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Selection Rules in Transition Rates

A selection rule is a symmetry statement that makes a transition matrix element vanish. In transition calculations, the rate is often proportional to a squared matrix element, so a symmetry zero suppresses the transition before any density-of-states or resonance factor matters.

For a weak perturbation V(t)V(t), the first-order transition amplitude contains

⟨f∣VI(t)∣i⟩.\langle f|V_I(t)|i\rangle.

In the golden-rule regime, a typical rate has the form

Γi→f=2πℏ∣Vfi∣2ρ(Ef).\Gamma_{i\to f} = \frac{2\pi}{\hbar} |V_{fi}|^2 \rho(E_f).

If Vfi=0V_{fi}=0 by symmetry, the leading transition rate vanishes.

Selection rules are not guesses about smallness. They are exact zeros under stated assumptions:

  • the Hamiltonian has the relevant symmetry;
  • the states are chosen with definite symmetry labels;
  • the perturbing operator transforms in a definite way;
  • the symmetry is not broken by the environment, boundary conditions, or approximations.

If any assumption fails, the selection rule may be weakened or removed.

Let Π\Pi be the parity operator. Suppose

Π∣i⟩=πi∣i⟩,Π∣f⟩=πf∣f⟩,\Pi\lvert i\rangle = \pi_i\lvert i\rangle, \qquad \Pi\lvert f\rangle = \pi_f\lvert f\rangle,

where πi,πf=±1\pi_i,\pi_f=\pm1. Let OO be an operator with parity πO\pi_O:

ΠOΠ−1=πOO.\Pi O\Pi^{-1} = \pi_O O.

Then

⟨f∣O∣i⟩=πfπOπi⟨f∣O∣i⟩.\langle f|O|i\rangle = \pi_f\pi_O\pi_i \langle f|O|i\rangle.

Therefore the matrix element can be nonzero only if

πfπOπi=1.\pi_f\pi_O\pi_i=1.

For an odd operator, πO=−1\pi_O=-1, transitions connect states of opposite parity. For an even operator, transitions connect states of the same parity.

In the electric dipole approximation, the perturbation is proportional to

d⋅ϵ,\mathbf d\cdot\boldsymbol\epsilon,

where d\mathbf d is odd under parity. Thus electric dipole transitions require opposite parity between initial and final states:

πf=−πi.\pi_f=-\pi_i.

For central-potential orbital states, the position operator transforms as a vector. The familiar orbital angular-momentum rule is

Δℓ=±1.\Delta \ell=\pm1.

The magnetic quantum number changes according to the polarization component:

Δm=0,±1.\Delta m=0,\pm1.

These are electric-dipole rules in the simplest nonrelativistic setting. Spin, fine structure, identical particles, and many-body structure add further labels.

Angular momentum selection rules come from rotational symmetry. A perturbing operator that transforms as a spherical tensor of rank kk can connect angular-momentum states only when angular momenta can couple consistently:

∣ji−k∣≤jf≤ji+k.|j_i-k| \le j_f \le j_i+k.

The magnetic quantum numbers satisfy

mf=mi+q,q=−k,…,k.m_f=m_i+q, \qquad q=-k,\ldots,k.

For a vector operator, k=1k=1, so q=0,±1q=0,\pm1. Clebsch–Gordan coefficients determine which allowed couplings have nonzero angular factors. The systematic theorem behind this factorization is the Wigner–Eckart Theorem.

A selection rule first constrains the amplitude. The transition rate then inherits that constraint:

Vfi=0⟹Γi→f=0V_{fi}=0 \quad \Longrightarrow \quad \Gamma_{i\to f}=0

at the order being computed. Higher-order processes may still occur. For example, a one-photon electric dipole transition may be forbidden while a two-photon process, magnetic dipole process, or symmetry-breaking perturbation gives a much smaller nonzero rate.

Selection rules therefore classify leading mechanisms. They do not imply that a transition is impossible under all physical perturbations.

For continuum processes, the symmetry-allowed matrix element must still be combined with the correctly normalized final-state measure; see Density of States in Transition Rates.

  • Calling a transition forbidden without naming the symmetry and operator.
  • Applying parity rules when the Hamiltonian or environment breaks parity.
  • Treating a leading-order forbidden transition as absolutely impossible.
  • Forgetting that degeneracy can require choosing symmetry-adapted states.
  • Ignoring polarization when applying angular-momentum selection rules.
  1. Two states have the same parity. Can an odd perturbation connect them at first order?
Solution

For an odd perturbation, πO=−1\pi_O=-1. If the states have the same parity, then πfπi=1\pi_f\pi_i=1, so

πfπOπi=−1.\pi_f\pi_O\pi_i=-1.

The matrix element must equal its negative, so it vanishes.

  1. A vector operator has spherical component q=+1q=+1. What magnetic quantum-number change does it imply?
Solution

For a spherical tensor component qq,

mf=mi+q.m_f=m_i+q.

Thus q=+1q=+1 gives Δm=+1\Delta m=+1.

  1. Why can a forbidden electric dipole transition still occur through a weaker process?
Solution

The electric dipole selection rule applies to the electric dipole operator under the stated symmetries. A different operator, such as a magnetic dipole or electric quadrupole operator, transforms differently and may have a nonzero matrix element. Symmetry breaking or higher-order multi-photon processes can also bypass the leading electric dipole rule.

  • J. J. Sakurai and J. Napolitano, Modern Quantum Mechanics, 3rd ed., Cambridge University Press, 2020.
  • C. Cohen-Tannoudji, B. Diu, and F. Laloë, Quantum Mechanics, Wiley, 1977.
  • A. R. Edmonds, Angular Momentum in Quantum Mechanics, Princeton University Press, 1996.
  • D. A. Varshalovich, A. N. Moskalev, and V. K. Khersonskii, Quantum Theory of Angular Momentum, World Scientific, 1988.