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Density of States

This card is the compact lookup. Density of States is the canonical quantum-matter article for crystalline-band normalization, dimensional thresholds, van Hove singularities, projected densities, thermodynamics, spectroscopy, and numerical evaluation.

For a finite spectrum, the exact density of states is the distribution

D(E)=∑αδ(E−Eα),D(E) = \sum_\alpha \delta(E-E_\alpha),

where α\alpha labels independent states.

Equivalently, if N(E)N(E) counts states below energy EE,

D(E)=dNdE.D(E) = \frac{dN}{dE}.

For a periodic single-particle band model in dd dimensions, a common density per volume is

D(E)V=∑n∫BZddk(2π)d δ(E−En(k)).\frac{D(E)}{V} = \sum_n \int_{\mathrm{BZ}} \frac{d^d k}{(2\pi)^d} \, \delta(E-E_n(\mathbf k)).

When the energy shell is smooth and ∇kEn≠0\nabla_{\mathbf k}E_n\ne0, this can be written as

D(E)V=∑n∫En(k)=EdSk(2π)d1∥∇kEn∥.\frac{D(E)}{V} = \sum_n \int_{E_n(\mathbf k)=E} \frac{dS_{\mathbf k}}{(2\pi)^d} \frac{1}{\lVert\nabla_{\mathbf k}E_n\rVert}.
  • The state-counting convention is specified: finite volume, per volume, per unit cell, per spin, or including internal degeneracies.
  • The delta functions are distributions or are replaced by a stated broadening in numerical work.
  • The Brillouin-zone normalization uses the convention compatible with the chosen unit-cell volume.
  • The energy-shell form assumes a smooth constant-energy surface away from critical points.

Density of states is a counting object. It becomes a smooth function only after a thermodynamic limit, coarse graining, or explicit broadening. Singularities can appear at band extrema, saddle points, flat bands, or thresholds where the energy-shell formula requires care.

  • Forgetting spin, valley, orbital, or band degeneracy factors.
  • Mixing total density of states with density per volume or per unit cell.
  • Treating a broadened numerical histogram as an exact formula.
  • Using the energy-shell expression at a critical point where ∇kEn=0\nabla_{\mathbf k}E_n=0.
  • Confusing density of states with occupation probability.

Why does a flat band produce a large density-of-states contribution?

Solution

If many independent states share the same energy, the sum ∑αδ(E−Eα)\sum_\alpha\delta(E-E_\alpha) has many contributions at that energy. In the band expression, a nearly flat En(k)E_n(\mathbf k) also makes ∥∇kEn∥\lVert\nabla_{\mathbf k}E_n\rVert small on the energy shell, enhancing the density of states.

  • N. W. Ashcroft and N. D. Mermin, Solid State Physics, Holt, Rinehart and Winston, 1976.
  • R. K. Pathria and P. D. Beale, Statistical Mechanics, 3rd ed., Academic Press, 2011.
  • S. H. Simon, The Oxford Solid State Basics, Oxford University Press, 2013.