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Projection Methods

A projection method separates a quantum problem into a retained subspace PHP\mathcal H and an eliminated subspace QHQ\mathcal H, then accounts for the eliminated amplitudes through an energy-dependent operator acting on PHP\mathcal H. The construction is an exact reorganization of the stationary Schrödinger equation whenever the required inverse exists. Approximation enters only when that inverse, its energy dependence, or the retained space is simplified.

This distinction matters. Merely replacing HH by PHPPHP discards every virtual excursion through QQ. Eliminating QQ instead produces a self-energy that shifts retained levels, induces new couplings, and reconstructs the omitted part of each eigenstate.

This page owns the basic P/Q workflow: block equations, Schur-complement reduction, projected resolvents, state reconstruction, and finite-dimensional examples. Projectors owns the underlying linear algebra. Feshbach Projection Formalism develops continuum boundary conditions, resonances, and optical Hamiltonians; Schrieffer–Wolff Transformation develops perturbative unitary block diagonalization; Effective Hamiltonians in Many-Body Systems owns the Hubbard and Anderson many-body applications.

Let PP be an orthogonal projector and define its complement by

Q=I−P.Q=I-P.

Then

P2=P,Q2=Q,P†=P,Q†=Q,P+Q=I,PQ=QP=0.\begin{aligned} P^2=P, &\qquad Q^2=Q, \\ P^\dagger=P, &\qquad Q^\dagger=Q, \\ P+Q=I, &\qquad PQ=QP=0. \end{aligned}

Every state has the unique orthogonal decomposition

∣Ψ⟩=∣ψP⟩+∣ψQ⟩,\lvert\Psi\rangle = \lvert\psi_P\rangle + \lvert\psi_Q\rangle,

where

∣ψP⟩=P∣Ψ⟩,∣ψQ⟩=Q∣Ψ⟩.\lvert\psi_P\rangle = P\lvert\Psi\rangle, \qquad \lvert\psi_Q\rangle = Q\lvert\Psi\rangle.

Orthogonality gives

∥Ψ∥2=∥ψP∥2+∥ψQ∥2.\lVert\Psi\rVert^2 = \lVert\psi_P\rVert^2 + \lVert\psi_Q\rVert^2.

The model space PHP\mathcal H need not be one-dimensional. It may contain a multiplet, several near-degenerate levels, a band, selected scattering channels, or all states below a chosen cutoff. The complement QHQ\mathcal H contains everything not retained.

The useful projector is chosen by the prediction one wants to preserve, not merely by which basis vectors are convenient. A sound model space usually satisfies three requirements:

  1. It contains every state that mixes strongly at the energy resolution of interest.
  2. The action of the eliminated sector can be computed or approximated more easily than the full problem.
  3. The relevant energy lies away from singularities of the eliminated-sector resolvent, unless those singularities are being treated explicitly.

If a nominally eliminated level is nearly resonant with a retained level, a denominator becomes small. The usual remedy is not to manipulate the denominator more aggressively; it is to enlarge PP. Quasi-Degenerate Perturbation Theory makes this model-space rule systematic.

Relative to

H=PH⊕QH,\mathcal H = P\mathcal H \oplus Q\mathcal H,

define

HPP=PHP,HPQ=PHQ,HQP=QHP,HQQ=QHQ.\begin{aligned} H_{PP}&=PHP, & H_{PQ}&=PHQ, \\ H_{QP}&=QHP, & H_{QQ}&=QHQ. \end{aligned}

The Hamiltonian can then be read as the block operator

H=(HPPHPQHQPHQQ).H = \begin{pmatrix} H_{PP} & H_{PQ} \\ H_{QP} & H_{QQ} \end{pmatrix}.

For a self-adjoint Hamiltonian,

HPP†=HPP,HQQ†=HQQ,HQP=HPQ†.\begin{aligned} H_{PP}^\dagger &= H_{PP}, & H_{QQ}^\dagger &= H_{QQ}, \\ H_{QP} &= H_{PQ}^\dagger. \end{aligned}

The diagonal blocks generate motion within each sector. The off-diagonal blocks transfer amplitude between them. In particular, PHP\mathcal H is an invariant subspace of a self-adjoint HH precisely when

HPQ=HQP=0,H_{PQ}=H_{QP}=0,

or equivalently when [P,H]=0[P,H]=0.

