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Exercises and Problems

This page is a problem index for Core Formalism. It collects the main skills readers should be able to perform after studying the volume and gives representative solved problems for self-checking.

The problems here are intentionally compact. Longer derivations and topic-specific exercises remain on their canonical teaching pages. Before using this page as an exam-style review, read the Dependency Graph of the Formalism and keep Common Checks and Sanity Tests nearby.

Problem groupCore skillsPreparation pages
State vectors and basis changesnormalize states, compute components, translate basesState Vectors, Change of Basis
Born rule calculationsidentify projectors, compute probabilities, handle phasesBorn Rule, Probability in Different Bases
Expectation values, variances, and covariancescompute averages, spreads, correlations, and reality checksExpectation Values, Variance and Standard Deviation, Correlations and Covariance
Commutators and uncertaintyevaluate commutators, interpret compatibility and spreadsCommutators, General Uncertainty Relations
Projective measurementsuse projectors, degeneracy, and state updateProjective Measurement, State Update Rule
Time evolutionuse Hamiltonians and unitary evolutionHamiltonians, Unitary Time Evolution
Tensor products and entanglementidentify product states, compute local predictionsTensor Products, Entangled States
Density matricescheck positivity, traces, purity, reduced statesDensity Operators, Reduced Density Matrices
Postulates and conceptual questionsidentify assumptions, scope, and interpretation boundariesMinimal Postulates, What the Postulates Do Not Say

Each representative problem states:

  • Level: undergraduate, graduate bridge, or conceptual review.
  • Skills: compact tags such as basis-change, born-rule, density-matrix, or postulates.
  • Solution status: full solution or guided solution.

When adding new problems, keep them tied to canonical pages and avoid duplicating long derivations that already live elsewhere.

Level: undergraduate
Skills: basis-change, state-vector, normalization
Solution status: full solution

Let

∣ψ⟩=∣0⟩+i∣1⟩2,∣+⟩=∣0⟩+∣1⟩2,∣−⟩=∣0⟩−∣1⟩2.\lvert\psi\rangle = \frac{\lvert0\rangle+i\lvert1\rangle}{\sqrt2}, \qquad \lvert+\rangle = \frac{\lvert0\rangle+\lvert1\rangle}{\sqrt2}, \qquad \lvert-\rangle = \frac{\lvert0\rangle-\lvert1\rangle}{\sqrt2}.

Compute the components of ∣ψ⟩\lvert\psi\rangle in the {∣+⟩,∣−⟩}\{\lvert+\rangle,\lvert-\rangle\} basis and check normalization.

Solution

The new components are inner products with the new basis:

c+=⟨+∣ψ⟩=1+i2,c−=⟨−∣ψ⟩=1−i2.c_+ = \langle+\vert\psi\rangle = \frac{1+i}{2}, \qquad c_- = \langle-\vert\psi\rangle = \frac{1-i}{2}.

Normalization is preserved:

∣c+∣2+∣c−∣2=24+24=1.\lvert c_+\rvert^2+\lvert c_-\rvert^2 = \frac{2}{4}+\frac{2}{4} = 1.

Level: undergraduate
Skills: born-rule, relative-phase, basis-change
Solution status: full solution

Let

∣ψ⟩=32∣0⟩+eiϕ2∣1⟩.\lvert\psi\rangle = \frac{\sqrt3}{2}\lvert0\rangle + \frac{e^{i\phi}}{2}\lvert1\rangle.

Find the probabilities for measuring ∣0⟩\lvert0\rangle or ∣1⟩\lvert1\rangle, and the probability for the ++ outcome in the {∣+⟩,∣−⟩}\{\lvert+\rangle,\lvert-\rangle\} basis.

Solution

In the {∣0⟩,∣1⟩}\{\lvert0\rangle,\lvert1\rangle\} basis,

p(0)=34,p(1)=14.p(0) = \frac{3}{4}, \qquad p(1) = \frac{1}{4}.

For the ++ outcome,

p(+)=∣⟨+∣ψ⟩∣2=12∣32+eiϕ2∣2.p(+) = \lvert\langle+\vert\psi\rangle\rvert^2 = \frac{1}{2} \left\lvert \frac{\sqrt3}{2} + \frac{e^{i\phi}}{2} \right\rvert^2.

Expanding the squared magnitude gives

p(+)=12+34cos⁡ϕ.p(+) = \frac{1}{2} + \frac{\sqrt3}{4}\cos\phi.

The relative phase does not affect the ∣0⟩,∣1⟩\lvert0\rangle,\lvert1\rangle probabilities, but it does affect interference in the ∣+⟩,∣−⟩\lvert+\rangle,\lvert-\rangle basis.

