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Pauli Exclusion Principle

The Pauli exclusion principle says that no two identical fermions can occupy the same complete one-particle quantum state.

The word complete matters. For an electron, a one-particle state includes spin as well as spatial quantum numbers. Two electrons may occupy the same spatial orbital only if their spin states differ so that the total two-electron state remains antisymmetric. In occupation-number language, each fermionic mode has occupation

ni=0orni=1.n_i=0\quad\text{or}\quad n_i=1.

Pauli exclusion is not an extra force between fermions. It is a direct consequence of the antisymmetry required by the symmetrization postulate.

In operator language, the same content is carried by fermionic anticommutation relations, especially (ci†)2=0(c_i^\dagger)^2=0.

Let h\mathcal h be the one-particle Hilbert space for a species of identical fermions. If ∣α⟩∈h\lvert\alpha\rangle\in\mathcal h is a normalized one-particle state, then the two-fermion state with both slots assigned to ∣α⟩\lvert\alpha\rangle is zero:

∣α,α⟩A=0.\lvert\alpha,\alpha\rangle_A=0.

Equivalently, an antisymmetric NN-fermion state vanishes whenever two fermions are assigned the same complete one-particle state.

For electrons in atoms, the “complete one-particle state” is often called a spin-orbital: a spatial orbital together with a spin state. Two electrons can share a spatial orbital only because spin provides two different spin-orbitals.

For two identical fermions in orthonormal one-particle states ∣α⟩\lvert\alpha\rangle and ∣β⟩\lvert\beta\rangle, the antisymmetric state is

∣α,β⟩A=12(∣α⟩1∣β⟩2−∣β⟩1∣α⟩2).\lvert\alpha,\beta\rangle_A = \frac{1}{\sqrt2} \bigl( \lvert\alpha\rangle_1\lvert\beta\rangle_2 - \lvert\beta\rangle_1\lvert\alpha\rangle_2 \bigr).

If the two one-particle states are the same, set ∣β⟩=∣α⟩\lvert\beta\rangle=\lvert\alpha\rangle. Then

∣α,α⟩A=12(∣α⟩1∣α⟩2−∣α⟩1∣α⟩2)=0.\lvert\alpha,\alpha\rangle_A = \frac{1}{\sqrt2} \bigl( \lvert\alpha\rangle_1\lvert\alpha\rangle_2 - \lvert\alpha\rangle_1\lvert\alpha\rangle_2 \bigr) = 0.

There is no normalized two-fermion state of this form. The state is not forbidden because it has high energy; it is absent from the fermionic Hilbert space.

Choose a one-particle basis {∣i⟩}\{\lvert i\rangle\} for h\mathcal h. A two-slot state may be expanded as

∣Ψ⟩=∑ijCij∣i⟩1∣j⟩2.\lvert\Psi\rangle = \sum_{ij} C_{ij} \lvert i\rangle_1\lvert j\rangle_2.

Fermionic antisymmetry requires

Cij=−Cji.C_{ij}=-C_{ji}.

Setting i=ji=j gives

Cii=−Cii,C_{ii}=-C_{ii},

so

Cii=0.C_{ii}=0.

Thus the amplitude for both fermions occupying the same basis state vanishes. This is the exclusion principle in coefficient form.

For NN fermions occupying one-particle orbitals φ1,…,φN\varphi_1,\ldots,\varphi_N, the antisymmetric wavefunction can be written as a determinant:

Ψ(q1,…,qN)=1N!det⁡(φ1(q1)⋯φN(q1)⋮⋱⋮φ1(qN)⋯φN(qN)).\Psi(q_1,\ldots,q_N) = \frac{1}{\sqrt{N!}} \det \begin{pmatrix} \varphi_1(q_1) & \cdots & \varphi_N(q_1)\\ \vdots & \ddots & \vdots\\ \varphi_1(q_N) & \cdots & \varphi_N(q_N) \end{pmatrix}.

Here q=(x,s)q=(\mathbf x,s) includes spatial and spin variables. Exchanging two particles exchanges two rows, so the determinant changes sign. If two occupied one-particle orbitals are the same, two columns are identical and the determinant is zero.

This determinant form is the basis of Slater determinants in quantum chemistry and many-electron physics. The detailed determinant technology belongs there; the essential exclusion logic is already visible here.

In a central-potential approximation, an electron state is labeled by quantum numbers such as

n,ℓ,mℓ,ms.n,\quad \ell,\quad m_\ell,\quad m_s.

For a fixed spatial orbital specified by n,ℓ,mℓn,\ell,m_\ell, an electron has two possible spin projections:

ms=12,ms=−12.m_s=\frac12, \qquad m_s=-\frac12.

Therefore a single spatial orbital can hold at most two electrons, one in each spin state. A subshell with orbital angular momentum ℓ\ell has 2ℓ+12\ell+1 values of mℓm_\ell, so its electron capacity is

2(2ℓ+1).2(2\ell+1).

In the ideal hydrogenic counting, a shell with principal quantum number nn has total capacity

2n2.2n^2.

Real atoms require electron-electron interactions, spin-orbit effects, screening, and many-body approximations, but the exclusion principle is the structural reason electrons fill shells rather than all collapsing into the same one-particle state.

