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Pauli Equation

This is a compact lookup card. The magnetic-factor convention, gauge covariance, Zeeman and Landau structure, and regime of validity are owned by the Pauli Equation; the leading reduction is derived on Dirac to Pauli.

For a spin-1/21/2 particle of charge qq in electromagnetic potentials Φ\Phi and A\mathbf A, define

π=−iℏ∇−qA.\boldsymbol\pi = -i\hbar\nabla-q\mathbf A.

The Pauli Hamiltonian with g=2g=2 is

H=12m(σ⋅π)2+qΦ.H = \frac{1}{2m} \left( \boldsymbol\sigma\cdot\boldsymbol\pi \right)^2 + q\Phi.

Using

B=∇×A,\mathbf B=\nabla\times\mathbf A,

this becomes

H=π22m+qΦ−qℏ2mσ⋅B.H = \frac{\boldsymbol\pi^2}{2m} + q\Phi - \frac{q\hbar}{2m} \boldsymbol\sigma\cdot\mathbf B.

The time-dependent equation is

iℏ∂ψ∂t=Hψ,i\hbar\frac{\partial\psi}{\partial t} = H\psi,

where ψ\psi is a two-component spinor.

  • The motion is nonrelativistic, but spin and electromagnetic coupling are retained.
  • The displayed magnetic term corresponds to the Dirac value g=2g=2 and omits anomalous magnetic moment corrections.
  • π=−iℏ∇−qA\boldsymbol\pi=-i\hbar\nabla-q\mathbf A uses the charge sign qq explicitly.
  • The electromagnetic fields are prescribed external backgrounds.

The Pauli equation is the leading nonrelativistic spin-1/21/2 equation with minimal electromagnetic coupling. It is the natural bridge between Pauli spinors and the Dirac equation’s nonrelativistic limit. Higher-order relativistic corrections include spin–orbit coupling, Darwin terms, and magnetic-moment corrections beyond g=2g=2; their crystal-field and Bloch-band projections require additional effective-theory assumptions.

  • Losing the sign of qq in the magnetic term.
  • Treating σ⋅B\boldsymbol\sigma\cdot\mathbf B as a scalar potential rather than a matrix acting on spin.
  • Forgetting that π\boldsymbol\pi components do not commute in a magnetic field.
  • Using the Pauli equation where pair creation, strong relativistic fields, or fully relativistic covariance matter.

For an electron with q=−eq=-e, what sign does the Pauli magnetic term have?

Solution

Insert q=−eq=-e into

−qℏ2mσ⋅B.- \frac{q\hbar}{2m} \boldsymbol\sigma\cdot\mathbf B.

The term becomes

+eℏ2mσ⋅B.+ \frac{e\hbar}{2m} \boldsymbol\sigma\cdot\mathbf B.

The sign convention is tied to the electron’s negative charge and to the Hamiltonian convention used here.

  • W. Pauli, “Zur Quantenmechanik des magnetischen Elektrons”, Zeitschrift für Physik 43, 601-623, 1927.
  • J. J. Sakurai and J. Napolitano, Modern Quantum Mechanics, 3rd ed., Cambridge University Press, 2020.
  • J. J. Sakurai, Advanced Quantum Mechanics, Addison-Wesley, 1967.