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Renyi Entropies

Renyi entropies are a one-parameter family of entropy measures built from powers of a density operator. For a density operator ρ\rho and a parameter α>0\alpha>0 with α≠1\alpha\ne1,

Sα(ρ)=11−αlog⁡Tr⁡(ρα).S_\alpha(\rho) = \frac{1}{1-\alpha} \log \operatorname{Tr}(\rho^\alpha).

The limit α→1\alpha\to1 gives the von Neumann entropy,

lim⁡α→1Sα(ρ)=S(ρ)=−Tr⁡(ρlog⁡ρ).\lim_{\alpha\to1}S_\alpha(\rho) = S(\rho) = -\operatorname{Tr}(\rho\log\rho).

For a pure bipartite state, applying SαS_\alpha to a reduced state gives a family of pure-state entanglement measures:

Sα(A)=Sα(ρA),ρA=Tr⁡B∣Ψ⟩⟨Ψ∣.S_\alpha(A) = S_\alpha(\rho_A), \qquad \rho_A=\operatorname{Tr}_B\lvert\Psi\rangle\langle\Psi\rvert.

Renyi entropies are especially useful because S2S_2 is determined by the purity Tr⁡(ρ2)\operatorname{Tr}(\rho^2), integer orders connect to replica methods, and different values of α\alpha probe different parts of the eigenvalue spectrum.

Let ρ\rho have spectral decomposition

ρ=∑kpk∣k⟩⟨k∣,pk≥0,∑kpk=1.\rho = \sum_k p_k \lvert k\rangle\langle k\rvert, \qquad p_k\ge0, \qquad \sum_k p_k=1.

Then

Tr⁡(ρα)=∑kpkα,\operatorname{Tr}(\rho^\alpha) = \sum_k p_k^\alpha,

so

Sα(ρ)=11−αlog⁡(∑kpkα).S_\alpha(\rho) = \frac{1}{1-\alpha} \log \left( \sum_k p_k^\alpha \right).

The logarithm base fixes the units. Base 22 gives bits; natural logarithms give nats. This page states finite-dimensional examples in bits when numerical values are given.

Renyi entropy depends only on the eigenvalues of ρ\rho. It is invariant under unitary conjugation:

Sα(UρU†)=Sα(ρ).S_\alpha(U\rho U^\dagger) = S_\alpha(\rho).

For a pure state, all Renyi entropies vanish:

Sα(∣ψ⟩⟨ψ∣)=0.S_\alpha(\lvert\psi\rangle\langle\psi\rvert)=0.

For a maximally mixed state ρ∗=I/d\rho_\ast=I/d,

Sα(ρ∗)=log⁡dS_\alpha(\rho_\ast) = \log d

for every α>0\alpha>0.

Let a normalized bipartite pure state have Schmidt decomposition

∣Ψ⟩=∑rsr∣ur⟩A∣vr⟩B.\lvert\Psi\rangle = \sum_r s_r \lvert u_r\rangle_A \lvert v_r\rangle_B.

Define Schmidt probabilities

pr=sr2.p_r=s_r^2.

The reduced density operator on AA has nonzero eigenvalues prp_r, so

Sα(A)=11−αlog⁡(∑rprα).S_\alpha(A) = \frac{1}{1-\alpha} \log \left( \sum_r p_r^\alpha \right).

The same value is obtained from ρB\rho_B:

Sα(A)=Sα(B)S_\alpha(A)=S_\alpha(B)

for pure bipartite states. Thus Renyi entropies form a family of pure-state entanglement measures across the chosen split.

The case α→1\alpha\to1 is the usual Entanglement Entropy:

S1(A)=−∑rprlog⁡pr.S_1(A) = -\sum_r p_r\log p_r.

The case α→0\alpha\to0 gives the logarithm of the Schmidt Rank:

S0(A)=log⁡SR⁡(Ψ),S_0(A) = \log \operatorname{SR}(\Psi),

provided the support is finite-dimensional.

Starting from

Sα(ρ)=log⁡f(α)1−α,f(α)=Tr⁡(ρα)=∑kpkα,S_\alpha(\rho) = \frac{\log f(\alpha)}{1-\alpha}, \qquad f(\alpha) = \operatorname{Tr}(\rho^\alpha) = \sum_k p_k^\alpha,

we have f(1)=1f(1)=1. The limit α→1\alpha\to1 has the indeterminate form 0/00/0. Differentiating numerator and denominator gives

lim⁡α→1log⁡f(α)1−α=−f′(1)f(1).\lim_{\alpha\to1} \frac{\log f(\alpha)}{1-\alpha} = - \frac{f'(1)}{f(1)}.