Projecting the exact eigenvalue equation

H∣Ψ⟩=E∣Ψ⟩H\lvert\Psi\rangle = E\lvert\Psi\rangle

with PP and QQ gives

HPP∣ψP⟩+HPQ∣ψQ⟩=E∣ψP⟩,HQP∣ψP⟩+HQQ∣ψQ⟩=E∣ψQ⟩.\begin{aligned} H_{PP}\lvert\psi_P\rangle + H_{PQ}\lvert\psi_Q\rangle &= E\lvert\psi_P\rangle, \\ H_{QP}\lvert\psi_P\rangle + H_{QQ}\lvert\psi_Q\rangle &= E\lvert\psi_Q\rangle. \end{aligned}

These two equations are exactly equivalent to the original one. No small parameter has appeared.

Projection of an exact eigenvalue problem into retained P and eliminated Q sectors, followed by a Q-space resolvent excursion and reconstruction of the full state.

Projection does not simply erase QQ. The resolvent RQ(E)=(E−HQQ)−1R_Q(E)=(E-H_{QQ})^{-1} propagates an amplitude through the eliminated sector. Returning to PP produces the self-energy ΣP(E)\Sigma_P(E), while the same excursion reconstructs ∣ψQ⟩\lvert\psi_Q\rangle.

Exact Elimination and the Schur Complement

Section titled “Exact Elimination and the Schur Complement”

Suppose E−HQQE-H_{QQ} is invertible on QHQ\mathcal H. Define the eliminated-space resolvent

RQ(E)=(E−HQQ)−1.R_Q(E) = \left( E-H_{QQ} \right)^{-1}.

The second block equation can be solved exactly:

∣ψQ⟩=RQ(E)HQP∣ψP⟩.\lvert\psi_Q\rangle = R_Q(E) H_{QP}\lvert\psi_P\rangle.

Substitution into the first block equation gives

Heff(E)∣ψP⟩=E∣ψP⟩,H_{\mathrm{eff}}(E) \lvert\psi_P\rangle = E\lvert\psi_P\rangle,

where

Heff(E)=HPP+ΣP(E),ΣP(E)=HPQRQ(E)HQP.\begin{aligned} H_{\mathrm{eff}}(E) &= H_{PP} + \Sigma_P(E), \\ \Sigma_P(E) &= H_{PQ} R_Q(E) H_{QP}. \end{aligned}

The self-energy ΣP(E)\Sigma_P(E) represents the ordered process

P→ HQP Q→ RQ(E) Q→ HPQ P.P \xrightarrow{\,H_{QP}\,} Q \xrightarrow{\,R_Q(E)\,} Q \xrightarrow{\,H_{PQ}\,} P.

It contains every repeated interaction internal to HQQH_{QQ} because the resolvent is exact. The formula therefore does not assume weak PP–QQ coupling. It does, however, replace a linear eigenvalue problem on the full Hilbert space with a generally nonlinear eigenvalue problem on PHP\mathcal H, because the operator being diagonalized depends on the unknown EE.

In finite dimensions the same reduction is the Schur complement of E−HQQE-H_{QQ}. Wherever this block is invertible,

det⁡(EI−H)=det⁡(EIQ−HQQ)×det⁡ ⁣(EIP−Heff(E)).\begin{aligned} \det(EI-H) &= \det(EI_Q-H_{QQ}) \\ &\quad\times \det\!\left( EI_P-H_{\mathrm{eff}}(E) \right). \end{aligned}

Thus the reduced secular equation reproduces the full eigenvalues that have nonzero projection into PP. The apparent poles in Heff(E)H_{\mathrm{eff}}(E) are essential: when the factors are multiplied, pole-zero cancellations recover the polynomial characteristic equation of the full matrix.

An eigenstate lying entirely in QHQ\mathcal H has ∣ψP⟩=0\lvert\psi_P\rangle=0 and is not represented by a nonzero solution of the reduced equation. This is expected. A projection method preserves information seen by the chosen model space; it does not promise to expose states orthogonal to it.

