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Energy Scales in One Dimension

Energy scales are the fastest way to understand a one-dimensional quantum problem before solving it. They tell you whether confinement is strong, whether a bound state should be shallow or deep, how long a forbidden-region tail should be, and which parameters actually control the spectrum.

The central rule is simple:

A length scale LL implies a kinetic-energy scale ℏ2/(2mL2)\hbar^2/(2mL^2).

Most one-dimensional estimates are refinements of that statement.

SituationNatural scaleMeaning
Confinement over length LLEL=ℏ2/(2mL2)E_L=\hbar^2/(2mL^2)Kinetic cost of localization
Infinite well of width LLE1=π2ℏ2/(2mL2)E_1=\pi^2\hbar^2/(2mL^2)Exact ground-state confinement energy
Finite well of half-width aa and depth V0V_0z0=a2mV0/ℏz_0=a\sqrt{2mV_0}/\hbarDimensionless depth-width parameter
Attractive delta well −αδ(x)-\alpha\delta(x)Eδ=−mα2/(2ℏ2)E_\delta=-m\alpha^2/(2\hbar^2)Zero-range binding energy
Forbidden region V>EV\gt Eℓtail=ℏ/2m(V−E)\ell_{\text{tail}}=\hbar/\sqrt{2m(V-E)}Evanescent decay length
Harmonic minimumEosc=ℏωE_{\mathrm{osc}}=\hbar\omegaLevel-spacing scale near a stable minimum
Smooth tunneling barrierΔE∝e−S/ℏ\Delta E\propto e^{-S/\hbar}Splitting or transmission controlled by action

The numerical constants differ from model to model. The scaling with mm, length, depth, and ℏ\hbar is the durable part.

A wavefunction localized over length LL must contain momenta of order

Δp∼ℏL.\Delta p\sim\frac{\hbar}{L}.

The corresponding kinetic energy is

EL∼(Δp)22m∼ℏ22mL2.E_L \sim \frac{(\Delta p)^2}{2m} \sim \frac{\hbar^2}{2mL^2}.

This estimate becomes exact up to a numerical factor in the infinite square well:

E1=π2ℏ22mL2.E_1 = \frac{\pi^2\hbar^2}{2mL^2}.

The 1/L21/L^2 dependence is why squeezing a one-dimensional bound state rapidly raises its energy. Doubling the length lowers this scale by a factor of four.

For the symmetric finite square well

V(x)={−V0,∣x∣<a,0,∣x∣≥a,V(x)= \begin{cases} -V_0, & \lvert x\rvert\lt a,\\ 0, & \lvert x\rvert\ge a, \end{cases}

the natural kinetic scale associated with the half-width aa is

Ea=ℏ22ma2.E_a=\frac{\hbar^2}{2ma^2}.

The dimensionless well strength is

V0Ea=2ma2V0ℏ2=z02,\frac{V_0}{E_a} = \frac{2ma^2V_0}{\hbar^2} =z_0^2,

where

z0=a2mV0ℏ.z_0=a\frac{\sqrt{2mV_0}}{\hbar}.

Large z0z_0 means many oscillations can fit inside the attractive region before the continuum threshold. The approximate number of bound states is controlled by

N∼2z0π.N\sim\frac{2z_0}{\pi}.

The exact count still requires threshold care, as explained in Bound-State Counting.

The attractive delta potential

V(x)=−αδ(x),α>0,V(x)=-\alpha\delta(x), \qquad \alpha\gt0,

has a coupling α\alpha with units of energy times length. The only length that can be built from mm, α\alpha, and ℏ\hbar is

ℓδ=ℏ2mα.\ell_\delta = \frac{\hbar^2}{m\alpha}.

The exact bound-state wavefunction decays on this length:

ψ(x)∝e−∣x∣/ℓδ.\psi(x)\propto e^{-\lvert x\rvert/\ell_\delta}.

The binding energy is

Eδ=−mα22ℏ2.E_\delta = -\frac{m\alpha^2}{2\hbar^2}.

Thus a stronger zero-range attraction makes the state smaller and more deeply bound. Unlike a fixed-width well, the delta problem has no separate geometric length; the interaction strength creates the length scale.

In a region where the potential is locally constant and larger than the energy,

V>E,V\gt E,

the stationary Schrödinger equation gives exponential behavior. Define

κ=2m(V−E)ℏ.\kappa = \frac{\sqrt{2m(V-E)}}{\hbar}.

The tail length is

ℓtail=1κ=ℏ2m(V−E).\ell_{\text{tail}} = \frac{1}{\kappa} = \frac{\hbar}{\sqrt{2m(V-E)}}.

This formula appears in finite wells, rectangular barriers, tunneling estimates, and near-threshold bound states. Larger mass, higher barrier excess V−EV-E, or smaller ℏ\hbar make the tail shorter. As EE approaches the threshold from below, κ→0\kappa\to0 and the tail becomes long.

Near a stable minimum x0x_0, a smooth potential has the expansion

V(x)≈V(x0)+12V′′(x0)(x−x0)2.V(x) \approx V(x_0) +\frac12V''(x_0)(x-x_0)^2.

Identify

mω2=V′′(x0).m\omega^2=V''(x_0).

The natural energy scale for small oscillations is

Eosc=ℏω,E_{\mathrm{osc}}=\hbar\omega,

and the natural length is

ℓosc=ℏmω.\ell_{\mathrm{osc}} = \sqrt{\frac{\hbar}{m\omega}}.

