Skip to content

Fock Space

Fock space is the Hilbert space for variable particle number. In nonrelativistic many-body quantum mechanics it is a compact way to organize identical particles. In quantum field theory it becomes the natural language for particle excitations of fields, especially in free or asymptotic theories.

Given a one-particle Hilbert space h\mathcal h, bosonic and fermionic Fock spaces are

FB(h)=⨁N=0∞Sym⁡Nh,FF(h)=⨁N=0∞∧Nh.\mathcal F_B(\mathcal h) = \bigoplus_{N=0}^{\infty} \operatorname{Sym}^N\mathcal h, \qquad \mathcal F_F(\mathcal h) = \bigoplus_{N=0}^{\infty} \wedge^N\mathcal h.

The N=0N=0 sector is the vacuum sector. A basis can be labeled by mode occupations:

∣n1,n2,…⟩.\lvert n_1,n_2,\ldots\rangle.

For bosons ni=0,1,2,…n_i=0,1,2,\ldots. For fermions ni=0n_i=0 or 11.

In a free field theory, each momentum mode behaves like an oscillator. Acting with creation operators on the vacuum builds particle states:

∣p1,…,pN⟩∼ap1†⋯apN†∣0⟩.\lvert \mathbf p_1,\ldots,\mathbf p_N\rangle \sim a^\dagger_{\mathbf p_1}\cdots a^\dagger_{\mathbf p_N} \lvert 0\rangle.

The symbol ∼\sim hides normalization choices. Relativistic continuum normalization, finite-box normalization, and nonrelativistic normalization use different factors.

  • Occupation-number labels.
  • Vacuum as the zero-particle state for a chosen representation.
  • Creation and annihilation operators.
  • Bosonic commutators and fermionic anticommutators.
  • Number operators.
  • Mode expansions.

Field theory changes the status of particle number. In interacting relativistic theories, particle number is usually not conserved. A Fock-space basis is most cleanly tied to free fields and asymptotic scattering states. The interacting vacuum is not merely the empty state of a naive free-particle basis.

  • Treating Fock space as optional notation rather than the natural Hilbert-space structure for variable particle number.
  • Forgetting that the vacuum depends on the Hamiltonian and representation.
  • Assuming particle number is always conserved.
  • Confusing nonrelativistic field operators with relativistic quantum fields.
  • Moving between finite-volume sums and continuum integrals without changing normalization.
  • A. L. Fetter and J. D. Walecka, Quantum Theory of Many-Particle Systems, Dover, 2003.
  • A. Altland and B. D. Simons, Condensed Matter Field Theory, 2nd ed., Cambridge University Press, 2010.
  • M. E. Peskin and D. V. Schroeder, An Introduction to Quantum Field Theory, Westview Press, 1995.
  • S. Weinberg, The Quantum Theory of Fields, Volume I, Cambridge University Press, 1995.
  1. Why does a fermionic mode have only two occupation possibilities?
Solution

For a fermionic creation operator, {ci†,ci†}=0\{c_i^\dagger,c_i^\dagger\}=0, so (ci†)2=0(c_i^\dagger)^2=0. Applying the same creation operator twice gives zero. A single mode can therefore be empty or occupied once, but not occupied twice.