Skip to content

Landau Levels

Landau levels are the discrete kinetic-energy levels of a charged particle moving in a uniform magnetic field. They are the canonical example of magnetic quantization: a continuous two-dimensional free-particle spectrum collapses into equally spaced levels, each with a large degeneracy.

This page treats a spinless nonrelativistic particle of mass mm and charge qq in a prescribed uniform magnetic field

B=Bz^,B>0.\mathbf B=B\hat{\mathbf z}, \qquad B\gt0.

The scalar potential is set to zero. Spin, Zeeman splitting, disorder, interactions, finite-thickness effects, and physical edges are not included in the ideal model. A periodic box in the yy direction is used only to normalize the Landau-gauge states and count bulk orbitals; the bulk limit is taken before interpreting edge physics.

Required background. Minimal Coupling in Wave Mechanics supplies the gauge-covariant kinetic momentum and Hamiltonian used below.

Helpful background. Particle in a Uniform Magnetic Field separates parallel and transverse motion; the Quantum Harmonic Oscillator supplies the ladder; Dimensionless Variables and Scaling supplies scale checks.

The two natural scales are the cyclotron frequency

ωc=∣q∣Bm\omega_c = \frac{\lvert q\rvert B}{m}

and the magnetic length

ℓB=ℏ∣q∣B.\ell_B = \sqrt{ \frac{\hbar}{\lvert q\rvert B} }.

The frequency ωc\omega_c sets the level spacing. The length ℓB\ell_B sets the transverse size of the oscillator wavefunctions and the area associated with one flux quantum. These scales are introduced more generally in Dimensionless Variables and Scaling.

Minimal coupling gives

H^=12m(p^−qA)2.\hat H = \frac{1}{2m} \left( \hat{\mathbf p}-q\mathbf A \right)^2.

Choose the Landau gauge

A=Bx y^.\mathbf A=Bx\,\hat{\mathbf y}.

Then

∇×A=Bz^,\nabla\times\mathbf A = B\hat{\mathbf z},

and the two-dimensional Hamiltonian is

H^=12m[p^x2+(p^y−qBx)2].\hat H = \frac{1}{2m} \left[ \hat p_x^2 + \left( \hat p_y-qBx \right)^2 \right].

For a three-dimensional particle, one simply adds the free longitudinal term p^z2/(2m)\hat p_z^2/(2m).

The Hamiltonian does not depend explicitly on yy, so p^y\hat p_y commutes with H^\hat H. Use a simultaneous eigenfunction of p^y\hat p_y:

ψ(x,y)=eikyyLyφ(x),p^yψ=ℏkyψ.\psi(x,y) = \frac{e^{ik_y y}}{\sqrt{L_y}}\varphi(x), \qquad \hat p_y\psi=\hbar k_y\psi.

Here yy is temporarily placed in a periodic box of length LyL_y, so ky=2πj/Lyk_y=2\pi j/L_y with j∈Zj\in\mathbb Z. We choose the oscillator functions to satisfy

∫−∞∞ ⁣dx ∣φn(x)∣2=1.\int_{-\infty}^{\infty}\!dx\,\lvert\varphi_n(x)\rvert^2=1.

Together with the factor Ly−1/2L_y^{-1/2}, this gives unit norm on R×[0,Ly)\mathbb R\times[0,L_y). The box is a regulator for normalization and state counting, not a claim that the physical sample has no edges.

Substitution gives a one-dimensional equation for φ(x)\varphi(x):

[−ℏ22md2dx2+(qB)22m(x−x0)2]φ=Eφ,\left[ -\frac{\hbar^2}{2m}\frac{d^2}{dx^2} + \frac{(qB)^2}{2m} \left( x-x_0 \right)^2 \right]\varphi = E\varphi,

where

x0=ℏkyqB.x_0 = \frac{\hbar k_y}{qB}.

The sign of x0x_0 depends on the sign of qBqB, but the oscillator frequency is positive:

ωc=∣q∣Bm.\omega_c = \frac{\lvert q\rvert B}{m}.

