Skip to content

Bosonic and Fermionic Matsubara Frequencies

Matsubara frequencies are the Fourier modes allowed by thermal boundary conditions on compact imaginary time.

For inverse temperature

β=1kBT,\beta = \frac1{k_{\mathrm B}T},

the Matsubara energies are

Ωm=2πmβbosonic,νn=(2n+1)πβfermionic,\begin{aligned} \Omega_m &= \frac{2\pi m}{\beta} && \text{bosonic}, \\ \nu_n &= \frac{(2n+1)\pi}{\beta} && \text{fermionic}, \end{aligned}

with m,n∈Zm,n\in\mathbb Z. The corresponding angular frequencies are

ωmB=2πmβℏ,ωnF=(2n+1)πβℏ.\begin{aligned} \omega_m^{\mathrm B} &= \frac{2\pi m}{\beta\hbar}, \\ \omega_n^{\mathrm F} &= \frac{(2n+1)\pi}{\beta\hbar}. \end{aligned}

Bosons include a zero mode. Fermions are shifted by half a grid spacing and do not.

This page is the canonical reference for:

  • bosonic and fermionic Matsubara energy grids;
  • explicit-ℏ\hbar angular-frequency conventions;
  • the natural-unit variants;
  • the boundary-condition derivation;
  • negative-index identities and symmetric summation;
  • assignment by total fermion parity;
  • zero modes, minimum frequencies, and temperature spacing;
  • frequency arithmetic at vertices;
  • finite-grid and discrete-Fourier-transform conventions;
  • simple twisted thermal boundary conditions.

Matsubara Formalism Preview owns the complete equilibrium calculation workflow, transform derivation, loop sums, convergence prescriptions, and QFT handoff. Green Functions in Many-Body QM owns single-particle propagator and spectral conventions. Diagrammatic Methods Preview owns line, vertex, self-energy, and diagrammatic rules.

QuantityBosonic channelFermionic channel
boundary conditionF(τ+βℏ)=F(τ)F(\tau+\beta\hbar)=F(\tau)F(τ+βℏ)=−F(τ)F(\tau+\beta\hbar)=-F(\tau)
Matsubara energyΩm=2πm/β\Omega_m=2\pi m/\betaνn=(2n+1)π/β\nu_n=(2n+1)\pi/\beta
angular frequencyωmB=2πm/(βℏ)\omega_m^{\mathrm B}=2\pi m/(\beta\hbar)ωnF=(2n+1)π/(βℏ)\omega_n^{\mathrm F}=(2n+1)\pi/(\beta\hbar)
grid spacing2π/β2\pi/\beta2π/β2\pi/\beta
nearest point to zeroΩ0=0\Omega_0=0ν−1=−π/β\nu_{-1}=-\pi/\beta, ν0=π/β\nu_0=\pi/\beta
negative-index identityΩ−m=−Ωm\Omega_{-m}=-\Omega_mν−n−1=−νn\nu_{-n-1}=-\nu_n
zero modepresentabsent
typical channeldensity, spin, current, pair fieldsingle creation or annihilation field

The argument of a Matsubara Green function is normally written iΩmi\Omega_m or iνni\nu_n. The factor ii identifies a point on the imaginary axis of a complex-energy plane; it is not part of the real number Ωm\Omega_m or νn\nu_n itself.

This page keeps four distinct objects:

SymbolMeaningUnits
β\betainverse temperatureinverse energy
Lτ=βℏL_\tau=\beta\hbarthermal circumferencetime
Ωm\Omega_m, νn\nu_nMatsubara energiesenergy
ωmB\omega_m^{\mathrm B}, ωnF\omega_n^{\mathrm F}angular Matsubara frequenciesinverse time

The conversions are

Ωm=ℏωmB,νn=ℏωnF.\begin{aligned} \Omega_m &= \hbar\omega_m^{\mathrm B}, \\ \nu_n &= \hbar\omega_n^{\mathrm F}. \end{aligned}

In terms of temperature,

Ωm=2πm kBT,νn=(2n+1)πkBT.\begin{aligned} \Omega_m &= 2\pi m\,k_{\mathrm B}T, \\ \nu_n &= (2n+1)\pi k_{\mathrm B}T. \end{aligned}

Many texts use ωn\omega_n for both grids and rely on context. This page uses:

  • Ωm\Omega_m for a bosonic Matsubara energy;
  • νn\nu_n for a fermionic Matsubara energy.

