses the following model.

FieldBaseline choice
particlesone species of identical spinless bosons
spacea cubic box of side LL and volume V=L3V=L^3
boundariesperiodic in all three directions
one-particle Hamiltonianh=p2/(2m)h=\mathbf p^2/(2m)
ground energyϵ0=0\epsilon_{\mathbf0}=0
many-body spacebosonic Fock space, or its fixed-NN sector
conserved chargetotal particle number NN
equilibrium controlsT,V,μT,V,\mu or T,V,NT,V,N
thermodynamic limitN,V→∞N,V\to\infty at fixed density n=N/Vn=N/V
interactionsabsent

This is not the same model as an ideal gas in a harmonic trap, an ideal lattice Bose gas, a multicomponent gas with separately conserved populations, or a gas of number-nonconserving quasiparticles. Those systems share mode factorization but not the same density of states, chemical-potential constraint, or condensation scale.

The one-particle Hilbert space is

h=L2(TL3),\mathcal h = L^2(\mathbb T_L^3),

where TL3\mathbb T_L^3 is the periodic cube. The bosonic Fock space is

FB(h)=⨁N=0∞Sym⁡Nh.\mathcal F_B(\mathcal h) = \bigoplus_{N=0}^{\infty} \operatorname{Sym}^N\mathcal h.

For fixed particle number, use only

HN=Sym⁡Nh.\mathcal H_N = \operatorname{Sym}^N\mathcal h.

Momentum-mode operators obey

[ak,aq†]=δkq,[ak,aq]=0,[ak†,aq†]=0.\begin{aligned} [a_{\mathbf k},a_{\mathbf q}^\dagger] &= \delta_{\mathbf k\mathbf q}, \\ [a_{\mathbf k},a_{\mathbf q}] &= 0, \\ [a_{\mathbf k}^\dagger,a_{\mathbf q}^\dagger] &= 0. \end{aligned}

Each occupation

nk=ak†akn_{\mathbf k} = a_{\mathbf k}^\dagger a_{\mathbf k}

has eigenvalues 0,1,2,…0,1,2,\ldots. Bosonic exchange symmetry is already built into this occupation-number construction; there are no additional particle labels to symmetrize.

Periodic momenta and one-particle energies are

k=2πLn,n∈Z3,\mathbf k = \frac{2\pi}{L}\mathbf n, \qquad \mathbf n\in\mathbb Z^3,

and

ϵk=ℏ2k22m.\epsilon_{\mathbf k} = \frac{\hbar^2k^2}{2m}.

The many-body Hamiltonian and number operator are

H=∑kϵknk,N=∑knk.\begin{aligned} H &= \sum_{\mathbf k} \epsilon_{\mathbf k}n_{\mathbf k}, \\ N &= \sum_{\mathbf k} n_{\mathbf k}. \end{aligned}

Grand-canonical calculations use

K=H−μN=∑k(ϵk−μ)nk.\begin{aligned} K &= H-\mu N \\ &= \sum_{\mathbf k} \left( \epsilon_{\mathbf k}-\mu \right) n_{\mathbf k}. \end{aligned}

At finite positive temperature, convergence requires

μ<ϵ0.\mu < \epsilon_{\mathbf0}.

With the baseline energy zero, this becomes μ<0\mu<0. In the condensed thermodynamic limit, μ\mu approaches zero from below; it does not cross above the lowest one-particle energy.

The absolute one-particle energy zero is conventional. Under

ϵk′=ϵk+C,μ′=μ+C,\epsilon_{\mathbf k}' = \epsilon_{\mathbf k}+C, \qquad \mu' = \mu+C,

one has

H′=H+CN,K′=H′−μ′N=K.\begin{aligned} H' &= H+CN, \\ K' &= H'-\mu'N = K. \end{aligned}

Occupations and all grand-canonical probabilities are unchanged. A comparison that shifts ϵ0\epsilon_{\mathbf0} but not μ\mu has changed the physical state rather than merely changing convention.

