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Clebsch–Gordan Quick Reference

This page is a quick reference for using Clebsch–Gordan coefficients without losing signs, labels, or basis conventions. It is meant for table lookup and calculation hygiene. The canonical explanation is Clebsch–Gordan Coefficients, the table-reading guide is Clebsch–Gordan Tables and Conventions, and the low-spin table is Clebsch–Gordan Coefficients.

The uncoupled basis is

∣j1,m1⟩∣j2,m2⟩,\lvert j_1,m_1\rangle \lvert j_2,m_2\rangle,

and the coupled basis is

∣j1,j2;J,M⟩.\lvert j_1,j_2;J,M\rangle.

The Clebsch–Gordan coefficient is the overlap

Cj1m1,j2m2JM≡⟨j1,m1;j2,m2∣J,M⟩.C^{JM}_{j_1m_1,j_2m_2} \equiv \langle j_1,m_1;j_2,m_2\vert J,M\rangle.

The coupled state expands as

∣j1,j2;J,M⟩=∑m1,m2Cj1m1,j2m2JM∣j1,m1⟩∣j2,m2⟩.\lvert j_1,j_2;J,M\rangle = \sum_{m_1,m_2} C^{JM}_{j_1m_1,j_2m_2} \lvert j_1,m_1\rangle \lvert j_2,m_2\rangle.

This volume uses the Condon–Shortley phase convention unless a page explicitly states otherwise. With real coefficients in this convention, signs are fixed by the ladder-operator convention and the chosen highest-weight phases.

For two angular momenta j1j_1 and j2j_2,

J=∣j1−j2∣,∣j1−j2∣+1,…,j1+j2.J = \lvert j_1-j_2\rvert, \lvert j_1-j_2\rvert+1, \ldots, j_1+j_2.

For each allowed JJ,

M=−J,−J+1,…,J.M=-J,-J+1,\ldots,J.

The magnetic quantum number rule is

M=m1+m2.M=m_1+m_2.

If this rule fails, the coefficient is zero. The dimension check is

(2j1+1)(2j2+1)=∑J=∣j1−j2∣j1+j2(2J+1).(2j_1+1)(2j_2+1) = \sum_{J=\lvert j_1-j_2\rvert}^{j_1+j_2} (2J+1).

Use this check to catch missing total-JJ sectors before consulting a table.

For fixed j1j_1 and j2j_2, the Clebsch–Gordan coefficients form a unitary change of basis:

∑m1,m2(Cj1m1,j2m2JM)∗Cj1m1,j2m2J′M′=δJJ′δMM′.\sum_{m_1,m_2} \left( C^{JM}_{j_1m_1,j_2m_2} \right)^* C^{J'M'}_{j_1m_1,j_2m_2} = \delta_{JJ'}\delta_{MM'}.

Completeness in the uncoupled basis gives

∑J,MCj1m1,j2m2JM(Cj1m1′,j2m2′JM)∗=δm1m1′δm2m2′.\sum_{J,M} C^{JM}_{j_1m_1,j_2m_2} \left( C^{JM}_{j_1m'_1,j_2m'_2} \right)^* = \delta_{m_1m'_1}\delta_{m_2m'_2}.

The inverse expansion is

∣j1,m1⟩∣j2,m2⟩=∑J,M⟨J,M∣j1,m1;j2,m2⟩∣j1,j2;J,M⟩.\lvert j_1,m_1\rangle \lvert j_2,m_2\rangle = \sum_{J,M} \langle J,M\vert j_1,m_1;j_2,m_2\rangle \lvert j_1,j_2;J,M\rangle.

For real coefficients, the inverse uses the same numerical coefficients after matching labels. In a complex convention, use complex conjugates.

Before using a coefficient table, check these items in order:

  1. Identify whether the table lists Clebsch–Gordan coefficients or Wigner 3j3j symbols.
  2. Verify the phase convention, usually Condon–Shortley in physics tables.
  3. Check the order of j1j_1 and j2j_2.
  4. Apply the zero tests M=m1+m2M=m_1+m_2 and ∣j1−j2∣≤J≤j1+j2\lvert j_1-j_2\rvert\leq J\leq j_1+j_2.
  5. Check normalization by summing the squared coefficients for a fixed coupled state.

The table home is Clebsch–Gordan Coefficients. For a compact formula card, use Addition of Angular Momentum.

For two spin-1/21/2 systems,

12⊗12=1⊕0.\frac12\otimes\frac12 = 1\oplus0.

In the standard convention,

∣1,0⟩=12(∣↑↓⟩+∣↓↑⟩),\lvert 1,0\rangle = \frac{1}{\sqrt2} \left( \lvert\uparrow\downarrow\rangle + \lvert\downarrow\uparrow\rangle \right),

while

∣0,0⟩=12(∣↑↓⟩−∣↓↑⟩).\lvert 0,0\rangle = \frac{1}{\sqrt2} \left( \lvert\uparrow\downarrow\rangle - \lvert\downarrow\uparrow\rangle \right).