Since

f′(α)=∑kpkαlog⁡pk,f'(\alpha) = \sum_k p_k^\alpha\log p_k,

the limit is

lim⁡α→1Sα(ρ)=−∑kpklog⁡pk=S(ρ).\lim_{\alpha\to1}S_\alpha(\rho) = - \sum_k p_k\log p_k = S(\rho).

This is why von Neumann entropy is often denoted S1S_1 in contexts where Renyi entropies are being discussed.

The second Renyi entropy is

S2(ρ)=−log⁡Tr⁡(ρ2).S_2(\rho) = -\log \operatorname{Tr}(\rho^2).

The quantity

Tr⁡(ρ2)\operatorname{Tr}(\rho^2)

is the purity. It equals 11 for pure states and is less than 11 for mixed states.

For a bipartite pure state, S2(ρA)S_2(\rho_A) is a simple entanglement measure. In terms of Schmidt probabilities,

S2(A)=−log⁡(∑rpr2).S_2(A) = -\log \left( \sum_r p_r^2 \right).

For a Bell state, p1=p2=1/2p_1=p_2=1/2, so

S2(A)=−log⁡2(14+14)=1S_2(A) = -\log_2 \left( \frac14+\frac14 \right) = 1

bit.

For

∣Ψθ⟩=cos⁡θ ∣00⟩+sin⁡θ ∣11⟩,\lvert\Psi_\theta\rangle = \cos\theta\,\lvert00\rangle + \sin\theta\,\lvert11\rangle,

the second Renyi entropy in bits is

S2(A)=−log⁡2(cos⁡4θ+sin⁡4θ).S_2(A) = -\log_2 \bigl( \cos^4\theta+\sin^4\theta \bigr).

It vanishes at product endpoints and reaches one bit at θ=π/4\theta=\pi/4.

The order α=0\alpha=0 is the rank entropy:

S0(ρ)=log⁡rank⁡ρ,S_0(\rho) = \log \operatorname{rank}\rho,

where the rank is the number of nonzero eigenvalues. It is sensitive to arbitrarily small nonzero eigenvalues, so it is mathematically clean but not robust under small perturbations.

The limit α→∞\alpha\to\infty gives the min-entropy:

S∞(ρ)=−log⁡pmax⁡,S_\infty(\rho) = -\log p_{\max},

where pmax⁡p_{\max} is the largest eigenvalue of ρ\rho.

For a fixed density operator, Renyi entropies are nonincreasing as α\alpha increases:

α<β⟹Sα(ρ)≥Sβ(ρ).\alpha<\beta \quad \Longrightarrow \quad S_\alpha(\rho)\ge S_\beta(\rho).

Small α\alpha gives more weight to the number of populated eigenvalues. Large α\alpha emphasizes the largest eigenvalues.

Renyi entropies appear often in many-body physics, quantum information, and quantum simulation.

In numerical work, S2S_2 is useful because it only requires Tr⁡(ρ2)\operatorname{Tr}(\rho^2). This is simpler than reconstructing the entire eigenvalue spectrum of ρ\rho when the Hilbert space is large.

In tensor-network and many-body settings, Renyi entropies summarize how entanglement is distributed across a spatial or site bipartition. They can diagnose area-law behavior, critical scaling, and finite-size trends. The interpretation depends on the physical split and on whether the total state is pure.

For spatial Rényi entropies, critical scaling, finite-size diagnostics, and numerical uses, see Entanglement Entropy in Many-Body Systems.

In experimental settings, purity and second Renyi entropy can sometimes be estimated from two-copy interference, randomized measurements, or statistical correlations across repeated preparations. The experimental protocol is not part of this page; the composite-systems point is that powers Tr⁡(ρα)\operatorname{Tr}(\rho^\alpha) can be more directly accessible than the full density matrix in some settings.

For an integer n>1n>1,

Sn(ρA)=11−nlog⁡Tr⁡(ρAn).S_n(\rho_A) = \frac{1}{1-n} \log \operatorname{Tr}(\rho_A^n).

The quantity Tr⁡(ρAn)\operatorname{Tr}(\rho_A^n) can sometimes be computed by considering nn copies of the system. In statistical mechanics and QFT, this idea leads to replica methods: compute for integer nn, then analytically continue and take the limit n→1n\to1 to obtain von Neumann entropy.

This is only a preview. In QFT, entanglement entropies of spatial regions can depend on regulators, boundary geometry, and continuum limits. The finite-dimensional Renyi formulas here are the conceptual entry point; Entanglement in QFT Preview explains the wider field-theory setting.

For a mixed joint state ρAB\rho_{AB}, the Renyi entropy of ρA\rho_A measures local mixedness, not entanglement by itself. The same warning that applies to von Neumann subsystem entropy applies to every Sα(ρA)S_\alpha(\rho_A).