Thus the Landau-gauge problem is a harmonic oscillator in xx, centered at x0x_0, with no energy dependence on kyk_y.

The two-dimensional Landau-level energies are

En=ℏωc(n+12),n=0,1,2,….E_n = \hbar\omega_c \left( n+\frac12 \right), \qquad n=0,1,2,\ldots .

The corresponding Landau-gauge wavefunctions have the form

ψn,ky(x,y)=eikyyLyφn(x−x0),\psi_{n,k_y}(x,y) = \frac{e^{ik_y y}}{\sqrt{L_y}} \varphi_n(x-x_0),

where φn\varphi_n is the nnth harmonic-oscillator wavefunction with width ℓB\ell_B.

For a three-dimensional particle with free motion along z^\hat{\mathbf z},

En,kz=ℏωc(n+12)+ℏ2kz22m.E_{n,k_z} = \hbar\omega_c \left( n+\frac12 \right) + \frac{\hbar^2k_z^2}{2m}.

The discreteness is transverse to the magnetic field; the parallel motion remains free unless another potential or boundary condition quantizes it.

Both natural scales have the required dimensions:

[ωc]=T−1,[ℓB]=L,[ℏωc]=E.[\omega_c]=T^{-1}, \qquad [\ell_B]=L, \qquad [\hbar\omega_c]=E.

The degeneracy density below also has dimensions of inverse area because 1/(2πℓB2)=∣q∣B/h1/(2\pi\ell_B^2)=\lvert q\rvert B/h. In the limit B→0B\to0, the spacing ℏωc\hbar\omega_c tends to zero and the degeneracy per unit area of any one level tends to zero. The two-dimensional free-particle continuum is recovered only after summing over the increasingly dense ladder of Landau levels; taking B→0B\to0 at fixed nn does not by itself reproduce a finite free-particle energy.

The label kyk_y changes the oscillator center x0x_0 but not the energy. In Landau gauge, this is how the degeneracy appears: many different guiding-center positions have the same cyclotron energy.

For a spinless two-dimensional particle in a large region of area AA, the bulk degeneracy of each Landau level is

NΦ=A2πℓB2=∣q∣BAh.N_\Phi = \frac{A}{2\pi\ell_B^2} = \frac{\lvert q\rvert BA}{h}.

Equivalently, each orbital Landau level contains one state per flux quantum through the sample. Boundary conditions control the exact finite-size statement. The dedicated counting argument is in Degeneracy of Landau Levels.

Classically, a charged particle in a uniform magnetic field executes circular cyclotron motion. Quantum mechanically, the cyclotron motion is quantized into oscillator-like levels, while the center of the orbit remains a separate degree of freedom.

In Landau gauge, kyk_y labels the guiding-center coordinate x0x_0. This label is gauge dependent; it is not simply a physical momentum in the ordinary free-particle sense. The physical content is that the magnetic field separates motion into:

  • cyclotron motion, whose energy is quantized;
  • guiding-center motion, which accounts for the degeneracy.

The kinetic momentum components do not commute,

[π^x,π^y]=iℏqB,[\hat\pi_x,\hat\pi_y] = i\hbar qB,

so the magnetic field creates an oscillator algebra from the transverse kinetic momenta. The guiding-center coordinates form a second noncommuting pair that labels states inside each Landau level.

Another common choice is symmetric gauge:

A=12B×r=B2(−y x^+x y^).\mathbf A = \frac12\mathbf B\times\mathbf r = \frac{B}{2} \left( -y\,\hat{\mathbf x} +x\,\hat{\mathbf y} \right).

This gauge preserves rotational symmetry about the zz axis, so angular-momentum labels become natural. The wavefunctions look different from the Landau-gauge wavefunctions, but the energies are identical:

En=ℏωc(n+12).E_n = \hbar\omega_c \left( n+\frac12 \right).

The difference between Landau gauge and symmetric gauge is descriptive, not physical. Gauge-invariant quantities such as energy, density profiles after summing over a complete degenerate subspace, flux counting, and current observables do not depend on the gauge used to compute them.