The distinction makes expressions such as

νn+Ωm\nu_n+\Omega_m

visibly fermionic and reduces index-routing errors.

Let the thermal circumference be

Lτ=βℏ.L_\tau = \beta\hbar.

A Fourier mode is

fζ(τ)=e−iζτ/ℏ,f_\zeta(\tau) = e^{-i\zeta\tau/\hbar},

where ζ\zeta has energy units.

For

fζ(τ+Lτ)=fζ(τ),f_\zeta(\tau+L_\tau) = f_\zeta(\tau),

one requires

e−iβζ=1.e^{-i\beta\zeta} = 1.

Thus

βζ=2πm,\beta\zeta = 2\pi m,

which gives

Ωm=2πmβ.\Omega_m = \frac{2\pi m}{\beta}.

For

fζ(τ+Lτ)=−fζ(τ),f_\zeta(\tau+L_\tau) = -f_\zeta(\tau),

one requires

e−iβζ=−1.e^{-i\beta\zeta} = -1.

Therefore

βζ=(2n+1)π,\beta\zeta = (2n+1)\pi,

which gives

νn=(2n+1)πβ.\nu_n = \frac{(2n+1)\pi}{\beta}.

The sign ultimately comes from trace cyclicity combined with graded imaginary-time ordering. It does not mean that a physical fermion state evolves for a time βℏ\beta\hbar and literally returns with a minus sign.

Define the common spacing

Δν:=2πβ.\Delta\nu := \frac{2\pi}{\beta}.

Then

Ωm=mΔν,νn=(n+12)Δν.\begin{aligned} \Omega_m &= m\Delta\nu, \\ \nu_n &= \left( n+\frac12 \right) \Delta\nu. \end{aligned}

Bosonic Matsubara points include zero while fermionic points are shifted by half a spacing

Bosonic and fermionic Matsubara energy grids. Both have spacing Δν=2π/β\Delta\nu=2\pi/\beta, but the fermionic grid is displaced by Δν/2=π/β\Delta\nu/2=\pi/\beta. Divide by ℏ\hbar to obtain angular frequencies.

Around the origin,

…,−4πβ,−2πβ,0,2πβ,4πβ,…\ldots, -\frac{4\pi}{\beta}, -\frac{2\pi}{\beta}, 0, \frac{2\pi}{\beta}, \frac{4\pi}{\beta}, \ldots

corresponds to

…,Ω−2,Ω−1,Ω0,Ω1,Ω2,…\ldots, \Omega_{-2}, \Omega_{-1}, \Omega_0, \Omega_1, \Omega_2, \ldots

Around the origin,

…,−3πβ,−πβ,πβ,3πβ,…\ldots, -\frac{3\pi}{\beta}, -\frac{\pi}{\beta}, \frac{\pi}{\beta}, \frac{3\pi}{\beta}, \ldots

corresponds to

…,ν−2,ν−1,ν0,ν1,…\ldots, \nu_{-2}, \nu_{-1}, \nu_0, \nu_1, \ldots

The labels nearest zero are n=−1n=-1 and n=0n=0, not n=0n=0 and n=1n=1.

For bosons,

Ω−m=−Ωm.\Omega_{-m} = -\Omega_m.

For fermions,

ν−n−1=−νn.\nu_{-n-1} = -\nu_n.

In particular,

ν−1=−ν0=−πβ.\nu_{-1} = -\nu_0 = -\frac{\pi}{\beta}.

The tempting identity ν−n=−νn\nu_{-n}=-\nu_n is false:

ν−n=(1−2n)πβ.\nu_{-n} = \frac{(1-2n)\pi}{\beta}.

If FF is even and the sums converge,

∑m=−∞∞F(Ωm)=F(0)+2∑m=1∞F(Ωm),\sum_{m=-\infty}^{\infty} F(\Omega_m) = F(0) + 2\sum_{m=1}^{\infty} F(\Omega_m),

whereas

∑n=−∞∞F(νn)=2∑n=0∞F(νn).\sum_{n=-\infty}^{\infty} F(\nu_n) = 2\sum_{n=0}^{\infty} F(\nu_n).