Projection can reduce the resolvent itself, not only individual eigenvectors. Let

G(z)=(z−H)−1,G(z) = \left( z-H \right)^{-1},

with zz outside the spectra needed to define the inverses. The PP block obeys

PG(z)P=[z−Heff(z)]−1,PG(z)P = \left[ z-H_{\mathrm{eff}}(z) \right]^{-1},

where

Heff(z)=HPP+HPQ(z−HQQ)−1HQP.H_{\mathrm{eff}}(z) = H_{PP} + H_{PQ} \left( z-H_{QQ} \right)^{-1} H_{QP}.

This identity explains why an energy-dependent effective Hamiltonian can reproduce projected spectral poles and response functions exactly. It also shows what it is designed to match: the PP-space Green function, not necessarily a globally defined, energy-independent operator on the full Hilbert space. The Resolvent Operator page develops the spectral and analytic meaning of G(z)G(z).

Solving the reduced equation is only half of the construction. The eliminated component is

∣ψQ⟩=RQ(E)HQP∣ψP⟩,\lvert\psi_Q\rangle = R_Q(E) H_{QP}\lvert\psi_P\rangle,

so the full eigenstate is

∣Ψ⟩=[P+RQ(E)HQP]∣ψP⟩.\lvert\Psi\rangle = \left[ P + R_Q(E)H_{QP} \right] \lvert\psi_P\rangle.

For a real bound-state energy outside the spectrum of HQQH_{QQ}, the resolvent is self-adjoint. Differentiating the effective Hamiltonian gives

∂Heff∂E=−HPQRQ(E)2HQP.\frac{\partial H_{\mathrm{eff}}}{\partial E} = - H_{PQ} R_Q(E)^2 H_{QP}.

Consequently,

⟨Ψ∣Ψ⟩=⟨ψP∣ψP⟩+⟨ψQ∣ψQ⟩=⟨ψP∣IP−∂Heff∂E∣ψP⟩.\begin{aligned} \langle\Psi\vert\Psi\rangle &= \langle\psi_P\vert\psi_P\rangle + \langle\psi_Q\vert\psi_Q\rangle \\ &= \left\langle\psi_P\left| I_P - \frac{\partial H_{\mathrm{eff}}}{\partial E} \right|\psi_P\right\rangle. \end{aligned}

The projected eigenvector should therefore not generally be normalized as though it were the full state. If a solution direction ∣ψ^P⟩\lvert\widehat\psi_P\rangle has unit norm inside PP, the probability carried by the retained sector after full normalization is

ZP=[⟨ψ^P∣IP−∂Heff∂E∣ψ^P⟩]−1.Z_P = \left[ \left\langle\widehat\psi_P\left| I_P - \frac{\partial H_{\mathrm{eff}}}{\partial E} \right|\widehat\psi_P\right\rangle \right]^{-1}.

Because −∂EHeff-\partial_EH_{\mathrm{eff}} is positive semidefinite in this bound-state setting, 0<ZP≤10\lt Z_P\le1.

Define the energy-dependent embedding on the model space by

Ω(E)=P+RQ(E)HQP.\Omega(E) = P + R_Q(E)H_{QP}.

Then ∣Ψ⟩=Ω(E)∣ψP⟩\lvert\Psi\rangle=\Omega(E)\lvert\psi_P\rangle. For an observable OO, its exact reduced matrix element is built from

Oeff(E)=Ω(E)†OΩ(E),O_{\mathrm{eff}}(E) = \Omega(E)^\dagger O \Omega(E),

together with the norm operator

N(E)=Ω(E)†Ω(E)=IP−∂Heff∂E.N(E) = \Omega(E)^\dagger\Omega(E) = I_P - \frac{\partial H_{\mathrm{eff}}}{\partial E}.

For one reconstructed state,

⟨O⟩=⟨ψP∣Oeff(E)∣ψP⟩⟨ψP∣N(E)∣ψP⟩.\langle O\rangle = \frac{ \langle\psi_P\vert O_{\mathrm{eff}}(E) \vert\psi_P\rangle }{ \langle\psi_P\vert N(E) \vert\psi_P\rangle }.

