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Amplitude Damping Master Equation

The amplitude damping master equation is the standard Markovian equation for irreversible relaxation from an excited state to a lower state. It is the generator behind spontaneous emission, zero-temperature qubit T1T_1 decay, cavity photon loss, and many quantum-jump models.

For a two-level system with excited state ∣e⟩\lvert e\rangle and ground state ∣g⟩\lvert g\rangle,

σ−=∣g⟩⟨e∣,σ+=∣e⟩⟨g∣.\sigma_-=\lvert g\rangle\langle e\rvert, \qquad \sigma_+=\lvert e\rangle\langle g\rvert.

The zero-temperature amplitude damping master equation is

dρdt=−iℏ[H,ρ]+Γ1D[σ−]ρ,\frac{d\rho}{dt} = - \frac{i}{\hbar}[H,\rho] + \Gamma_1\mathcal D[\sigma_-]\rho,

where

D[L]ρ=LρL†−12{L†L,ρ}.\mathcal D[L]\rho = L\rho L^\dagger - \frac12\{L^\dagger L,\rho\}.

Here Γ1\Gamma_1 is the population-relaxation rate. The finite-time channel generated by this equation is the Amplitude-Damping Channel with decay probability p(t)=1−e−Γ1tp(t)=1-e^{-\Gamma_1t}.

For a notebook contract that validates this master equation by comparing ODE integration, matrix exponentials, and finite-time channel checks, see Solving Lindblad Equations.

Amplitude damping is energy relaxation into degrees of freedom that are not retained in the system description. For an atom, those degrees of freedom may be emitted radiation modes. For a superconducting qubit, they may be electromagnetic, dielectric, quasiparticle, or engineered reservoir modes. For a cavity oscillator, the dissipative operator is usually aa, corresponding to loss of one quantum.

The word “amplitude” comes from the fact that a probability amplitude involving the excited state decays at half the population-relaxation rate. In density-matrix language, this is the relation between T1T_1 relaxation and transverse coherence decay.

Take

H=ℏω0∣e⟩⟨e∣H = \hbar\omega_0 \lvert e\rangle\langle e\rvert

or equivalently the same Hamiltonian up to an irrelevant multiple of the identity. In the interaction picture with respect to HH, the dissipative equation gives

ρ˙ee=−Γ1ρee,ρ˙gg=Γ1ρee,ρ˙eg=−Γ12ρeg,ρ˙ge=−Γ12ρge.\begin{aligned} \dot\rho_{ee}&=-\Gamma_1\rho_{ee},\\ \dot\rho_{gg}&=\Gamma_1\rho_{ee},\\ \dot\rho_{eg}&=-\frac{\Gamma_1}{2}\rho_{eg},\\ \dot\rho_{ge}&=-\frac{\Gamma_1}{2}\rho_{ge}. \end{aligned}

Thus

ρee(t)=e−Γ1tρee(0),\rho_{ee}(t) = e^{-\Gamma_1t}\rho_{ee}(0),

and

ρeg(t)=e−Γ1t/2ρeg(0)\rho_{eg}(t) = e^{-\Gamma_1t/2}\rho_{eg}(0)

apart from Hamiltonian phase rotation. The ground-state population increases by the lost excited-state population:

ρgg(t)=1−ρee(t)\rho_{gg}(t) = 1-\rho_{ee}(t)

for a normalized two-level state.

If

H=ℏω0∣e⟩⟨e∣,H = \hbar\omega_0 \lvert e\rangle\langle e\rvert,

then the Schrödinger-picture coherence obeys

ρ˙eg=−(iω0+Γ12)ρeg.\dot\rho_{eg} = - \left( i\omega_0+\frac{\Gamma_1}{2} \right) \rho_{eg}.

Hence

ρeg(t)=e−iω0te−Γ1t/2ρeg(0)\rho_{eg}(t) = e^{-i\omega_0t} e^{-\Gamma_1t/2} \rho_{eg}(0)

when no additional dephasing is present. If a pure-dephasing term with rate Γϕ\Gamma_\phi is also present, the transverse decay rate becomes

1T2=Γ12+Γϕ.\frac{1}{T_2} = \frac{\Gamma_1}{2} + \Gamma_\phi.