The fermionic pairing is between indices nn and −n−1-n-1.

For an odd integrand, a symmetric sum may vanish, but only if the summation prescription respects the pairing and the expression is sufficiently convergent or regulated. A shift of a conditionally convergent series can change an intermediate result.

The grid is determined by the total fermion parity of the operator channel.

Let

(−1)NO(−1)N=(−1)pOO,pO∈{0,1}.\begin{aligned} (-1)^N O(-1)^N &= (-1)^{p_O}O, \\ p_O &\in \{0,1\}. \end{aligned}

Then:

pO=0⟹bosonic grid,pO=1⟹fermionic grid.\begin{aligned} p_O=0 &\Longrightarrow \text{bosonic grid}, \\ p_O=1 &\Longrightarrow \text{fermionic grid}. \end{aligned}
OperatorNumber of odd fermionic factors modulo twoGrid
cic_i or ci†c_i^\dagger1fermionic
ci†cjc_i^\dagger c_j0bosonic
density nin_i0bosonic
spin density0bosonic
current0bosonic
pair field ci↓ci↑c_{i\downarrow}c_{i\uparrow}0bosonic
three-fermion composite1fermionic
elementary boson field bib_i0bosonic

A pair field is built from fermions but is even. Its pair susceptibility therefore carries a bosonic external Matsubara energy and may have an Ω0\Omega_0 component.

A normal single-particle fermion Green function is antiperiodic in the difference of its time arguments. A density-density, spin-spin, or current-current correlator is periodic. The statistics of an internal line and the statistics of the external response channel need not match.

The grids obey:

Ωm+Ωℓ=Ωm+ℓ,νn+Ωm=νn+m,νn−νr=Ωn−r.\begin{aligned} \Omega_m+\Omega_\ell &= \Omega_{m+\ell}, \\ \nu_n+\Omega_m &= \nu_{n+m}, \\ \nu_n-\nu_r &= \Omega_{n-r}. \end{aligned}

These identities encode parity conservation:

  • boson plus boson gives boson;
  • fermion plus boson gives fermion;
  • fermion minus fermion gives boson.

For a density bubble with external Ωℓ\Omega_\ell, the two internal fermionic arguments may be

iνnandiνn+iΩℓ.i\nu_n \qquad \text{and} \qquad i\nu_n+i\Omega_\ell.

The second lies on the fermionic grid because

νn+Ωℓ=νn+ℓ.\nu_n+\Omega_\ell = \nu_{n+\ell}.

The bosonic grid contains

Ω0=0.\Omega_0 = 0.

This mode represents a configuration constant around the thermal circle. It is often important for:

  • static susceptibilities;
  • order-parameter fluctuations;
  • long-distance thermal behavior;
  • dimensional-reduction arguments;
  • infrared divergences near criticality.

The existence of a zero frequency does not imply a divergent propagator. A denominator such as

Ωm2+E2\Omega_m^2+E^2

remains finite at m=0m=0 when E>0E>0. Divergence requires additional infrared structure, such as a vanishing mass or gap.

The nearest fermionic energies are

ν−1=−πβ,ν0=πβ.\nu_{-1} = -\frac{\pi}{\beta}, \qquad \nu_0 = \frac{\pi}{\beta}.

At nonzero temperature, an odd thermal field therefore has a smallest Matsubara-energy magnitude π/β\pi/\beta.

This does not mean that a fermionic system cannot have a zero-energy excitation after analytic continuation. It means only that the discrete imaginary-energy sampling grid has no point at zero for an antiperiodic channel.

The common spacing is

Δν=2πβ=2πkBT.\Delta\nu = \frac{2\pi}{\beta} = 2\pi k_{\mathrm B}T.

The smallest nonzero magnitudes are

∣Ω±1∣=2πkBT,∣ν−1∣=∣ν0∣=πkBT.\begin{aligned} \lvert\Omega_{\pm1}\rvert &= 2\pi k_{\mathrm B}T, \\ \lvert\nu_{-1}\rvert = \lvert\nu_0\rvert &= \pi k_{\mathrm B}T. \end{aligned}

As T→0T\to0,

Δν⟶0,\Delta\nu \longrightarrow 0,

and both grids become dense on the imaginary-energy axis.