Using HeffH_{\mathrm{eff}} while replacing every observable by POPPOP omits the same virtual admixtures that generated the effective Hamiltonian. In a Schrieffer–Wolff treatment this information appears as the unitary dressing of states and observables.

Consider

H=(εpgg∗εq),H = \begin{pmatrix} \varepsilon_p & g \\ g^* & \varepsilon_q \end{pmatrix},

and retain the first basis state. Then

Heff(E)=εp+∣g∣2E−εq.H_{\mathrm{eff}}(E) = \varepsilon_p + \frac{\lvert g\rvert^2} {E-\varepsilon_q}.

The reduced eigenvalue equation is

E=εp+∣g∣2E−εq.E = \varepsilon_p + \frac{\lvert g\rvert^2} {E-\varepsilon_q}.

Multiplying by E−εqE-\varepsilon_q gives

(E−εp)(E−εq)−∣g∣2=0,(E-\varepsilon_p) (E-\varepsilon_q) - \lvert g\rvert^2 = 0,

with exact roots

E±=εp+εq2±(εp−εq2)2+∣g∣2.E_\pm = \frac{\varepsilon_p+\varepsilon_q}{2} \pm \sqrt{ \left( \frac{\varepsilon_p-\varepsilon_q}{2} \right)^2 + \lvert g\rvert^2 }.

The eliminated amplitude satisfies

ψqψp=g∗E−εq.\frac{\psi_q}{\psi_p} = \frac{g^*} {E-\varepsilon_q}.

If the projected component is initially assigned unit norm, the retained probability in the normalized full eigenstate is

ZP(E)=[1+∣g∣2(E−εq)2]−1.Z_P(E) = \left[ 1 + \frac{\lvert g\rvert^2} {(E-\varepsilon_q)^2} \right]^{-1}.

This agrees with the derivative formula because

∂Heff∂E=−∣g∣2(E−εq)2.\frac{\partial H_{\mathrm{eff}}}{\partial E} = - \frac{\lvert g\rvert^2} {(E-\varepsilon_q)^2}.

Let d=εp−εqd=\varepsilon_p-\varepsilon_q and suppose ∣g/d∣≪1\lvert g/d\rvert\ll1. The root connected continuously to εp\varepsilon_p is

Ep=εp+∣g∣2d−∣g∣4d3+O ⁣(∣g∣6d5).E_p = \varepsilon_p + \frac{\lvert g\rvert^2}{d} - \frac{\lvert g\rvert^4}{d^3} + O\!\left( \frac{\lvert g\rvert^6}{d^5} \right).

The familiar second-order energy denominator is therefore the first approximation to an exact energy-dependent equation. Near d=0d=0, the expansion fails while the exact square root remains regular and produces an avoided crossing.

Let two retained states couple to one remote state:

H=(ε10g1∗0ε2g2∗g1g2Δ).H = \begin{pmatrix} \varepsilon_1 & 0 & g_1^* \\ 0 & \varepsilon_2 & g_2^* \\ g_1 & g_2 & \Delta \end{pmatrix}.

Choose PP to retain the first two basis states and QQ to retain the third. Exact elimination gives

Heff(E)=(ε100ε2)+1E−Δ(∣g1∣2g1∗g2g2∗g1∣g2∣2).\begin{aligned} H_{\mathrm{eff}}(E) &= \begin{pmatrix} \varepsilon_1 & 0 \\ 0 & \varepsilon_2 \end{pmatrix} \\ &\quad+ \frac{1}{E-\Delta} \begin{pmatrix} \lvert g_1\rvert^2 & g_1^*g_2 \\ g_2^*g_1 & \lvert g_2\rvert^2 \end{pmatrix}. \end{aligned}

Even though the retained states have no direct matrix element, the eliminated state mediates one. If

∣E∣,∣ε1∣,∣ε2∣≪∣Δ∣,\lvert E\rvert, \lvert\varepsilon_1\rvert, \lvert\varepsilon_2\rvert \ll \lvert\Delta\rvert,

freezing the denominator at E=0E=0 gives

Heff≃(ε100ε2)−1Δ(∣g1∣2g1∗g2g2∗g1∣g2∣2).\begin{aligned} H_{\mathrm{eff}} &\simeq \begin{pmatrix} \varepsilon_1 & 0 \\ 0 & \varepsilon_2 \end{pmatrix} \\ &\quad- \frac{1}{\Delta} \begin{pmatrix} \lvert g_1\rvert^2 & g_1^*g_2 \\ g_2^*g_1 & \lvert g_2\rvert^2 \end{pmatrix}. \end{aligned}

The diagonal entries are virtual level shifts. The off-diagonal entries are an induced interaction of order g1∗g2/Δg_1^*g_2/\Delta.