The helium ground state gives the first useful example. Both electrons occupy the same spatial 1s1s orbital in a simple approximation, but they have opposite spin projections and combine into an antisymmetric spin singlet. The spatial part is symmetric, the spin part is antisymmetric, and the total electronic state is antisymmetric.

Pauli Principle in Atoms develops the atomic consequences in full, including equivalent-electron term restrictions, closed-subshell structure, particle–hole counting, and the qualified connection to periodicity.

Pauli exclusion is a major ingredient in the stability and bulk structure of ordinary matter. Since electrons are fermions, many electrons cannot all occupy the same low-energy one-particle state. Filling many distinct states forces a kinetic-energy cost that grows with density.

This effect is often called degeneracy pressure in many-body settings. It is not a classical pressure caused by collisions. It is the energy cost of antisymmetric fermionic state filling. In atoms, molecules, solids, white dwarfs, and neutron-rich matter, this filling structure combines with Coulomb forces, gravity, interactions, and boundary conditions.

The exclusion principle alone is not a complete proof of matter stability. Rigorous stability results also use kinetic-energy estimates, electrostatic inequalities, and the detailed form of the Hamiltonian. Still, without fermionic antisymmetry, ordinary matter would have a radically different structure.

A free spin-1/21/2 Fermi gas illustrates exclusion in momentum space. Put particles in a box and label one-particle states by momentum and spin. At zero temperature, the lowest-energy many-fermion state fills momentum modes up to a Fermi momentum kFk_F. The Degenerate Fermi Gas page develops the resulting thermal shell, Pauli-blocked final states, pressure, and low-temperature heat capacity.

In three dimensions, with spin degeneracy gg, the number density is

n=g kF36π2.n = \frac{g\,k_F^3}{6\pi^2}.

The corresponding Fermi energy for nonrelativistic particles of mass mm is

EF=ℏ2kF22m.E_F = \frac{\hbar^2 k_F^2}{2m}.

This simple model is the entry point to electron gases in metals, neutron matter, and many condensed-matter estimates. The full many-body theory is much richer, but the first step is just one fermion per mode.

  • Pauli exclusion does not say two fermions can never be at the same position.
  • Pauli exclusion does not apply to bosons.
  • “Same state” means the same complete one-particle state, including spin and other internal labels.
  • The exclusion principle is not a repulsive potential inserted into the Hamiltonian.
  • Opposite-spin electrons in the same spatial orbital do not violate exclusion because their spin-orbitals differ.
  • Pauli exclusion is not the same topic as Pauli matrices, despite the shared name.
  • W. Pauli, “On the Connection Between the Completion of Electron Groups in the Atom and the Complex Structure of Spectra,” Zeitschrift fur Physik 31, 765-783, 1925.
  • P. A. M. Dirac, The Principles of Quantum Mechanics, 4th ed., Oxford University Press, 1958.
  • A. Messiah and O. W. Greenberg, “Symmetrization Postulate and Its Experimental Foundation,” Physical Review 136, B248-B267, 1964.
  • J. J. Sakurai and J. Napolitano, Modern Quantum Mechanics, 3rd ed., Cambridge University Press, 2020.
  • A. L. Fetter and J. D. Walecka, Quantum Theory of Many-Particle Systems, McGraw-Hill, 1971.
  • E. H. Lieb and R. Seiringer, The Stability of Matter in Quantum Mechanics, Cambridge University Press, 2010.
  1. Show directly that two identical fermions cannot both occupy the same one-particle state ∣α⟩\lvert\alpha\rangle.
Solution

The antisymmetric two-fermion construction gives

12(∣α⟩1∣α⟩2−∣α⟩1∣α⟩2)=0.\frac{1}{\sqrt2} \bigl( \lvert\alpha\rangle_1\lvert\alpha\rangle_2 - \lvert\alpha\rangle_1\lvert\alpha\rangle_2 \bigr) = 0.

The zero vector is not a physical state, so two identical fermions cannot occupy the same complete one-particle state.

  1. Why can the two electrons in the helium ground-state approximation share a spatial 1s1s orbital?
Solution

They do not occupy the same complete one-particle state. The spatial orbital is the same, but the spin states differ. In the usual ground-state approximation, the spatial wavefunction is symmetric and the spin state is the antisymmetric singlet, making the total electronic state antisymmetric as required for fermions.

  1. How many electrons can fit in a pp subshell in the central-potential counting?
Solution

A pp subshell has ℓ=1\ell=1, so mℓ=−1,0,1m_\ell=-1,0,1: three spatial orbital states. Each can be paired with two spin projections. The capacity is therefore

2(2ℓ+1)=2(3)=6.2(2\ell+1) = 2(3) = 6.
  1. A spin-1/21/2 Fermi gas has spin degeneracy g=2g=2. Express kFk_F in terms of the number density nn.
Solution

Use

n=g kF36π2.n = \frac{g\,k_F^3}{6\pi^2}.

With g=2g=2,

n=kF33π2.n = \frac{k_F^3}{3\pi^2}.

Therefore

kF=(3π2n)1/3.k_F = (3\pi^2 n)^{1/3}.