As temperature increases, the points spread farther apart. Fewer low-energy samples then lie within a fixed physical bandwidth, while the bosonic zero mode remains at the origin.

Two internally consistent transform conventions are common.

Use ζn=ℏωn\zeta_n=\hbar\omega_n and

FE(iζn)=1ℏ∫0βℏdτ eiζnτ/ℏF(τ).F_E(i\zeta_n) = \frac1\hbar \int_0^{\beta\hbar} d\tau\, e^{i\zeta_n\tau/\hbar} F(\tau).

The inverse is

F(τ)=1β∑ne−iζnτ/ℏFE(iζn).F(\tau) = \frac1\beta \sum_n e^{-i\zeta_n\tau/\hbar} F_E(i\zeta_n).

The sum measure is 1/β1/\beta times a discrete sum.

Use ωn=ζn/ℏ\omega_n=\zeta_n/\hbar and

Fω(iωn)=∫0βℏdτ eiωnτF(τ).F_\omega(i\omega_n) = \int_0^{\beta\hbar} d\tau\, e^{i\omega_n\tau} F(\tau).

The inverse is

F(τ)=1βℏ∑ne−iωnτFω(iωn).F(\tau) = \frac1{\beta\hbar} \sum_n e^{-i\omega_n\tau} F_\omega(i\omega_n).

For the same time-domain function,

Fω(iωn)=ℏFE(iζn).F_\omega(i\omega_n) = \hbar F_E(i\zeta_n).

Mixing the forward transform from one convention with the inverse normalization from the other produces a missing or extra factor of ℏ\hbar.

If

ℏ=kB=1,\hbar = k_{\mathrm B} = 1,

then

β=1T,0≤τ<β,\beta = \frac1T, \qquad 0\leq\tau<\beta,

and

Ωm=2πmT,νn=(2n+1)πT.\begin{aligned} \Omega_m &= 2\pi mT, \\ \nu_n &= (2n+1)\pi T. \end{aligned}

Energy, inverse time, and temperature share the same units. This convenience hides which factors must be restored.

If only kB=1k_{\mathrm B}=1 but ℏ\hbar remains explicit, then β=1/T\beta=1/T while the thermal circumference is still βℏ\beta\hbar and angular frequencies still carry 1/ℏ1/\hbar.

In energy notation, a thermal loop sum is written

1β∑nF(iζn).\frac1\beta \sum_n F(i\zeta_n).

In angular-frequency notation, the corresponding measure is

1βℏ∑nF(iωn).\frac1{\beta\hbar} \sum_n F(i\omega_n).

At zero temperature, under suitable convergence assumptions,

1β∑nF(iζn)⟶∫−∞∞dζ2πF(iζ).\frac1\beta \sum_n F(i\zeta_n) \longrightarrow \int_{-\infty}^{\infty} \frac{d\zeta}{2\pi} F(i\zeta).

The detailed use of these sums, including convergence factors and contour methods, belongs to Matsubara Formalism Preview.

Imaginary-Axis Labels and Analytic Continuation

Section titled “Imaginary-Axis Labels and Analytic Continuation”

The label G(iζn)G(i\zeta_n) means that a function is sampled at discrete points on the imaginary-energy axis. It does not make iζni\zeta_n a physical real frequency. A retarded function is obtained only after identifying an analytic function with the correct spectral and growth properties and taking the boundary value

iζn⟶ω+i0+,i\zeta_n \longrightarrow \omega+i0^+,

with units adjusted to the chosen energy or angular-frequency convention. The advanced boundary value uses ω−i0+\omega-i0^+. Finite noisy Matsubara data generally do not determine this continuation stably without additional information or regularization.

For a grand-canonical ensemble,

K=H−μN.\mathcal K = H-\mu N.

In the standard convention, the bosonic or fermionic grid remains fixed by thermal boundary conditions. The chemical potential enters the operator evolution and propagator denominator through energies measured relative to μ\mu.

For a free fermionic mode,

ξ=ϵ−μ,\xi = \epsilon-\mu,

and the normal propagator has the form

G0(iνn)=1iνn−ξ.\mathcal G_0(i\nu_n) = \frac1{i\nu_n-\xi}.

One should not replace the standard grid by νn−μ\nu_n-\mu without also changing the convention for the thermal boundary condition and time evolution.