For ε1=ε2=0\varepsilon_1=\varepsilon_2=0, the vector

∣D⟩∝g2∣1⟩−g1∣2⟩\lvert D\rangle \propto g_2\lvert1\rangle - g_1\lvert2\rangle

is annihilated by HQPH_{QP} and is therefore an exact dark eigenstate with energy zero. The orthogonal bright combination couples to QQ and is shifted. Projection makes the distinction transparent: only the component that can leave PP acquires the self-energy.

From Exact Elimination to an Approximation

Section titled “From Exact Elimination to an Approximation”

The exact expression can be expanded around a reference energy E0E_0. Write

R0=(E0−HQQ)−1.R_0 = \left( E_0-H_{QQ} \right)^{-1}.

If

∣E−E0∣∥R0∥<1,\lvert E-E_0\rvert \lVert R_0\rVert \lt1,

the resolvent has the convergent Neumann expansion

RQ(E)=R0−(E−E0)R02+(E−E0)2R03−⋯ .\begin{aligned} R_Q(E) &= R_0 - (E-E_0)R_0^2 \\ &\quad+ (E-E_0)^2R_0^3 - \cdots. \end{aligned}

Keeping only R0R_0 yields the static approximation

Heff≃HPP+HPQR0HQP.H_{\mathrm{eff}} \simeq H_{PP} + H_{PQ}R_0H_{QP}.

If the off-diagonal coupling has scale vv and the eliminated spectrum is separated by a scale Δ\Delta, then

∥ΣP∥∼v2Δ.\lVert\Sigma_P\rVert \sim \frac{v^2}{\Delta}.

The neglected energy dependence is smaller only when the retained energy window is also narrow compared with Δ\Delta. Weak coupling and a narrow model-space window are related but distinct conditions.

This expansion connects several methods:

These are not competing names for one formula. They preserve different structures and organize the same virtual processes in different ways.

For self-adjoint HQQH_{QQ} and real EE outside its spectrum,

∥RQ(E)∥=1dist⁡(E,spec⁡HQQ).\lVert R_Q(E)\rVert = \frac{1}{ \operatorname{dist} \left( E,\operatorname{spec}H_{QQ} \right) }.

Therefore

∥ΣP(E)∥≤∥HPQ∥∥HQP∥dist⁡(E,spec⁡HQQ).\lVert\Sigma_P(E)\rVert \le \frac{ \lVert H_{PQ}\rVert \lVert H_{QP}\rVert }{ \operatorname{dist} \left( E,\operatorname{spec}H_{QQ} \right) }.

For a self-adjoint HH, the numerator is ∥HPQ∥2\lVert H_{PQ}\rVert^2. This estimate captures the small-denominator problem directly. As EE approaches the eliminated spectrum, the resolvent grows, the reconstructed QQ weight grows, and a low-order static approximation loses control.

For the expansion around E0E_0, the resolvent identity gives the explicit bound

∥RQ(E)−R0∥≤∣E−E0∣∥R0∥21−∣E−E0∣∥R0∥.\begin{aligned} \lVert R_Q(E)-R_0\rVert &\le \frac{ \lvert E-E_0\rvert \lVert R_0\rVert^2 }{ 1- \lvert E-E_0\rvert \lVert R_0\rVert }. \end{aligned}

Multiplying by the norms of HPQH_{PQ} and HQPH_{QP} bounds the error made by freezing the self-energy. Small Parameters and Error Estimates develops the broader discipline of turning such ratios into honest validity statements.

In a discrete bound-state problem, EE may lie outside the spectrum of HQQH_{QQ}. In scattering, QHQ\mathcal H can contain a continuum at the physical energy. The resolvent is then specified by a boundary value such as

RQ(E+)=(E+i0−HQQ)−1.R_Q(E^+) = \left( E+i0-H_{QQ} \right)^{-1}.