For example,

ρcc=12∣00⟩⟨00∣+12∣11⟩⟨11∣\rho_{\mathrm{cc}} = \frac12 \lvert00\rangle\langle00\rvert + \frac12 \lvert11\rangle\langle11\rvert

has ρA=I/2\rho_A=I/2, so every Renyi entropy of AA is one bit. The state is separable. Its local entropy reflects classical correlation with BB, not pure-state entanglement.

By contrast, for a Bell pure state, the same one-qubit reduced state I/2I/2 arises from entanglement with the other qubit. The joint-state context determines the interpretation.

  • Forgetting that α=1\alpha=1 is a limit, not a direct substitution into the formula with 1−α1-\alpha in the denominator.
  • Confusing S2(ρ)S_2(\rho) with the square of S(ρ)S(\rho).
  • Treating Sα(ρA)S_\alpha(\rho_A) as a mixed-state entanglement measure without knowing that ρAB\rho_{AB} is pure.
  • Comparing numerical values without stating the logarithm base.
  • Assuming full Schmidt rank implies large Renyi entropy for every order.
  • Ignoring zero eigenvalues when discussing S0S_0.
  • Assuming the replica trick is automatic in continuum QFT; analytic continuation and regularization are separate issues.
  • A. Renyi, “On Measures of Entropy and Information,” in Proceedings of the Fourth Berkeley Symposium on Mathematical Statistics and Probability, Vol. 1, 547-561, University of California Press, 1961.
  • A. Wehrl, “General Properties of Entropy,” Reviews of Modern Physics 50, 221-260, 1978.
  • M. A. Nielsen and I. L. Chuang, Quantum Computation and Quantum Information, Cambridge University Press, 2010.
  • P. Calabrese and J. Cardy, “Entanglement Entropy and Quantum Field Theory,” Journal of Statistical Mechanics P06002, 2004.
  • J. Eisert, M. Cramer, and M. B. Plenio, “Area Laws for the Entanglement Entropy,” Reviews of Modern Physics 82, 277-306, 2010.
  • M. M. Wilde, Quantum Information Theory, 2nd ed., Cambridge University Press, 2017.
  • J. Watrous, The Theory of Quantum Information, Cambridge University Press, 2018.
  1. Compute SαS_\alpha for a pure state.
Solution

A pure state has eigenvalues 1,0,0,…1,0,0,\ldots. Therefore

Tr⁡(ρα)=1α=1,\operatorname{Tr}(\rho^\alpha) = 1^\alpha = 1,

so

Sα(ρ)=11−αlog⁡1=0.S_\alpha(\rho) = \frac{1}{1-\alpha}\log1 = 0.
  1. Compute SαS_\alpha for the maximally mixed state I/dI/d.
Solution

The eigenvalues are all 1/d1/d. Hence

Tr⁡(ρα)=d(1d)α=d1−α.\operatorname{Tr}(\rho^\alpha) = d\left(\frac1d\right)^\alpha = d^{1-\alpha}.

Thus

Sα(ρ)=11−αlog⁡d1−α=log⁡d.S_\alpha(\rho) = \frac{1}{1-\alpha}\log d^{1-\alpha} = \log d.
  1. Compute the second Renyi entropy in bits for a Bell state reduction.
Solution

For a Bell state, ρA=I/2\rho_A=I/2. Thus

Tr⁡(ρA2)=Tr⁡(14I)=12.\operatorname{Tr}(\rho_A^2) = \operatorname{Tr}\left(\frac14 I\right) = \frac12.

Therefore

S2(ρA)=−log⁡212=1S_2(\rho_A) = -\log_2\frac12 = 1

bit.

  1. Show that the limit α→1\alpha\to1 gives the von Neumann entropy for eigenvalues pkp_k.
Solution

Let

f(α)=∑kpkα.f(\alpha)=\sum_k p_k^\alpha.

Then f(1)=1f(1)=1, and

Sα=log⁡f(α)1−α.S_\alpha = \frac{\log f(\alpha)}{1-\alpha}.

Using L’Hospital’s rule,

lim⁡α→1Sα=−f′(1)=−∑kpklog⁡pk.\lim_{\alpha\to1}S_\alpha = - f'(1) = - \sum_k p_k\log p_k.
  1. For Schmidt probabilities p,1−pp,1-p, write S2S_2 in bits.
Solution

The second Renyi entropy is

S2=−log⁡2(p2+(1−p)2).S_2 = -\log_2 \bigl( p^2+(1-p)^2 \bigr).

It is zero at p=0p=0 and p=1p=1, and equals one bit at p=1/2p=1/2.