  • Using qB/mqB/m instead of ∣q∣B/m\lvert q\rvert B/m for the positive level spacing.
  • Treating kyk_y in Landau gauge as an ordinary gauge-invariant momentum.
  • Forgetting that the ideal Landau levels here are spinless; electron spin adds Zeeman splitting.
  • Counting degeneracy without specifying boundary conditions or sample area.
  • Thinking the Landau-gauge and symmetric-gauge wavefunctions must look the same if they describe the same physics.
  • Forgetting the free kzk_z contribution in the three-dimensional problem.
  1. Starting from the Landau-gauge Hamiltonian, derive the oscillator center x0x_0 and frequency ωc\omega_c.
Solution

With

ψ(x,y)=eikyyφ(x),\psi(x,y)=e^{ik_y y}\varphi(x),

the operator p^y\hat p_y acts as multiplication by ℏky\hbar k_y. Thus

(p^y−qBx)2→(ℏky−qBx)2.\left( \hat p_y-qBx \right)^2 \to \left( \hbar k_y-qBx \right)^2.

Rewrite this as

(qB)2(x−ℏkyqB)2.(qB)^2 \left( x-\frac{\hbar k_y}{qB} \right)^2.

Therefore

x0=ℏkyqB.x_0=\frac{\hbar k_y}{qB}.

The quadratic coefficient satisfies

(qB)22m=12mωc2,\frac{(qB)^2}{2m} = \frac12m\omega_c^2,

so

ωc=∣q∣Bm.\omega_c = \frac{\lvert q\rvert B}{m}.
  1. Use guiding-center spacing to estimate the degeneracy of one Landau level in a rectangle of area A=LxLyA=L_xL_y.
Solution

Periodic boundary conditions along yy give

ky=2πrLy.k_y=\frac{2\pi r}{L_y}.

Since x0=ℏky/(qB)x_0=\hbar k_y/(qB), neighboring allowed kyk_y values correspond to guiding-center spacing

Δx0=2πℏ∣q∣BLy=2πℓB2Ly.\Delta x_0 = \frac{2\pi\hbar}{\lvert q\rvert BL_y} = \frac{2\pi\ell_B^2}{L_y}.

The number of centers that fit in width LxL_x is approximately

NΦ=LxΔx0=LxLy2πℓB2=A2πℓB2.N_\Phi = \frac{L_x}{\Delta x_0} = \frac{L_xL_y}{2\pi\ell_B^2} = \frac{A}{2\pi\ell_B^2}.
  1. Add free motion along zz and find the three-dimensional spectrum.
Solution

For a uniform field along z^\hat{\mathbf z}, the Hamiltonian separates into transverse Landau motion plus free longitudinal motion:

H^=H^⊥+p^z22m.\hat H = \hat H_\perp + \frac{\hat p_z^2}{2m}.

Using p^zeikzz=ℏkzeikzz\hat p_z e^{ik_z z}=\hbar k_z e^{ik_z z}, the energy is

En,kz=ℏωc(n+12)+ℏ2kz22m.E_{n,k_z} = \hbar\omega_c \left( n+\frac12 \right) + \frac{\hbar^2k_z^2}{2m}.
  • Minimal Coupling in Wave Mechanics supplies the Hamiltonian and gauge conventions.
  • Landau Levels in Solids keeps this ideal oscillator result as an input and owns its controlled specialization to anisotropic material bands, internal splittings, valleys, nonparabolicity, and Dirac contrasts.

These pages connect the ideal Landau problem to its setup, symmetries, and applications:

  • D. J. Griffiths and D. F. Schroeter, Introduction to Quantum Mechanics, 3rd ed., Cambridge University Press, 2018.
  • L. D. Landau and E. M. Lifshitz, Quantum Mechanics: Non-Relativistic Theory, 3rd ed., Pergamon, 1977.
  • R. E. Prange and S. M. Girvin, eds., The Quantum Hall Effect, 2nd ed., Springer, 1990.
  • R. Shankar, Principles of Quantum Mechanics, 2nd ed., Springer, 1994.