Formally,

RQ(E+)=P1E−HQQ−iπδ(E−HQQ).R_Q(E^+) = \mathcal P \frac{1}{E-H_{QQ}} - i\pi\delta(E-H_{QQ}).

The self-energy consequently has a real dispersive part and, for open eliminated channels, a negative imaginary part:

ΣP(E+)=ΔP(E)−i2ΓP(E).\Sigma_P(E^+) = \Delta_P(E) - \frac{i}{2}\Gamma_P(E).

The width operator

ΓP(E)=2πHPQδ(E−HQQ)HQP\Gamma_P(E) = 2\pi H_{PQ} \delta(E-H_{QQ}) H_{QP}

is positive semidefinite. It describes probability leaving the retained channel while the full closed-system evolution remains unitary. Thresholds, analytic continuation, resonance poles, and optical potentials are developed at their canonical home, Feshbach Projection Formalism.

QuestionNatural constructionCharacter of the result
What is the exact equation seen by a chosen finite model space?P/Q projection and Schur complementEnergy dependent; exact where the resolvent exists
How do open channels shift and broaden retained states?Feshbach projectionBoundary-value resolvent; generally non-Hermitian in PP
How should several close levels be treated together?Quasi-degenerate perturbation theoryHermitian model-space matrix order by order
How can a separated block be decoupled perturbatively?Schrieffer–Wolff transformationEnergy-independent unitary block diagonalization
How can one iterate an energy-dependent perturbative equation?Brillouin–Wigner perturbation theoryNonlinear eigenvalue problem

The best method is fixed by the desired output. A projected Green function, a reusable low-energy Hamiltonian, and a perturbative spectrum are related objects, but they are not interchangeable without matching states and observables.

The finite-dimensional algebra extends to operators on infinite-dimensional Hilbert spaces only with additional care. For an unbounded Hamiltonian:

  • PP and QQ must act compatibly with the relevant operator domains;
  • the inverse of E−HQQE-H_{QQ} must exist on the vectors to which it is applied;
  • continuum energies require boundary values rather than ordinary bounded inverses;
  • norm estimates may need relative-boundedness or quadratic-form arguments.

Numerically, projection is useful only if applying RQ(E)R_Q(E) is cheaper than solving the full problem. One may never form the inverse explicitly; instead, solve the linear system

(E−HQQ)∣x⟩=HQP∣ψP⟩.\left( E-H_{QQ} \right)\lvert x\rangle = H_{QP}\lvert\psi_P\rangle.

For large sparse problems, this avoids a dense inverse and lets iterative linear solvers exploit the structure of HQQH_{QQ}. Near a pole, however, that linear system becomes ill-conditioned, faithfully signaling that the chosen reduction is difficult.

  • Calling HPPH_{PP} the effective Hamiltonian without accounting for virtual excursions through QQ.
  • Treating the exact elimination formula as though it already were a weak-coupling expansion.
  • Forgetting that Heff(E)H_{\mathrm{eff}}(E) defines a nonlinear eigenvalue problem.
  • Normalizing ∣ψP⟩\lvert\psi_P\rangle as the full state and ignoring the reconstructed QQ weight.
  • Computing observables with POPPOP while retaining self-energy corrections in the Hamiltonian.
  • Freezing the resolvent at E0E_0 without checking the width of the retained energy window.
  • Eliminating a state whose energy is close to the energies being sought.
  • Interpreting a non-Hermitian projected scattering operator as nonunitarity of the full closed system.
  • Using a matrix inverse explicitly when a structured linear solve is more stable.

Starting from H∣Ψ⟩=E∣Ψ⟩H\lvert\Psi\rangle=E\lvert\Psi\rangle, derive the two coupled block equations. Show that [P,H]=0[P,H]=0 implies that PHP\mathcal H and QHQ\mathcal H evolve independently.