StructureBaseline statementQualification
global phaseak↦eiθaka_{\mathbf k}\mapsto e^{i\theta}a_{\mathbf k}generated by NN
particle number[H,N]=0[H,N]=0choose canonical or grand-canonical treatment explicitly
translationtotal momentum is conservedexact for periodic uniform geometry
cubic point groupthe finite box preserves cubic rotations and reflectionsfull spatial rotations emerge only in the continuum thermodynamic description
time reversalpresent in the absence of gauge fields or rotationmaps k\mathbf k to −k-\mathbf k
mode occupations[H,nk]=0[H,n_{\mathbf k}]=0 for every k\mathbf kdestroyed by generic interactions

The independently conserved mode occupations are the strongest signature of the free model. They make the equilibrium spectrum trivial to label, but they also mean the isolated model contains no collision mechanism that would dynamically establish a thermal distribution from a generic initial state.

The thermal de Broglie wavelength is

λT=2πℏ2mkBT.\lambda_T = \sqrt{ \frac{2\pi\hbar^2} {mk_{\mathrm B}T} }.

The principal dimensionless controls are

z=eβμ,D=nλT3,ηL=LλT.\begin{aligned} z &= e^{\beta\mu}, \\ \mathcal D &= n\lambda_T^3, \\ \eta_L &= \frac{L}{\lambda_T}. \end{aligned}

Here zz is fugacity, D\mathcal D is phase-space density for the spinless baseline, and ηL\eta_L measures finite-box resolution. The continuum thermodynamic formulas assume ηL≫1\eta_L\gg1 for the thermally occupied excited states, while the ground mode remains separate.

For the uniform three-dimensional baseline,

Dc=ζ ⁣(32)\mathcal D_c = \zeta\!\left(\frac32\right)

is the excited-state saturation value. Equivalently,

kBTc=2πℏ2m[nζ(3/2)]2/3.k_{\mathrm B}T_c = \frac{2\pi\hbar^2}{m} \left[ \frac{n} {\zeta(3/2)} \right]^{2/3}.

This TcT_c is not portable to another geometry or dispersion without recomputing the one-particle density of states.

An occupation configuration

∣{nk}⟩\lvert\{n_{\mathbf k}\}\rangle

is an exact many-body eigenstate with

E=∑kϵknk,N=∑knk.\begin{aligned} E &= \sum_{\mathbf k} \epsilon_{\mathbf k}n_{\mathbf k}, \\ N &= \sum_{\mathbf k} n_{\mathbf k}. \end{aligned}

For a finite set of modes, the grand partition function factorizes exactly:

Ξ=∏k11−e−β(ϵk−μ).\Xi = \prod_{\mathbf k} \frac{1} {1-e^{-\beta(\epsilon_{\mathbf k}-\mu)}}.

The mean occupation is

n‾k=1eβ(ϵk−μ)−1.\overline n_{\mathbf k} = \frac{1} {e^{\beta(\epsilon_{\mathbf k}-\mu)}-1}.

The exactness claim is quantity-dependent.

QuantityStatusCaveat
finite-volume energies and eigenstatesexact occupation-number solutionrequires the declared one-particle spectrum
grand partition functionexact product over modesconverges only for μ<ϵ0\mu<\epsilon_0 at finite TT
fixed-NN partition functionexactly defined and computable by coefficient extraction or recurrencedoes not factor into independent grand-canonical mode sums
mode occupationsexact in equilibriumensemble must be stated
grand-canonical equal-time correlatorsGaussian and reducible by Wick contractionsfixed-NN states require number-conserving treatment
free dynamicsexact mode phasesno collisions or intrinsic equilibration
thermodynamic-limit formulasexact leading limit for the stated geometryfinite-size corrections and order of limits remain separate
experimental condensate propertiesnot supplied by the ideal model aloneinteractions, trapping, loss, and preparation matter

In the Heisenberg picture,

ak(t)=e−iϵkt/ℏak(0).a_{\mathbf k}(t) = e^{-i\epsilon_{\mathbf k}t/\hbar} a_{\mathbf k}(0).

This solves free evolution, but it does not imply that a nonequilibrium occupation profile relaxes to a Bose–Einstein distribution. Thermal equilibrium is an ensemble assumption for the ideal Hamiltonian, not a consequence of ideal-gas collisions.