See Pure Dephasing Master Equation for the separate generator that changes coherence without changing populations.

For the broader T1T_1, T2T_2, and protocol-dependent coherence-time bookkeeping, see Decoherence Timescales.

Adding a near-resonant coherent drive to this same two-level relaxation model gives the Optical Bloch Equations.

Let the ground state ∣g⟩\lvert g\rangle be the north pole, so

ρ=12(I+rxσx+ryσy+rzσz),\rho = \frac12 \left( I+r_x\sigma_x+r_y\sigma_y+r_z\sigma_z \right),

with rz=+1r_z=+1 for ∣g⟩\lvert g\rangle and rz=−1r_z=-1 for ∣e⟩\lvert e\rangle. In the interaction picture,

r˙x=−Γ12rx,r˙y=−Γ12ry,r˙z=Γ1(1−rz).\begin{aligned} \dot r_x&=-\frac{\Gamma_1}{2}r_x,\\ \dot r_y&=-\frac{\Gamma_1}{2}r_y,\\ \dot r_z&=\Gamma_1(1-r_z). \end{aligned}

The fixed point is the ground state. The transverse components contract, while the longitudinal component relaxes toward +1+1.

This affine flow is the continuous-time version of the nonunital Bloch-ball map on the Amplitude-Damping Channel. It is not a Pauli channel and not depolarizing noise.

Solving the master equation gives a completely positive trace-preserving map. With

p(t)=1−e−Γ1t,p(t)=1-e^{-\Gamma_1t},

the Kraus operators may be chosen as

K0(t)=∣g⟩⟨g∣+1−p(t) ∣e⟩⟨e∣,K_0(t) = \lvert g\rangle\langle g\rvert + \sqrt{1-p(t)}\, \lvert e\rangle\langle e\rvert,

and

K1(t)=p(t) ∣g⟩⟨e∣.K_1(t) = \sqrt{p(t)}\, \lvert g\rangle\langle e\rvert.

This finite-time channel is useful for quantum information noise models, while the master equation is useful when composing with Hamiltonian dynamics, drives, other Lindblad terms, and time-dependent control.

If the emitted quantum is monitored by an ideal photon counter, the jump operator is

J=Γ1 σ−.J=\sqrt{\Gamma_1}\,\sigma_-.

During a short interval dtdt, the probability of observing a jump is

pjump=dt Tr⁡(J†Jρ)=Γ1dt ρee.p_{\mathrm{jump}} = dt\, \operatorname{Tr}(J^\dagger J\rho) = \Gamma_1dt\,\rho_{ee}.

After a detected jump, the state updates to

ρ⟼σ−ρσ+Tr⁡(σ+σ−ρ).\rho \longmapsto \frac{ \sigma_-\rho\sigma_+ }{ \operatorname{Tr}(\sigma_+\sigma_-\rho) }.

If no jump is detected, the unnormalized conditional state evolves under the effective Hamiltonian

Heff=H−iℏΓ12σ+σ−.H_{\mathrm{eff}} = H - \frac{i\hbar\Gamma_1}{2} \sigma_+\sigma_-.

The no-jump evolution is not the same as closed Hamiltonian evolution; absence of a click is itself information. Averaging the jump and no-jump conditioned updates recovers the unconditional amplitude damping master equation.

At nonzero temperature, the bath may also excite the system. The two-level finite-temperature equation is

dρdt=−iℏ[H,ρ]+Γ↓D[σ−]ρ+Γ↑D[σ+]ρ.\frac{d\rho}{dt} = - \frac{i}{\hbar}[H,\rho] + \Gamma_\downarrow\mathcal D[\sigma_-]\rho + \Gamma_\uparrow\mathcal D[\sigma_+]\rho.

The excited-state population obeys

ρ˙ee=−Γ↓ρee+Γ↑ρgg.\dot\rho_{ee} = - \Gamma_\downarrow\rho_{ee} + \Gamma_\uparrow\rho_{gg}.

The population relaxation time is

T1=1Γ↓+Γ↑.T_1 = \frac{1} {\Gamma_\downarrow+\Gamma_\uparrow}.

