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Ladder Operators

Ladder operators convert the angular momentum algebra into a practical way of constructing multiplets. They raise or lower the mm label while leaving jj fixed.

Define

J+=Jx+iJy,J−=Jx−iJy.J_+=J_x+iJ_y, \qquad J_-=J_x-iJ_y.

The ladder operators obey

[Jz,J±]=±ℏJ±,[J_z,J_\pm]=\pm\hbar J_\pm,

and

[J2,J±]=0.[J^2,J_\pm]=0.

The first relation says J±J_\pm changes the JzJ_z eigenvalue. The second says it does not change the J2J^2 eigenvalue.

If

Jz∣j,m⟩=ℏm∣j,m⟩,J_z\lvert j,m\rangle = \hbar m\lvert j,m\rangle,

then

Jz(J±∣j,m⟩)=ℏ(m±1)(J±∣j,m⟩).J_z(J_\pm\lvert j,m\rangle) = \hbar(m\pm1)(J_\pm\lvert j,m\rangle).

Thus J+J_+ raises mm by one and J−J_- lowers mm by one.

With normalized states and the standard Condon–Shortley convention,

J±∣j,m⟩=ℏj(j+1)−m(m±1)∣j,m±1⟩.J_\pm\lvert j,m\rangle = \hbar \sqrt{j(j+1)-m(m\pm1)} \lvert j,m\pm1\rangle.

The coefficient vanishes at the top or bottom of the multiplet:

J+∣j,j⟩=0,J−∣j,−j⟩=0.J_+\lvert j,j\rangle=0, \qquad J_-\lvert j,-j\rangle=0.

Use

J−J+=J2−Jz2−ℏJz.J_-J_+ = J^2-J_z^2-\hbar J_z.

Then

∥J+∣j,m⟩∥2=⟨j,m∣J−J+∣j,m⟩.\lVert J_+\lvert j,m\rangle\rVert^2 = \langle j,m|J_-J_+|j,m\rangle.

Substituting the eigenvalues gives

∥J+∣j,m⟩∥2=ℏ2[j(j+1)−m(m+1)].\lVert J_+\lvert j,m\rangle\rVert^2 = \hbar^2\left[j(j+1)-m(m+1)\right].

The square root gives the raising coefficient. The lowering coefficient follows similarly.

Repeated raising and lowering must eventually stop because norms cannot become negative. This algebraic termination gives a finite chain

m=−j,−j+1,…,j.m=-j,-j+1,\ldots,j.

The number of states is 2j+12j+1. Orbital angular momentum has integer ℓ\ell; spin allows half-integer jj as well.

For j=1/2j=1/2, the multiplet has

m=−12,12.m=-\frac12,\frac12.

There are two states.

For j=1j=1, the multiplet has

m=−1,0,1.m=-1,0,1.

There are three states.

  • Applying J+J_+ above m=jm=j or J−J_- below m=−jm=-j.
  • Forgetting the factor of ℏ\hbar in the ladder action.
  • Reversing the sign in J±=Jx±iJyJ_\pm=J_x\pm iJ_y.
  • Assuming ladder operators change jj; they change mm inside a fixed-jj multiplet.
  • Mixing phase conventions when comparing coefficients from different references.
  • A. R. Edmonds, Angular Momentum in Quantum Mechanics, Princeton University Press, 1957.
  • J. J. Sakurai and J. Napolitano, Modern Quantum Mechanics, 3rd ed., Cambridge University Press, 2020.
  • R. Shankar, Principles of Quantum Mechanics, 2nd ed., Springer, 1994.
  1. Compute J+∣1,0⟩J_+\lvert 1,0\rangle.
Solution

Use

J+∣j,m⟩=ℏj(j+1)−m(m+1)∣j,m+1⟩.J_+\lvert j,m\rangle = \hbar\sqrt{j(j+1)-m(m+1)}\lvert j,m+1\rangle.

For j=1,m=0j=1,m=0, the coefficient is ℏ2\hbar\sqrt{2}, so

J+∣1,0⟩=ℏ2 ∣1,1⟩.J_+\lvert 1,0\rangle = \hbar\sqrt2\,\lvert1,1\rangle.
  1. Why does J+∣j,j⟩=0J_+\lvert j,j\rangle=0?
Solution

The coefficient is

ℏj(j+1)−j(j+1)=0.\hbar\sqrt{j(j+1)-j(j+1)}=0.

There is no allowed state with m=j+1m=j+1 in the fixed-jj multiplet.