For the uniform three-dimensional continuum, separating the ground mode gives

n=N0V+1λT3Li⁡3/2(z).n = \frac{N_0}{V} + \frac{1}{\lambda_T^3} \operatorname{Li}_{3/2}(z).

In the normal phase,

P=kBTλT3Li⁡5/2(z),UV=32P.\begin{aligned} P &= \frac{k_{\mathrm B}T}{\lambda_T^3} \operatorname{Li}_{5/2}(z), \\ \frac{U}{V} &= \frac32 P. \end{aligned}

Below the ideal condensation scale, the thermodynamic-limit excited fraction is

NexN=(TTc)3/2,\frac{N_{\mathrm{ex}}}{N} = \left( \frac{T}{T_c} \right)^{3/2},

so

N0N=1−(TTc)3/2.\frac{N_0}{N} = 1- \left( \frac{T}{T_c} \right)^{3/2}.

These formulas are model fingerprints, not a second derivation. Their derivation, entropy, compressibility, and equation-of-state consequences are developed in the teaching article.

Suppose the excited one-particle density of states near its minimum behaves as

ρex(ϵ)∼Cϵs−1.\rho_{\mathrm{ex}}(\epsilon) \sim C\epsilon^{s-1}.

At saturation, the low-energy number integral behaves as

∫0dϵ ϵs−2.\int_0 d\epsilon\, \epsilon^{s-2}.

It is infrared finite only when

s>1.s>1.

For a uniform dispersion ϵ∝kp\epsilon\propto k^p in dd dimensions,

s=dp.s = \frac{d}{p}.

Thus a uniform quadratic gas has the ordinary finite-temperature capacity limit only for d>2d>2. A harmonic trap has a different density-of-states exponent; a lattice has a band-dependent low-energy density of states. Bose–Einstein Condensation owns the general derivation and Quantum Gases in Traps owns trap state counting.

LimitControlled resultWhat must remain fixed
z≪1z\ll1Maxwell–Boltzmann occupation plus exchange correctionsspectrum, TT, and dilute phase-space density
T→0T\to0 at fixed finite NNparticles occupy a unique ground modeground-state degeneracy and ensemble
V,N→∞V,N\to\infty at fixed nnsharp thermodynamic condensation boundary in the baseline modelorder of limits and density
L/λT→∞L/\lambda_T\to\inftyexcited-mode sums approach continuum integralsdistinguished ground mode kept explicit
d≤2d\le2 with quadratic uniform dispersionno ordinary finite-TT ideal-gas condensationhomogeneous thermodynamic limit
harmonic confinementaltered density of states and condensate-fraction powertrap frequencies and trap thermodynamic limit
weak repulsive interactionideal gas becomes the reference point for Bogoliubov theorydilute parameter and scattering convention
lattice projectionfree bosonic band model; interactions lead toward Bose–Hubbard physicsband, filling, and boundary conditions

The classical limit is not obtained merely by raising the temperature. The relevant requirement is small phase-space density, or equivalently small fugacity in the normal regime.

At finite LL and finite NN:

  • the spectrum is discrete;
  • μ<ϵ0\mu<\epsilon_0 in the grand ensemble;
  • all thermodynamic functions are smooth;
  • there is no exact nonanalytic transition;
  • canonical and grand-canonical condensate fluctuations can differ strongly.

With ϵ0=0\epsilon_0=0, the exact grand-canonical ground-mode occupation is

N0=z1−z.N_0 = \frac{z}{1-z}.

Solving for zz gives

z=N0N0+1<1.z = \frac{N_0}{N_0+1} < 1.

Therefore

μ=kBTln⁡z=−kBTln⁡ ⁣(1+1N0)∼−kBTN0(N0≫1).\begin{aligned} \mu &= k_{\mathrm B}T\ln z \\ &= -k_{\mathrm B}T \ln\!\left( 1+\frac{1}{N_0} \right) \\ &\sim -\frac{k_{\mathrm B}T}{N_0} \qquad (N_0\gg1). \end{aligned}

The thermodynamic shorthand z=1z=1 below TcT_c means this limit has been taken after the ground mode was separated. Substituting z=1z=1 into a finite-volume ground-mode geometric series would make that series diverge.