The steady excited-state population is

ρeess=Γ↑Γ↑+Γ↓.\rho_{ee}^{\mathrm{ss}} = \frac{\Gamma_\uparrow} {\Gamma_\uparrow+\Gamma_\downarrow}.

For a single thermal bath at inverse temperature β\beta and transition frequency ω0>0\omega_0>0, Detailed Balance gives

Γ↑Γ↓=e−βℏω0.\frac{\Gamma_\uparrow}{\Gamma_\downarrow} = e^{-\beta\hbar\omega_0}.

The zero-temperature amplitude damping equation is the limit Γ↑→0\Gamma_\uparrow\to0.

For a cavity or oscillator mode at zero temperature, amplitude damping is

dρdt=−iℏ[ℏωa†a,ρ]+κD[a]ρ.\frac{d\rho}{dt} = - \frac{i}{\hbar} [\hbar\omega a^\dagger a,\rho] + \kappa\mathcal D[a]\rho.

The mean occupation obeys

ddt⟨a†a⟩=−κ⟨a†a⟩,\frac{d}{dt} \langle a^\dagger a\rangle = - \kappa \langle a^\dagger a\rangle,

while the field amplitude obeys

ddt⟨a⟩=−(iω+κ2)⟨a⟩.\frac{d}{dt}\langle a\rangle = - \left( i\omega+\frac{\kappa}{2} \right) \langle a\rangle.

Thus energy decays at rate κ\kappa, while field amplitude decays at rate κ/2\kappa/2. Confusing these two rates is a common linewidth-convention error.

At finite temperature, add the thermal excitation term κnˉD[a†]ρ\kappa\bar n\mathcal D[a^\dagger]\rho as described in Thermal Master Equations and Quantum Optical Master Equation.

In a weak-coupling derivation, amplitude damping comes from a transverse system–bath coupling with matrix elements between different energy eigenstates. A schematic interaction is

HI=A⊗B,H_I = A\otimes B,

where AA has components such as

A(ω0)∝σ−,A(−ω0)∝σ+.A(\omega_0) \propto \sigma_-, \qquad A(-\omega_0) \propto \sigma_+.

After Born, Markov, and secular approximations, the bath spectrum at the transition frequency gives the downward rate, and the bath spectrum at the negative transition frequency gives the upward rate.

At zero temperature for an ordinary passive bath, the upward rate vanishes. In structured reservoirs, strong coupling, non-Markovian environments, or driven frames, this simple separation can fail or need modification.

Before using an amplitude damping master equation, check:

  • Which state is excited and which state is lower?
  • Is the bath effectively at zero temperature, or are upward transitions needed?
  • Is the transition frequency inside a smooth reservoir spectrum?
  • Are the Born, Markov, and secular approximations justified?
  • Is the system Hamiltonian written in the basis used by σ−\sigma_-?
  • Are additional pure-dephasing terms separated from T1T_1 decay?
  • Is leakage outside the modeled Hilbert space important?
  • Are reported linewidths energy-decay rates, amplitude-decay rates, or full widths?

If the environment is monitored, also specify the detection scheme. The same unconditional master equation can correspond to different trajectory descriptions depending on how the environment is measured.

Treating amplitude damping as pure dephasing

Section titled “Treating amplitude damping as pure dephasing”

Amplitude damping changes populations. Pure dephasing does not. Both can reduce coherence, but they represent different physical processes and different Lindblad operators.

Zero-temperature T1T_1 decay with rate Γ1\Gamma_1 gives transverse coherence decay Γ1/2\Gamma_1/2 before additional pure dephasing. The square root in the finite-time channel is the same fact.

Using zero-temperature damping at finite temperature

Section titled “Using zero-temperature damping at finite temperature”

If Γ↑\Gamma_\uparrow is appreciable, the zero-temperature equation predicts the wrong steady state. Use upward and downward rates satisfying the appropriate thermal or nonequilibrium relation.

Amplitude damping maps the excited state into a lower state inside the modeled Hilbert space. Leakage into a state outside the computational subspace requires a larger Hilbert space or a leakage channel.

Conditioned no-jump evolution changes the state because the absence of an event updates the observer’s information. The unconditional equation is recovered only after averaging over all records.