Low-lying states in a smooth well often resemble oscillator states near the minimum:

En≈V(x0)+ℏω(n+12).E_n \approx V(x_0) +\hbar\omega \left( n+\frac12 \right).

This approximation is local. It fails for highly excited states that explore anharmonic parts of the well or approach a finite barrier top.

Tunneling introduces an energy scale that can be much smaller than the local level spacing. In a symmetric double well, each well may have a local oscillator scale ℏω0\hbar\omega_0, but the splitting between the even and odd combinations can be exponentially small:

ΔE∼Ae−S/ℏ.\Delta E \sim A e^{-S/\hbar}.

Here SS is a barrier action of the rough form

S∼∫x1x22m(V(x)−E) dx,S \sim \int_{x_1}^{x_2} \sqrt{2m(V(x)-E)}\,dx,

over the classically forbidden region. The prefactor AA is model dependent, but the exponential sensitivity is the key scale lesson. Small changes in barrier width, height, or mass can produce large changes in tunneling splittings.

Detailed WKB prefactors belong to the semiclassical volume. In this chapter, the main use is diagnostic: tunneling splittings are often far smaller than ordinary confinement or oscillator spacings.

Mass appears in nearly every one-dimensional scale:

EL∝1m,ℓtail∝1m,Eδ∝m,ℓosc∝1mE_L\propto\frac{1}{m}, \qquad \ell_{\text{tail}}\propto\frac{1}{\sqrt m}, \qquad E_\delta\propto m, \qquad \ell_{\mathrm{osc}}\propto\frac{1}{\sqrt m}

when the external potential parameters are held fixed.

This mix of dependencies is not contradictory. The length and strength being held fixed matter. A heavier particle has a lower confinement kinetic energy for a fixed box, a shorter evanescent tail for a fixed barrier excess, and a deeper delta binding energy for a fixed integrated attraction.

Before solving a one-dimensional model:

  1. Identify the relevant length: box width, well half-width, oscillator length, decay length, or barrier width.
  2. Form the kinetic scale ℏ2/(2mL2)\hbar^2/(2mL^2).
  3. Compare potential depths or barriers to that kinetic scale.
  4. Convert the comparison into a dimensionless parameter such as z0z_0.
  5. Estimate the number of states, tail lengths, or splitting sizes.
  6. Only then solve the exact matching equations or numerical eigenvalue problem.

This workflow catches many wrong answers. A computed state with a tail much longer than the numerical box, or an energy spacing wildly inconsistent with ℏ2/(2mL2)\hbar^2/(2mL^2), deserves suspicion.

  • Comparing two energies without checking that they are measured from the same zero.
  • Forgetting the square on LL in the confinement scale.
  • Treating the finite-well depth V0V_0 alone as the state-counting parameter; width and mass matter too.
  • Applying the harmonic scale to states far from the minimum.
  • Ignoring a long near-threshold tail in a finite numerical box.
  • Treating an exponentially small tunneling splitting as comparable to the local oscillator spacing.
  • Dropping ℏ\hbar or mm during dimensional estimates and then restoring them inconsistently.
  • D. J. Griffiths and D. F. Schroeter, Introduction to Quantum Mechanics, 3rd ed., Cambridge University Press, 2018.
  • R. Shankar, Principles of Quantum Mechanics, 2nd ed., Springer, 1994.
  • C. Cohen-Tannoudji, B. Diu, and F. Laloë, Quantum Mechanics, Wiley, 1977.
  • L. D. Landau and E. M. Lifshitz, Quantum Mechanics: Non-Relativistic Theory, 3rd ed., Pergamon, 1977.
  1. A box length is doubled while the mass is fixed. How does the confinement scale change?
Solution

The confinement scale is

EL=ℏ22mL2.E_L=\frac{\hbar^2}{2mL^2}.

Replacing LL by 2L2L gives

E2L=ℏ22m(2L)2=EL4.E_{2L} = \frac{\hbar^2}{2m(2L)^2} = \frac{E_L}{4}.

The scale decreases by a factor of four.

  1. Use dimensional reasoning to construct the delta-well length scale from mm, α\alpha, and ℏ\hbar.
Solution

For V(x)=−αδ(x)V(x)=-\alpha\delta(x), the strength α\alpha has units of energy times length. The combination

ℓδ=ℏ2mα\ell_\delta = \frac{\hbar^2}{m\alpha}

has units of length. The exact solution confirms that this is the decay length:

ψ(x)∝e−∣x∣/ℓδ.\psi(x)\propto e^{-\lvert x\rvert/\ell_\delta}.
  1. A forbidden region has constant V−E=U>0V-E=U\gt0. Find the decay length.
Solution

The decay constant is

κ=2mUℏ.\kappa = \frac{\sqrt{2mU}}{\hbar}.

Therefore

ℓtail=1κ=ℏ2mU.\ell_{\text{tail}} = \frac{1}{\kappa} = \frac{\hbar}{\sqrt{2mU}}.
  1. Near a smooth minimum, V′′(x0)=KV''(x_0)=K. What oscillator frequency and energy scale should be used?
Solution

Compare

V(x)≈V(x0)+12K(x−x0)2V(x)\approx V(x_0)+\frac12K(x-x_0)^2

with the oscillator form

12mω2(x−x0)2.\frac12m\omega^2(x-x_0)^2.

Thus

ω=Km.\omega=\sqrt{\frac{K}{m}}.

The corresponding level-spacing scale is

ℏω=ℏKm.\hbar\omega = \hbar\sqrt{\frac{K}{m}}.