The grand-canonical mode variance,

Var⁡(nk)=n‾k(1+n‾k),\operatorname{Var}(n_{\mathbf k}) = \overline n_{\mathbf k} \left( 1+\overline n_{\mathbf k} \right),

produces order-one relative fluctuations for a macroscopically occupied ideal ground mode. That result is ensemble- and model-specific; it is not a universal prediction for an interacting fixed-NN condensate.

ObservableIdeal-model form or routeInterpretation caveat
momentum occupationn‾k\overline n_{\mathbf k}depends on μ\mu, TT, and energy-zero convention together
ground-mode occupationN0N_0macroscopic occupation is not by itself superfluidity
pressure and energypolylogarithm formulas in the continuum baselinegeometry and density of states matter
one-body density matrixFourier transform of momentum occupationsPenrose–Onsager eigenvalues give the basis-independent criterion
density correlationsWick contractions in the grand Gaussian statecanonical number projection changes fluctuation relations
compressibilityderivative of the number equationideal condensed gas is pathologically soft
free time correlationsmode phases e−iϵkt/ℏe^{-i\epsilon_{\mathbf k}t/\hbar}no damping or collision-induced linewidth

The model describes Bose enhancement, exchange-statistical pressure corrections, excited-state saturation, and ideal condensation. It does not establish a finite sound speed, vortex energetics, collision rates, hydrodynamic equilibration, or a nonzero Landau critical velocity.

Consider two identical bosons restricted to a nondegenerate ground mode of energy 00 and one excited mode of energy Δ>0\Delta>0. Work in the fixed-N=2N=2 sector. The three occupation states are

∣2,0⟩,∣1,1⟩,∣0,2⟩,\lvert2,0\rangle, \qquad \lvert1,1\rangle, \qquad \lvert0,2\rangle,

with energies 0,Δ,2Δ0,\Delta,2\Delta. Defining

q=e−βΔ,q = e^{-\beta\Delta},

the canonical partition function is

Z2=1+q+q2.Z_2 = 1+q+q^2.

The mean excited-mode occupation is

⟨n1⟩=q+2q21+q+q2.\langle n_1\rangle = \frac{q+2q^2} {1+q+q^2}.

Hence

T→0:⟨n1⟩→0,T→∞:⟨n1⟩→1.\begin{aligned} T\to0 &: \langle n_1\rangle\to0, \\ T\to\infty &: \langle n_1\rangle\to1. \end{aligned}

The high-temperature limit weights the three bosonic Fock configurations equally. There is no extra multiplicity for “which particle” is excited because the particles are identical. This finite model shows Bose occupation counting but has no phase transition.

The canonical numerical contract is MB-B006: Ideal Bose Gas.

Its reference fingerprints include

ζ(3/2)=2.612375348685488…,ζ(5/2)=1.341487257250917….\begin{aligned} \zeta(3/2) &= 2.612375348685488\ldots, \\ \zeta(5/2) &= 1.341487257250917\ldots. \end{aligned}

For the normal-state target

nλT3=1,n\lambda_T^3=1,

the physical fugacity root is

z=0.698614359135065.z = 0.698614359135065.

At

TTc=12,\frac{T}{T_c} = \frac12,

the thermodynamic condensate fraction is

N0N=0.646446609406726.\frac{N_0}{N} = 0.646446609406726.

A valid implementation must:

  1. bracket the normal-state root inside 0<z<10<z<1;
  2. report the number-equation residual separately from quadrature error;
  3. reproduce the zeta values independently of the root solver;
  4. separate the ground mode below TcT_c rather than seeking an unphysical z>1z>1;
  5. distinguish the thermodynamic z=1z=1 prescription from a finite-box calculation;
  6. refine arithmetic or quadrature until the reported digits stabilize.

The notebook name ideal_bose_gas_bec.ipynb is currently a planned artifact, not a committed executable. Its release status and promotion requirements belong to Reproducible Notebooks.

An internal degeneracy factor gg multiplies the normal-state density of states only when the components have matching spectra and chemical potentials. If component populations are separately conserved or the ground level is degenerate, condensate allocation requires additional state data.