For ρ˙=Γ1D[σ−]ρ\dot\rho=\Gamma_1\mathcal D[\sigma_-]\rho, derive ρ˙ee=−Γ1ρee\dot\rho_{ee}=-\Gamma_1\rho_{ee}.

Solution

Use σ+σ−=∣e⟩⟨e∣\sigma_+\sigma_-=\lvert e\rangle\langle e\rvert and σ−ρσ+=ρee∣g⟩⟨g∣\sigma_-\rho\sigma_+=\rho_{ee}\lvert g\rangle\langle g\rvert. The positive term has no excited-state component:

⟨e∣σ−ρσ+∣e⟩=0.\langle e|\sigma_-\rho\sigma_+|e\rangle=0.

The anticommutator gives

⟨e∣12{σ+σ−,ρ}∣e⟩=ρee.\left\langle e\left| \frac12\{\sigma_+\sigma_-,\rho\} \right|e\right\rangle = \rho_{ee}.

Therefore

ρ˙ee=−Γ1ρee.\dot\rho_{ee} = -\Gamma_1\rho_{ee}.

For the same equation, show that ρ˙eg=−(Γ1/2)ρeg\dot\rho_{eg}=-(\Gamma_1/2)\rho_{eg} in the interaction picture.

Solution

The positive term σ−ρσ+\sigma_-\rho\sigma_+ is proportional to ∣g⟩⟨g∣\lvert g\rangle\langle g\rvert, so it has no egeg matrix element. The anticommutator gives

({σ+σ−,ρ})eg=ρeg.\left( \{\sigma_+\sigma_-,\rho\} \right)_{eg} = \rho_{eg}.

Thus

ρ˙eg=−Γ12ρeg.\dot\rho_{eg} = - \frac{\Gamma_1}{2} \rho_{eg}.

Solve ρ˙ee=−Γ1ρee\dot\rho_{ee}=-\Gamma_1\rho_{ee} and identify the finite-time decay probability p(t)p(t) in the amplitude-damping channel.

Solution

The population solution is

ρee(t)=e−Γ1tρee(0).\rho_{ee}(t) = e^{-\Gamma_1t}\rho_{ee}(0).

The probability that an initially excited population has decayed by time tt is therefore

p(t)=1−e−Γ1t.p(t) = 1-e^{-\Gamma_1t}.

For finite-temperature rates, solve for the steady excited-state population of

ρ˙ee=−Γ↓ρee+Γ↑(1−ρee).\dot\rho_{ee} = - \Gamma_\downarrow\rho_{ee} + \Gamma_\uparrow(1-\rho_{ee}).
Solution

Set the derivative to zero:

0=−Γ↓ρeess+Γ↑(1−ρeess).0 = - \Gamma_\downarrow\rho_{ee}^{\mathrm{ss}} + \Gamma_\uparrow \left( 1-\rho_{ee}^{\mathrm{ss}} \right).

Rearranging gives

(Γ↓+Γ↑)ρeess=Γ↑.(\Gamma_\downarrow+\Gamma_\uparrow) \rho_{ee}^{\mathrm{ss}} = \Gamma_\uparrow.

Thus

ρeess=Γ↑Γ↓+Γ↑.\rho_{ee}^{\mathrm{ss}} = \frac{\Gamma_\uparrow} {\Gamma_\downarrow+\Gamma_\uparrow}.

For ρ˙=κD[a]ρ\dot\rho=\kappa\mathcal D[a]\rho, use the adjoint dissipator to show that ⟨a⟩\langle a\rangle decays at rate κ/2\kappa/2.

Solution

The adjoint dissipator is

D†[a]O=a†Oa−12{a†a,O}.\mathcal D^\dagger[a]O = a^\dagger Oa - \frac12\{a^\dagger a,O\}.

For O=aO=a, use [a†a,a]=−a[a^\dagger a,a]=-a to obtain

D†[a]a=−12a.\mathcal D^\dagger[a]a = - \frac12 a.

Therefore

ddt⟨a⟩=κ⟨D†[a]a⟩=−κ2⟨a⟩\frac{d}{dt}\langle a\rangle = \kappa \langle \mathcal D^\dagger[a]a\rangle = - \frac{\kappa}{2} \langle a\rangle

in the interaction picture.

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