The relative sign distinguishes the triplet state from the singlet state. The physical interpretation is developed in Singlet and Triplet States.

For j1=1j_1=1 and j2=1/2j_2=1/2,

1⊗12=32⊕12.1\otimes\frac12 = \frac32\oplus\frac12.

The M=3/2M=3/2 state has only one product-basis component:

∣32,32⟩=∣1,1⟩∣12,12⟩.\left\lvert \frac32,\frac32 \right\rangle = \lvert1,1\rangle \left\lvert\frac12,\frac12\right\rangle.

Lowering this state and normalizing generates the J=3/2J=3/2 multiplet; orthogonality then fixes the J=1/2J=1/2 states up to the convention-fixed signs.

Clebsch–Gordan coefficients and Wigner 3j3j symbols contain the same coupling information. With the convention used here,

⟨j1,m1;j2,m2∣J,M⟩=(−1)j1−j2+M2J+1(j1j2Jm1m2−M).\langle j_1,m_1;j_2,m_2\vert J,M\rangle = (-1)^{j_1-j_2+M} \sqrt{2J+1} \begin{pmatrix} j_1&j_2&J\\ m_1&m_2&-M \end{pmatrix}.

The 3j3j symbol is often better for identities and symmetry relations. The Clebsch–Gordan coefficient is often better for changing basis between uncoupled and coupled states. Do not use a 3j3j table as a Clebsch–Gordan table without the phase and normalization factor.

For two angular momenta, the main ordering issue is whether the table uses j1,j2j_1,j_2 or j2,j1j_2,j_1. For three or more angular momenta, one must also specify which pair is coupled first.

For example,

∣(j1j2)j12,j3;JM⟩\left| (j_1j_2)j_{12},j_3;JM \right\rangle

and

∣j1,(j2j3)j23;JM⟩\left| j_1,(j_2j_3)j_{23};JM \right\rangle

are different coupled bases. Their change of basis involves Wigner 6j6j symbols, not merely a Clebsch–Gordan table. Use Recoupling and Wigner Symbols when the problem has more than two angular momenta.

TaskBest starting page
Understand coupled versus uncoupled basesCoupled and Uncoupled Bases
Learn what the coefficients meanClebsch–Gordan Coefficients
Resolve table and phase conventionsClebsch–Gordan Tables and Conventions
Look up low-spin coefficientsClebsch–Gordan Coefficients Table
Check allowed JJ values and MM rulesAddition of Angular Momentum
Interpret the singlet and tripletSinglet and Triplet States
Convert to Wigner 3j3j notationWigner Symbols
Change coupling order for three angular momentaRecoupling and Wigner Symbols
  • Forgetting that Clebsch–Gordan coefficients are basis-change amplitudes, not energy-level data.
  • Using a coefficient even though M≠m1+m2M\ne m_1+m_2.
  • Comparing signs from tables with different phase conventions.
  • Swapping j1j_1 and j2j_2 without checking the table convention.
  • Treating 3j3j symbols and Clebsch–Gordan coefficients as identical.
  • Omitting multiplicity or intermediate-coupling labels in problems with more than two angular momenta.
  • A. R. Edmonds, Angular Momentum in Quantum Mechanics, Princeton University Press, 1957.
  • D. A. Varshalovich, A. N. Moskalev, and V. K. Khersonskii, Quantum Theory of Angular Momentum, World Scientific, 1988.
  • D. M. Brink and G. R. Satchler, Angular Momentum, 3rd ed., Oxford University Press, 1993.
  • J. J. Sakurai and J. Napolitano, Modern Quantum Mechanics, 3rd ed., Cambridge University Press, 2020.
  • R. N. Zare, Angular Momentum: Understanding Spatial Aspects in Chemistry and Physics, Wiley, 1988.
  1. Which total angular momenta appear in 2⊗12\otimes1?
Solution

The allowed total angular momenta run from

∣2−1∣=1\lvert2-1\rvert=1

to

2+1=32+1=3

in integer steps. Therefore

2⊗1=3⊕2⊕1.2\otimes1=3\oplus2\oplus1.
  1. Can ⟨1,1;1,−1∣1,1⟩\langle1,1;1,-1\vert1,1\rangle be nonzero?
Solution

The magnetic quantum number rule requires

M=m1+m2.M=m_1+m_2.

Here m1=1m_1=1 and m2=−1m_2=-1, so m1+m2=0m_1+m_2=0, while the coupled state has M=1M=1. The coefficient is therefore zero.

  1. Why is a 3j3j table not automatically a Clebsch–Gordan table?
Solution

The two notations differ by a phase and a normalization factor:

⟨j1,m1;j2,m2∣J,M⟩=(−1)j1−j2+M2J+1(j1j2Jm1m2−M).\langle j_1,m_1;j_2,m_2\vert J,M\rangle = (-1)^{j_1-j_2+M} \sqrt{2J+1} \begin{pmatrix} j_1&j_2&J\\ m_1&m_2&-M \end{pmatrix}.

Using a 3j3j value directly as a Clebsch–Gordan coefficient generally gives the wrong sign or magnitude.