A useful generalization is

F(τ+βℏ)=e−iθF(τ),F(\tau+\beta\hbar) = e^{-i\theta} F(\tau),

where θ\theta is defined modulo 2π2\pi. The mode condition becomes

e−iβζ=e−iθ,e^{-i\beta\zeta} = e^{-i\theta},

so

ζn(θ)=2πn+θβ.\zeta_n(\theta) = \frac{2\pi n+\theta}{\beta}.

The standard cases are:

θ=0⟹periodic bosonic grid,θ=π⟹antiperiodic fermionic grid.\begin{aligned} \theta=0 &\Longrightarrow \text{periodic bosonic grid}, \\ \theta=\pi &\Longrightarrow \text{antiperiodic fermionic grid}. \end{aligned}

Twists arise in boundary-condition probes, imaginary chemical potentials, and thermal holonomies. Gauge equivalence, charge assignments, and analytic continuation in chemical potential require additional care; the standard formulas on this page assume θ=0\theta=0 or π\pi.

A computation truncates the infinite grid. The truncation must preserve the symmetry appropriate to the channel.

For a symmetric cutoff MM,

m=−M,…,Mm = -M,\ldots,M

contains 2M+12M+1 points and includes m=0m=0.

A symmetric frequency set may use

n=−M,…,M−1.n = -M,\ldots,M-1.

It contains 2M2M points paired by

n⟷−n−1.n \longleftrightarrow -n-1.

The set includes both ν−1=−π/β\nu_{-1}=-\pi/\beta and ν0=π/β\nu_0=\pi/\beta.

If imaginary time is sampled at NτN_\tau points, the representable frequency range is finite. The exact ordering of positive and negative indices depends on the discrete-Fourier-transform library. A reliable implementation records:

  • whether the time grid includes an endpoint;
  • where zero frequency is stored;
  • how negative frequencies wrap in array order;
  • whether a half-step phase was used for antiperiodic fields;
  • the ultraviolet cutoff implied by the time spacing;
  • the normalization of both transforms.

Do not infer physical asymmetry from an array whose negative-frequency half has merely been stored after the positive-frequency half.

Let E0E_0 be a reference energy and choose

βE0=8.\beta E_0 = 8.

Then the spacing in units of E0E_0 is

ΔνE0=2π8=π4.\frac{\Delta\nu}{E_0} = \frac{2\pi}{8} = \frac{\pi}{4}.

The nearest fermionic points have magnitude

∣ν0∣E0=π8.\frac{\lvert\nu_0\rvert}{E_0} = \frac{\pi}{8}.

Thus the first points are:

ChannelNegative pointZeroPositive point
bosonicΩ−1/E0=−π/4\Omega_{-1}/E_0=-\pi/4Ω0=0\Omega_0=0Ω1/E0=π/4\Omega_1/E_0=\pi/4
fermionicν−1/E0=−π/8\nu_{-1}/E_0=-\pi/8noneν0/E0=π/8\nu_0/E_0=\pi/8

This example is dimensionless and remains valid for any system once βE0\beta E_0 is fixed.

When reading or writing a finite-temperature formula, identify:

  1. Is the symbol an energy or an angular frequency?
  2. Is τ\tau measured in time or inverse-energy units?
  3. Is the channel even or odd under fermion parity?
  4. Does the stated grid include a zero mode?
  5. Are negative fermionic indices paired as nn and −n−1-n-1?
  6. Is the sum measure 1/β1/\beta or 1/(βℏ)1/(\beta\hbar)?
  7. Does a chemical potential enter the generator or an explicitly twisted boundary condition?
  8. Are external and internal frequencies on compatible grids?
  9. Does a finite cutoff preserve positive-negative pairing?
  10. Is a real-frequency statement being inferred only after a valid analytic continuation?
  • Calling νn\nu_n an angular frequency while assigning it energy units.
  • Forgetting ℏ\hbar in ωn=νn/ℏ\omega_n=\nu_n/\hbar.
  • Using the fermionic formula for a density, current, spin, or pair channel.
  • Assuming every object built from fermion operators is fermionic.
  • Writing ν−n=−νn\nu_{-n}=-\nu_n instead of ν−n−1=−νn\nu_{-n-1}=-\nu_n.
  • Omitting the bosonic m=0m=0 term in a symmetric sum.
  • Inserting a fictitious fermionic zero mode.
  • Interpreting the absence of a fermionic zero Matsubara point as a physical spectral gap.
  • Using 1/β1/\beta with an angular-frequency transform that requires 1/(βℏ)1/(\beta\hbar).
  • Shifting a conditionally convergent sum without preserving its regulator.
  • Treating μ\mu as an automatic real shift of the standard Matsubara grid.
  • Confusing a finite FFT array order with increasing signed frequency.
  • Setting ℏ=1\hbar=1 in one line and restoring it by dimensional guesswork later.
  1. T. Matsubara, “A New Approach to Quantum-Statistical Mechanics”, Progress of Theoretical Physics 14, 351–378 (1955) – original imaginary-time many-body formalism.
  2. P. C. Martin and J. Schwinger, “Theory of Many-Particle Systems. I”, Physical Review 115, 1342–1373 (1959) – equilibrium Green functions and thermal boundary structure.
  3. G. Baym and N. D. Mermin, “Determination of Thermodynamic Green’s Functions”, Journal of Mathematical Physics 2, 232–234 (1961) – analytic conditions associated with thermal Green functions.
  4. A. L. Fetter and J. D. Walecka, Quantum Theory of Many-Particle Systems, Dover (2003 reprint of the 1971 edition) – many-body finite-temperature conventions.
  5. G. D. Mahan, Many-Particle Physics, 3rd ed., Springer (2000) – Matsubara sums and condensed-matter applications.
  6. J. W. Negele and H. Orland, Quantum Many-Particle Systems, CRC Press (2018 reissue) – operator and functional finite-temperature methods.
  7. M. Le Bellac, Thermal Field Theory, Cambridge University Press (1996) – thermal frequency conventions in relativistic field theory.
  8. J. I. Kapusta and C. Gale, Finite-Temperature Field Theory, 2nd ed., Cambridge University Press (2006) – thermal sums, zero modes, and field-theory applications.

Suppose a channel obeys

Fp(τ+βℏ)=(−1)pFp(τ),p∈{0,1}.\begin{aligned} F_p(\tau+\beta\hbar) &= (-1)^p F_p(\tau), \\ p &\in \{0,1\}. \end{aligned}

Derive one formula for its allowed Matsubara energies.

Solution

For a mode e−iζτ/ℏe^{-i\zeta\tau/\hbar}, the boundary condition requires

e−iβζ=(−1)p=e−iπp.e^{-i\beta\zeta} = (-1)^p = e^{-i\pi p}.

Therefore

βζ=2πn+πp,\beta\zeta = 2\pi n+\pi p,

up to an integer relabeling. Hence

ζn(p)=(2n+p)πβ.\zeta_n^{(p)} = \frac{(2n+p)\pi}{\beta}.

Setting p=0p=0 gives the bosonic grid, while p=1p=1 gives the fermionic grid.

Starting from the energy convention

F(τ)=1β∑ne−iζnτ/ℏF(iζn),F(\tau) = \frac1\beta\sum_n e^{-i\zeta_n\tau/\hbar}F(i\zeta_n),

set ζn=ℏωn\zeta_n=\hbar\omega_n and define F~(iωn)=ℏF(iζn)\widetilde F(i\omega_n)=\hbar F(i\zeta_n). Show that the same function can be written with the angular-frequency sum measure 1/(βℏ)1/(\beta\hbar).

Solution

Substitution gives

F(τ)=1β∑ne−iωnτF~(iωn)ℏ=1βℏ∑ne−iωnτF~(iωn).F(\tau) = \frac1\beta\sum_n e^{-i\omega_n\tau} \frac{\widetilde F(i\omega_n)}{\hbar} = \frac1{\beta\hbar}\sum_n e^{-i\omega_n\tau} \widetilde F(i\omega_n).

The factor of ℏ\hbar therefore moves between the transform coefficient and the frequency-space function. Mixing the exponent from one convention with the normalization of the other changes dimensions.

Show that the negative of νn\nu_n is ν−n−1\nu_{-n-1}. Use the result to rewrite an even fermionic sum over all integers as a sum over nonnegative nn.