Level: undergraduate
Skills: expectation-value, variance, pauli-matrices
Solution status: full solution

For the same state as Problem 2, compute ⟨σz⟩\langle\sigma_z\rangle and Var⁡(σz)\operatorname{Var}(\sigma_z).

Solution

Since σz∣0⟩=∣0⟩\sigma_z\lvert0\rangle=\lvert0\rangle and σz∣1⟩=−∣1⟩\sigma_z\lvert1\rangle=-\lvert1\rangle,

⟨σz⟩=p(0)−p(1)=34−14=12.\langle\sigma_z\rangle = p(0)-p(1) = \frac{3}{4}-\frac{1}{4} = \frac{1}{2}.

Also σz2=I\sigma_z^2=I, so ⟨σz2⟩=1\langle\sigma_z^2\rangle=1. Therefore

Var⁡(σz)=⟨σz2⟩−⟨σz⟩2=1−14=34.\operatorname{Var}(\sigma_z) = \langle\sigma_z^2\rangle-\langle\sigma_z\rangle^2 = 1-\frac{1}{4} = \frac{3}{4}.

Level: undergraduate
Skills: commutator, uncertainty, operator-algebra
Solution status: full solution

Use [σx,σy]=2iσz[\sigma_x,\sigma_y]=2i\sigma_z. In the state ∣0⟩\lvert0\rangle, compute the Robertson lower bound for Δσx Δσy\Delta\sigma_x\,\Delta\sigma_y, and compare it with the actual product.

Solution

The Robertson bound gives

Δσx Δσy≥12∣⟨[σx,σy]⟩∣=12∣2i⟨σz⟩∣.\Delta\sigma_x\,\Delta\sigma_y \ge \frac{1}{2} \left\lvert \langle[\sigma_x,\sigma_y]\rangle \right\rvert = \frac{1}{2} \left\lvert 2i\langle\sigma_z\rangle \right\rvert.

In ∣0⟩\lvert0\rangle, ⟨σz⟩=1\langle\sigma_z\rangle=1, so the lower bound is 11.

Since ⟨σx⟩=⟨σy⟩=0\langle\sigma_x\rangle=\langle\sigma_y\rangle=0 and σx2=σy2=I\sigma_x^2=\sigma_y^2=I,

Δσx=1,Δσy=1.\Delta\sigma_x = 1, \qquad \Delta\sigma_y = 1.

The product is 11, so the bound is saturated.

Level: undergraduate
Skills: projectors, measurement-update, degeneracy
Solution status: full solution

Let {∣1⟩,∣2⟩,∣3⟩}\{\lvert1\rangle,\lvert2\rangle,\lvert3\rangle\} be an orthonormal basis. A measurement has outcome aa on the subspace spanned by ∣1⟩,∣2⟩\lvert1\rangle,\lvert2\rangle and outcome bb on the subspace spanned by ∣3⟩\lvert3\rangle. For

∣ψ⟩=∣1⟩+∣2⟩+2 ∣3⟩2,\lvert\psi\rangle = \frac{\lvert1\rangle+\lvert2\rangle+\sqrt2\,\lvert3\rangle}{2},

find p(a)p(a) and the selective post-measurement state after observing aa.

Solution

The projector for outcome aa is

Pa=∣1⟩⟨1∣+∣2⟩⟨2∣.P_a = \lvert1\rangle\langle1\rvert + \lvert2\rangle\langle2\rvert.

Applying it gives

Pa∣ψ⟩=∣1⟩+∣2⟩2.P_a\lvert\psi\rangle = \frac{\lvert1\rangle+\lvert2\rangle}{2}.

Thus

p(a)=⟨ψ∣Pa∣ψ⟩=12.p(a) = \langle\psi\vert P_a\vert\psi\rangle = \frac{1}{2}.

The normalized selective state is

∣ψa⟩=Pa∣ψ⟩p(a)=∣1⟩+∣2⟩2.\lvert\psi_a\rangle = \frac{P_a\lvert\psi\rangle}{\sqrt{p(a)}} = \frac{\lvert1\rangle+\lvert2\rangle}{\sqrt2}.

The relative coherence inside the degenerate outcome subspace is preserved by the ideal Lüders update.

Level: undergraduate
Skills: unitary-evolution, hamiltonian, born-rule
Solution status: full solution

Let

H=ℏω2σz,∣ψ(0)⟩=∣+⟩.H = \frac{\hbar\omega}{2}\sigma_z, \qquad \lvert\psi(0)\rangle = \lvert+\rangle.

Compute the probability of finding the system in ∣+⟩\lvert+\rangle at time tt.

Solution

The evolution operator is

U(t)=e−iHt/ℏ=e−iωtσz/2.U(t) = e^{-iHt/\hbar} = e^{-i\omega t\sigma_z/2}.