Solution

Insert I=P+QI=P+Q on the state and act first with PP:

PH(P+Q)∣Ψ⟩=EP∣Ψ⟩,HPP∣ψP⟩+HPQ∣ψQ⟩=E∣ψP⟩.\begin{aligned} PH(P+Q)\lvert\Psi\rangle &= EP\lvert\Psi\rangle, \\ H_{PP}\lvert\psi_P\rangle + H_{PQ}\lvert\psi_Q\rangle &= E\lvert\psi_P\rangle. \end{aligned}

Acting with QQ similarly gives

HQP∣ψP⟩+HQQ∣ψQ⟩=E∣ψQ⟩.H_{QP}\lvert\psi_P\rangle + H_{QQ}\lvert\psi_Q\rangle = E\lvert\psi_Q\rangle.

If [P,H]=0[P,H]=0, then

PHQ=PH(I−P)=PH−PHP=0,\begin{aligned} PHQ &= PH(I-P) \\ &= PH-PHP \\ &= 0, \end{aligned}

and similarly QHP=0QHP=0. The off-diagonal blocks vanish, so each component satisfies its own equation and no amplitude is transferred between the sectors.

For a finite-dimensional matrix, use block Gaussian elimination to prove

det⁡(EI−H)=det⁡(EIQ−HQQ)×det⁡(EIP−Heff(E)).\begin{aligned} \det(EI-H) &= \det(EI_Q-H_{QQ}) \\ &\quad\times \det(EI_P-H_{\mathrm{eff}}(E)). \end{aligned}
Solution

Write

EI−H=(E−HPP−HPQ−HQPE−HQQ).EI-H = \begin{pmatrix} E-H_{PP} & -H_{PQ} \\ -H_{QP} & E-H_{QQ} \end{pmatrix}.

Left-multiply by the block triangular matrix

L=(IPHPQ(E−HQQ)−10IQ),L = \begin{pmatrix} I_P & H_{PQ}(E-H_{QQ})^{-1} \\ 0 & I_Q \end{pmatrix},

whose determinant is one. Define

SP(E)=E−Heff(E).S_P(E) = E-H_{\mathrm{eff}}(E).

Direct multiplication gives

L(EI−H)=(SP(E)0−HQPE−HQQ).L(EI-H) = \begin{pmatrix} S_P(E) & 0 \\ -H_{QP} & E-H_{QQ} \end{pmatrix}.

The determinant of the resulting block triangular matrix is the product of the two diagonal-block determinants, proving the identity.

For the two-level model, reconstruct the eliminated amplitude and verify both the direct norm formula and the derivative formula for ZP(E)Z_P(E).

Solution

The QQ equation gives

ψq=g∗E−εqψp.\psi_q = \frac{g^*}{E-\varepsilon_q} \psi_p.

Taking ψp=1\psi_p=1 temporarily,

∥Ψ∥2=1+∣g∣2(E−εq)2.\lVert\Psi\rVert^2 = 1 + \frac{\lvert g\rvert^2} {(E-\varepsilon_q)^2}.

The normalized PP weight is therefore

ZP(E)=[1+∣g∣2(E−εq)2]−1.Z_P(E) = \left[ 1 + \frac{\lvert g\rvert^2} {(E-\varepsilon_q)^2} \right]^{-1}.

On the other hand,

∂EHeff(E)=−∣g∣2(E−εq)2,\partial_EH_{\mathrm{eff}}(E) = - \frac{\lvert g\rvert^2} {(E-\varepsilon_q)^2},

so

ZP(E)=[1−∂EHeff(E)]−1.Z_P(E) = \left[ 1-\partial_EH_{\mathrm{eff}}(E) \right]^{-1}.

The two calculations agree.

Set ε1=ε2=0\varepsilon_1=\varepsilon_2=0 in the three-level example. Find one normalized state in PP that does not couple to QQ, and identify the orthogonal bright direction.

Solution

For a retained vector with amplitudes (c1,c2)(c_1,c_2),

HQP(c1c2)=g1c1+g2c2.H_{QP} \begin{pmatrix} c_1\\c_2 \end{pmatrix} = g_1c_1+g_2c_2.

