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Heisenberg Equations of Motion

The Heisenberg equation of motion gives the time derivative of an operator in the Heisenberg picture:

dAHdt=iℏ[HH,AH]+(∂A∂t)H.\frac{dA_H}{dt} = \frac{i}{\hbar}[H_H,A_H] + \left(\frac{\partial A}{\partial t}\right)_H.

It is the operator analogue of Hamiltonian time evolution. The dynamics-side discussion of commutators as generators is Commutator Dynamics.

The Core expectation-value consequence, including the conservation-law test, is Conservation Laws. For a practical symmetry-oriented checklist, see Constants of Motion.

For an operator with no explicit time dependence,

AH(t)=U†(t,t0)ASU(t,t0).A_H(t)=U^\dagger(t,t_0)A_SU(t,t_0).

Using

iℏ∂U∂t=HU,i\hbar\frac{\partial U}{\partial t}=HU,

and its adjoint, differentiation gives

dAHdt=iℏHHAH−iℏAHHH=iℏ[HH,AH].\frac{dA_H}{dt} = \frac{i}{\hbar}H_HA_H - \frac{i}{\hbar}A_HH_H = \frac{i}{\hbar}[H_H,A_H].

If ASA_S has explicit time dependence, the extra term (∂A/∂t)H\left(\partial A/\partial t\right)_H must be included.

For

H=p22m,H=\frac{p^2}{2m},

the canonical commutator gives

dxHdt=pHm,dpHdt=0.\frac{dx_H}{dt} =\frac{p_H}{m}, \qquad \frac{dp_H}{dt}=0.

Thus

xH(t)=xH(0)+pH(0)mt.x_H(t)=x_H(0)+\frac{p_H(0)}{m}t.

For

H=p22m+V(x),H=\frac{p^2}{2m}+V(x),

one obtains

dxHdt=pHm,dpHdt=−V′(xH).\frac{dx_H}{dt}=\frac{p_H}{m}, \qquad \frac{dp_H}{dt}=-V'(x_H).

These are operator equations. Their expectation values lead to Ehrenfest theorem.

For

H=ℏω(a†a+12),H=\hbar\omega\left(a^\dagger a+\frac12\right),

the ladder operator obeys

daHdt=−iωaH,\frac{da_H}{dt}=-i\omega a_H,

so

aH(t)=aH(0)e−iωt.a_H(t)=a_H(0)e^{-i\omega t}.

For a spin in a constant magnetic field, the Hamiltonian is proportional to B⋅S\mathbf B\cdot\mathbf S. The Heisenberg equation gives spin precession: the spin operator rotates around the magnetic-field direction.

The spin-specific derivation is Larmor Precession.

  • Forgetting the explicit time-derivative term.
  • Reversing the commutator sign.
  • Treating operator equations as ordinary commuting equations.
  • Assuming Heisenberg equations automatically solve the whole classical-limit problem.
  • Dropping domain and boundary-condition issues for unbounded operators.
  • R. Shankar, Principles of Quantum Mechanics, 2nd ed., Springer, 1994.
  • J. J. Sakurai and J. Napolitano, Modern Quantum Mechanics, 3rd ed., Cambridge University Press, 2020.
  • D. J. Griffiths and D. F. Schroeter, Introduction to Quantum Mechanics, 3rd ed., Cambridge University Press, 2018.
  1. Use [x,p]=iℏ[x,p]=i\hbar to derive dxH/dt=pH/mdx_H/dt=p_H/m for the free particle.
Solution

For H=p2/(2m)H=p^2/(2m),

dxHdt=iℏ[H,xH]=i2mℏ[pH2,xH].\frac{dx_H}{dt} =\frac{i}{\hbar}[H,x_H] =\frac{i}{2m\hbar}[p_H^2,x_H].

Using [p2,x]=p[p,x]+[p,x]p=−2iℏp[p^2,x]=p[p,x]+[p,x]p=-2i\hbar p gives

dxHdt=i2mℏ(−2iℏpH)=pHm.\frac{dx_H}{dt} =\frac{i}{2m\hbar}(-2i\hbar p_H) =\frac{p_H}{m}.