Since ∣+⟩=(∣0⟩+∣1⟩)/2\lvert+\rangle=(\lvert0\rangle+\lvert1\rangle)/\sqrt2,

∣ψ(t)⟩=e−iωt/2∣0⟩+eiωt/2∣1⟩2.\lvert\psi(t)\rangle = \frac{e^{-i\omega t/2}\lvert0\rangle + e^{i\omega t/2}\lvert1\rangle}{\sqrt2}.

The return amplitude is

⟨+∣ψ(t)⟩=e−iωt/2+eiωt/22=cos⁡ωt2.\langle+\vert\psi(t)\rangle = \frac{e^{-i\omega t/2}+e^{i\omega t/2}}{2} = \cos\frac{\omega t}{2}.

Therefore

p+(t)=cos⁡2ωt2.p_+(t) = \cos^2\frac{\omega t}{2}.

Level: undergraduate
Skills: tensor-product, product-state, entanglement
Solution status: full solution

Classify the two states:

∣ψ⟩=∣00⟩+∣01⟩2,∣Φ+⟩=∣00⟩+∣11⟩2.\lvert\psi\rangle = \frac{\lvert00\rangle+\lvert01\rangle}{\sqrt2}, \qquad \lvert\Phi^+\rangle = \frac{\lvert00\rangle+\lvert11\rangle}{\sqrt2}.

Which one factors into subsystem states?

Solution

The first state factors:

∣ψ⟩=∣0⟩⊗∣0⟩+∣1⟩2=∣0⟩⊗∣+⟩.\lvert\psi\rangle = \lvert0\rangle \otimes \frac{\lvert0\rangle+\lvert1\rangle}{\sqrt2} = \lvert0\rangle\otimes\lvert+\rangle.

It is a product state. The Bell state ∣Φ+⟩\lvert\Phi^+\rangle does not factor into a state of AA times a state of BB; it has Schmidt rank 22 and is entangled.

Level: undergraduate
Skills: density-matrix, positivity, purity
Solution status: full solution

For real rr, consider

ρ(r)=12(1rr1).\rho(r) = \frac{1}{2} \begin{pmatrix} 1 & r \\ r & 1 \end{pmatrix}.

For which values of rr is this a valid density matrix? When is it pure?

Solution

The matrix is Hermitian and has trace one for every real rr. Its eigenvectors are the ∣+⟩\lvert+\rangle and ∣−⟩\lvert-\rangle states, with eigenvalues

λ±=1±r2.\lambda_\pm = \frac{1\pm r}{2}.

Positivity requires both eigenvalues to be nonnegative, so

−1≤r≤1.-1 \le r \le 1.

The state is pure when one eigenvalue is 11 and the other is 00, which occurs at r=1r=1 or r=−1r=-1. Equivalently, Tr⁡ρ2=1\operatorname{Tr}\rho^2=1 only for ∣r∣=1\lvert r\rvert=1.

Level: conceptual review
Skills: postulates, measurement-context, scope
Solution status: full solution

Someone writes: “The state ∣ψ⟩\lvert\psi\rangle tells us what value an observable already has before measurement.” Identify what is wrong and replace the sentence with a formalism-safe version.

Solution

The statement treats the state as assigning pre-existing sharp values to all observables. The standard formalism instead uses the state together with a specified measurement to assign probabilities.

A safer version is:

Given a state and a specified measurement, the Born rule assigns probabilities to possible outcomes. If the state is an eigenstate of the measured observable, one outcome can be sharp; otherwise the formalism generally gives a probability distribution.

This answer separates the state, the observable or measurement, and the probability rule. It also avoids adding an interpretation that is not part of the minimal postulates.

For a balanced Core Formalism review, choose:

  1. one state-normalization or basis-change problem;
  2. one Born-rule problem in a non-measurement basis;
  3. one expectation-value and variance problem;
  4. one commutator or uncertainty problem;
  5. one projective-measurement update problem;
  6. one unitary time-evolution problem;
  7. one tensor-product or entanglement problem;
  8. one density-operator or partial-trace problem;
  9. one conceptual postulates question.

After solving, run the Common Checks and Sanity Tests on every answer. If an answer fails a check, use Common Mistakes in the Formalism to diagnose the likely failure mode.

  • R. Shankar, Principles of Quantum Mechanics, 2nd ed., Springer, 1994.
  • J. J. Sakurai and J. Napolitano, Modern Quantum Mechanics, 3rd ed., Cambridge University Press, 2020.
  • D. J. Griffiths and D. F. Schroeter, Introduction to Quantum Mechanics, 3rd ed., Cambridge University Press, 2018.
  • A. Peres, Quantum Theory: Concepts and Methods, Kluwer, 1995.