Choosing (c1,c2)=(g2,−g1)(c_1,c_2)=(g_2,-g_1) makes this expression vanish. Thus

∣D⟩=g2∣1⟩−g1∣2⟩∣g1∣2+∣g2∣2\lvert D\rangle = \frac{ g_2\lvert1\rangle-g_1\lvert2\rangle }{ \sqrt{\lvert g_1\rvert^2+\lvert g_2\rvert^2} }

is dark and has no QQ component. An orthogonal normalized bright direction is

∣B⟩=g1∗∣1⟩+g2∗∣2⟩∣g1∣2+∣g2∣2.\lvert B\rangle = \frac{ g_1^*\lvert1\rangle+g_2^*\lvert2\rangle }{ \sqrt{\lvert g_1\rvert^2+\lvert g_2\rvert^2} }.

Only ∣B⟩\lvert B\rangle is acted on by the rank-one self-energy. Its leading far-detuned shift is

δEB≃−∣g1∣2+∣g2∣2Δ.\delta E_B \simeq - \frac{ \lvert g_1\rvert^2+\lvert g_2\rvert^2 }{\Delta}.

Let δ=E−E0\delta=E-E_0 and assume ∣δ∣∥R0∥<1\lvert\delta\rvert\lVert R_0\rVert\lt1. Derive a norm bound on RQ(E)−R0R_Q(E)-R_0 and hence on the error in the frozen self-energy.

Solution

Since

RQ(E)=(I+δR0)−1R0,R_Q(E) = \left( I+\delta R_0 \right)^{-1} R_0,

the resolvent identity gives

RQ(E)−R0=−δR02(I+δR0)−1.R_Q(E)-R_0 = - \delta R_0^2 \left( I+\delta R_0 \right)^{-1}.

The Neumann-series estimate is

∥(I+δR0)−1∥≤11−∣δ∣∥R0∥.\left\lVert \left( I+\delta R_0 \right)^{-1} \right\rVert \le \frac{1}{ 1-\lvert\delta\rvert\lVert R_0\rVert }.

Therefore

∥RQ(E)−R0∥≤∣δ∣∥R0∥21−∣δ∣∥R0∥.\lVert R_Q(E)-R_0\rVert \le \frac{ \lvert\delta\rvert\lVert R_0\rVert^2 }{ 1-\lvert\delta\rvert\lVert R_0\rVert }.

Multiplying on the left and right gives

∥ΣP(E)−ΣP(E0)∥≤∥HPQ∥∥HQP∥×∣δ∣∥R0∥21−∣δ∣∥R0∥.\begin{aligned} \lVert \Sigma_P(E)-\Sigma_P(E_0) \rVert &\le \lVert H_{PQ}\rVert \lVert H_{QP}\rVert \\ &\quad\times \frac{ \lvert\delta\rvert\lVert R_0\rVert^2 }{ 1-\lvert\delta\rvert\lVert R_0\rVert }. \end{aligned}

6. Show that the scattering width is positive

Section titled “6. Show that the scattering width is positive”

Assume the spectral delta operator δ(E−HQQ)\delta(E-H_{QQ}) is positive. Show that ΓP(E)\Gamma_P(E) is positive semidefinite.

Solution

For any ∣ϕP⟩\lvert\phi_P\rangle, define

∣χQ⟩=HQP∣ϕP⟩.\lvert\chi_Q\rangle = H_{QP}\lvert\phi_P\rangle.

For compactness, also write

DQ(E)=δ(E−HQQ).D_Q(E) = \delta(E-H_{QQ}).

Then

γϕ(E)≡⟨ϕP∣ΓP(E)∣ϕP⟩,γϕ(E)=2π⟨χQ∣DQ(E)∣χQ⟩=2π∥DQ(E)1/2∣χQ⟩∥2≥0.\begin{aligned} \gamma_\phi(E) &\equiv \langle\phi_P\vert \Gamma_P(E) \vert\phi_P\rangle, \\ \gamma_\phi(E) &= 2\pi \langle\chi_Q\vert D_Q(E) \vert\chi_Q\rangle \\ &= 2\pi \left\lVert D_Q(E)^{1/2} \lvert\chi_Q\rangle \right\rVert^2 \\ &\ge0. \end{aligned}

Thus the imaginary part of the outgoing self-energy is −ΓP/2-\Gamma_P/2 with a nonnegative width. The sign encodes loss from the retained channel into outgoing eliminated channels.

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