Confinement changes the low-energy density of states and the thermodynamic limit. The uniform-box power 3/23/2 for the condensate fraction is not the three-dimensional harmonic-trap power. Use Quantum Gases in Traps for the canonical trapped treatment.

For ideal bosons in a band,

H=∑kϵband(k)nk.H = \sum_{\mathbf k} \epsilon_{\mathrm{band}}(\mathbf k) n_{\mathbf k}.

Mode factorization survives, but bandwidth, band minima, boundary twists, and van Hove structure alter thermodynamics. Adding onsite repulsion produces the Bose–Hubbard Model, which is a different interacting model.

The contact-interaction term

g2∫d3x ψ†ψ†ψψ\frac{g}{2} \int d^3x\, \psi^\dagger\psi^\dagger\psi\psi

destroys independent conservation of every momentum occupation. Weakly Interacting Bose Gas Preview owns the dilute control parameter, sound, depletion, and the bridge to Bogoliubov quasiparticles.

Equilibrium photons and phonons usually have μ=0\mu=0 because their number is not conserved. Their Bose occupation law does not make them the same fixed-particle-number gas used for the baseline condensation calculation.

This dossier owns:

  • the convention-complete baseline record;
  • the energy-zero and chemical-potential audit;
  • the quantity-specific exactness statement;
  • the comparison of finite-volume and thermodynamic claims;
  • the model-variant and benchmark handoffs.

It does not rederive:

  • Writing “ideal Bose gas” without specifying the one-particle spectrum, geometry, and ensemble.
  • Treating the grand Hamiltonian K=H−μNK=H-\mu N as though it were the isolated Hamiltonian HH.
  • Shifting one-particle energies without shifting the chemical potential.
  • Letting μ\mu exceed the lowest one-particle energy.
  • Replacing the entire finite spectrum by a continuum integral and losing the ground mode.
  • Setting z=1z=1 in a finite-volume ground-mode geometric series.
  • Calling a finite-size crossover an exact phase transition.
  • Using the uniform three-dimensional critical temperature for a trap or lattice.
  • Inserting an internal degeneracy factor without specifying population constraints.
  • Calling a fixed-NN thermal state a product of independent grand-canonical mode states.
  • Assuming exact free evolution implies collision-driven thermalization.
  • Identifying condensate fraction with superfluid fraction.
  • Inferring sound, stiffness, or vortex stability from the noninteracting model.
  • Treating the anomalous grand-canonical condensate fluctuation as ensemble independent.
  • Using an unconstrained numerical root finder that can return z>1z>1.
  1. Energy-zero covariance. Show directly that the mean occupation is unchanged by
ϵα↦ϵα+C,μ↦μ+C.\epsilon_\alpha\mapsto\epsilon_\alpha+C, \qquad \mu\mapsto\mu+C.

What goes wrong if only ϵα\epsilon_\alpha is shifted?

Solution

The occupation depends only on the difference:

n‾α=1eβ(ϵα−μ)−1.\overline n_\alpha = \frac{1} {e^{\beta(\epsilon_\alpha-\mu)}-1}.

After shifting both quantities,

ϵα′−μ′=ϵα−μ,\epsilon_\alpha' -\mu' = \epsilon_\alpha-\mu,

so every occupation and grand-canonical weight is unchanged. If only ϵα\epsilon_\alpha is shifted, then ϵα−μ\epsilon_\alpha-\mu changes by CC; the fugacity relative to the spectrum changes, so this is a different equilibrium state.

  1. Finite-box chemical potential. Starting from N0=z/(1−z)N_0=z/(1-z) with ϵ0=0\epsilon_0=0, derive the large-N0N_0 behavior of μ\mu. Explain why it approaches zero from below.
Solution

Solving for zz gives

z=N0N0+1.z = \frac{N_0}{N_0+1}.

Therefore

μ=−kBTln⁡ ⁣(1+1N0).\mu = -k_{\mathrm B}T \ln\!\left( 1+\frac{1}{N_0} \right).

Using ln⁡(1+x)=x+O(x2)\ln(1+x)=x+O(x^2),

μ=−kBTN0+O ⁣(kBTN02).\mu = -\frac{k_{\mathrm B}T}{N_0} + O\!\left( \frac{k_{\mathrm B}T}{N_0^2} \right).