Solution

By definition,

ν−n−1=[2(−n−1)+1]πβ=−(2n+1)πβ=−νn.\begin{aligned} \nu_{-n-1} &= \frac{ \left[ 2(-n-1)+1 \right]\pi }{ \beta } \\ &= -\frac{(2n+1)\pi}{\beta} \\ &= -\nu_n. \end{aligned}

If F(−ν)=F(ν)F(-\nu)=F(\nu) and the sum converges,

∑n=−∞∞F(νn)=2∑n=0∞F(νn).\sum_{n=-\infty}^{\infty} F(\nu_n) = 2 \sum_{n=0}^{\infty} F(\nu_n).

The nonnegative labels n≥0n\geq0 represent the positive-frequency half; the matching negative label is −n−1-n-1.

A natural-unit calculation writes

νn=(2n+1)πT.\nu_n = (2n+1)\pi T.

Restore kBk_{\mathrm B} and ℏ\hbar for both the Matsubara energy and angular frequency.

Solution

Temperature becomes an energy through kBTk_{\mathrm B}T. Therefore

νn=(2n+1)πkBT.\nu_n = (2n+1)\pi k_{\mathrm B}T.

Dividing by ℏ\hbar gives the angular frequency:

ωnF=(2n+1)πkBTℏ.\omega_n^{\mathrm F} = \frac{ (2n+1)\pi k_{\mathrm B}T }{ \hbar }.

The first has energy units; the second has inverse-time units.

Classify the Matsubara grid for each operator:

O1=ci†cj,O2=cicjck,O3=ci↓ci↑,O4=bi†cj.\begin{aligned} O_1 &= c_i^\dagger c_j, \\ O_2 &= c_i c_j c_k, \\ O_3 &= c_{i\downarrow}c_{i\uparrow}, \\ O_4 &= b_i^\dagger c_j. \end{aligned}

Here bib_i is bosonic.

Solution

O1O_1 contains two odd factors and is even, so it uses the bosonic grid.

O2O_2 contains three odd factors and is odd, so it uses the fermionic grid.

O3O_3 is a pair field with two odd factors. It is even and uses the bosonic grid.

O4O_4 contains one odd fermionic factor; the bosonic factor does not change fermion parity. It is odd and uses the fermionic grid.

Let an incoming fermion carry νn\nu_n and an emitted boson carry Ωm\Omega_m. Show that the outgoing fermion energy νn−Ωm\nu_n-\Omega_m remains on the fermionic grid.

Solution

Directly,

νn−Ωm=(2n+1)πβ−2mπβ=[2(n−m)+1]πβ=νn−m.\begin{aligned} \nu_n-\Omega_m &= \frac{(2n+1)\pi}{\beta} - \frac{2m\pi}{\beta} \\ &= \frac{ \left[ 2(n-m)+1 \right]\pi }{ \beta } \\ &= \nu_{n-m}. \end{aligned}

Subtracting a bosonic frequency shifts the integer label but preserves the half-step offset.

For

F(τ+βℏ)=e−iθF(τ),F(\tau+\beta\hbar) = e^{-i\theta}F(\tau),

derive the allowed energies and recover the standard grids at θ=0\theta=0 and θ=π\theta=\pi.

Solution

A mode e−iζτ/ℏe^{-i\zeta\tau/\hbar} must satisfy

e−iβζ=e−iθ.e^{-i\beta\zeta} = e^{-i\theta}.

Thus

βζ=2πn+θ,\beta\zeta = 2\pi n+\theta,

and

ζn(θ)=2πn+θβ.\zeta_n(\theta) = \frac{2\pi n+\theta}{\beta}.

For θ=0\theta=0, this is 2πn/β2\pi n/\beta, the periodic bosonic grid. For θ=π\theta=\pi, it is (2n+1)π/β(2n+1)\pi/\beta, the antiperiodic fermionic grid.

Construct finite bosonic and fermionic index sets that preserve frequency reflection. State the number of points and whether zero is included.

Solution

For bosons, choose

m=−M,…,M.m = -M,\ldots,M.

This set has 2M+12M+1 points, is invariant under m↦−mm\mapsto-m, and includes m=0m=0.

For fermions, choose

n=−M,…,M−1.n = -M,\ldots,M-1.

This set has 2M2M points and is invariant under

n↦−n−1.n \mapsto -n-1.

It contains the pair n=−1,0n=-1,0 nearest the origin and has no zero-frequency point.