For every finite N0N_0, z<1z<1 and μ<0\mu<0. Zero is reached only as the occupation becomes macroscopic in the relevant thermodynamic sequence.

  1. General infrared test. Let ϵ∝kp\epsilon\propto k^p in dd uniform spatial dimensions. Determine when the saturated excited-state number is infrared finite.
Solution

The low-energy density of states scales as

ρ(ϵ)∝ϵd/p−1.\rho(\epsilon) \propto \epsilon^{d/p-1}.

At saturation,

1eβϵ−1∼1βϵ.\frac{1}{e^{\beta\epsilon}-1} \sim \frac{1}{\beta\epsilon}.

The number integrand is therefore proportional to

ϵd/p−2.\epsilon^{d/p-2}.

Its integral converges at zero when

dp−2>−1,\frac{d}{p}-2>-1,

or

d>p.d>p.

For quadratic dispersion, p=2p=2, so the uniform finite-temperature capacity limit requires d>2d>2.

  1. Two-mode canonical check. For the two-boson, two-mode example, compute the mean energy and its low- and high-temperature limits.
Solution

Since E=Δn1E=\Delta n_1,

⟨E⟩=Δq+2q21+q+q2.\langle E\rangle = \Delta \frac{q+2q^2} {1+q+q^2}.

As T→0T\to0, q→0q\to0 and ⟨E⟩→0\langle E\rangle\to0. As T→∞T\to\infty, q→1q\to1 and

⟨E⟩⟶Δ.\langle E\rangle \longrightarrow \Delta.

The latter is the average of the three equally weighted energies 0,Δ,2Δ0,\Delta,2\Delta.

  1. Uniqueness of the benchmark root. Show that the normal-state equation
Li⁡3/2(z)=1\operatorname{Li}_{3/2}(z)=1

has at most one root in 0<z<10<z<1. Why is bracketing preferable to an unconstrained Newton iteration?

Solution

For 0<z<10<z<1,

ddzLi⁡3/2(z)=Li⁡1/2(z)z>0.\frac{d}{dz} \operatorname{Li}_{3/2}(z) = \frac{ \operatorname{Li}_{1/2}(z) }{z} > 0.

Thus Li⁡3/2(z)\operatorname{Li}_{3/2}(z) is strictly increasing and can cross the target only once. It rises from 00 to ζ(3/2)>1\zeta(3/2)>1, so a root exists and is unique.

A bracketed method preserves the physical interval and the existence guarantee. An unconstrained Newton step can leave 0<z<10<z<1, encounter an unphysical branch, or produce z>1z>1 even when the initial residual is small.

  1. R. K. Pathria and P. D. Beale, Statistical Mechanics, 3rd ed., Elsevier (2011).
  2. K. Huang, Statistical Mechanics, 2nd ed., Wiley (1987).
  3. M. Kardar, Statistical Physics of Particles, Cambridge University Press (2007).
  4. A. L. Fetter and J. D. Walecka, Quantum Theory of Many-Particle Systems, Dover (2003).
  5. C. J. Pethick and H. Smith, Bose–Einstein Condensation in Dilute Gases, 2nd ed., Cambridge University Press (2008).
  6. L. Pitaevskii and S. Stringari, Bose–Einstein Condensation and Superfluidity, Oxford University Press (2016).
  7. O. Penrose and L. Onsager, “Bose–Einstein Condensation and Liquid Helium”, Physical Review 104, 576–584 (1956).
  8. V. Bagnato and D. Kleppner, “Bose–Einstein Condensation in Low-Dimensional Traps”, Physical Review A 44, 7439–7441 (1991).
  9. F. Dalfovo, S. Giorgini, L. P. Pitaevskii, and S. Stringari, “Theory of Bose–Einstein Condensation in Trapped Gases”, Reviews of Modern Physics 71, 463–512 (1999).
  10. I. Bloch, J. Dalibard, and W. Zwerger, “Many-Body Physics with Ultracold Gases”, Reviews of Modern Physics 80, 885–964 (2008).