The Pauli matrices, together with the identity, form an orthogonal basis for
all complex 2 × 2 2\times2 2 × 2 matrices. Their multiplication table compresses much
of two-dimensional matrix algebra into ordinary dot and cross products in
three coordinates.
This page develops that matrix calculus. The interpretation
S i = ℏ σ i / 2 S_i=\hbar\sigma_i/2 S i = ℏ σ i /2 as spin components belongs to
Pauli Matrices in Symmetry, Angular Momentum, and Spin ,
while qubit-state geometry belongs to
Bloch Sphere Geometry .
Set σ 0 = I 2 \sigma_0=I_2 σ 0 = I 2 . The three Pauli matrices are
σ x = ( 0 1 1 0 ) , σ y = ( 0 − i i 0 ) , σ z = ( 1 0 0 − 1 ) . \begin{aligned}
\sigma_x
&=
\begin{pmatrix}
0&1\\
1&0
\end{pmatrix},\\[6pt]
\sigma_y
&=
\begin{pmatrix}
0&-i\\
i&0
\end{pmatrix},\\[6pt]
\sigma_z
&=
\begin{pmatrix}
1&0\\
0&-1
\end{pmatrix}.
\end{aligned} σ x σ y σ z = ( 0 1 1 0 ) , = ( 0 i − i 0 ) , = ( 1 0 0 − 1 ) .
Each σ i \sigma_i σ i is Hermitian and unitary:
σ i † = σ i , σ i 2 = I . \sigma_i^\dagger=\sigma_i,
\qquad
\sigma_i^2=I. σ i † = σ i , σ i 2 = I .
It follows that
tr σ i = 0 , det σ i = − 1 , σ i − 1 = σ i . \operatorname{tr}\sigma_i=0,
\qquad
\det\sigma_i=-1,
\qquad
\sigma_i^{-1}=\sigma_i. tr σ i = 0 , det σ i = − 1 , σ i − 1 = σ i .
The eigenvalues are + 1 +1 + 1 and − 1 -1 − 1 . Thus each Pauli matrix is both an
involution and a reflection-like unitary, not a positive operator.
For i , j , k ∈ { x , y , z } i,j,k\in\{x,y,z\} i , j , k ∈ { x , y , z } ,
σ i σ j = δ i j I + i ∑ k ϵ i j k σ k . \sigma_i\sigma_j
=\delta_{ij}I
+i\sum_k\epsilon_{ijk}\sigma_k. σ i σ j = δ ij I + i k ∑ ϵ ij k σ k .
For equal indices this gives σ i 2 = I \sigma_i^2=I σ i 2 = I . For distinct indices it encodes
the cyclic products
σ x σ y = i σ z , σ y σ z = i σ x , σ z σ x = i σ y , \begin{aligned}
\sigma_x\sigma_y
&=i\sigma_z,\\
\sigma_y\sigma_z
&=i\sigma_x,\\
\sigma_z\sigma_x
&=i\sigma_y,
\end{aligned} σ x σ y σ y σ z σ z σ x = i σ z , = i σ x , = i σ y ,
and reversing an order changes the sign. For example,
σ y σ x = − i σ z . \sigma_y\sigma_x=-i\sigma_z. σ y σ x = − i σ z .
The factor of i i i is essential. It allows the product of two noncommuting
Hermitian matrices to be non-Hermitian.
Taking the antisymmetric and symmetric parts of the multiplication rule gives
[ σ i , σ j ] = 2 i ∑ k ϵ i j k σ k , { σ i , σ j } = 2 δ i j I . \begin{aligned}
[\sigma_i,\sigma_j]
&=2i\sum_k\epsilon_{ijk}\sigma_k,\\
\{\sigma_i,\sigma_j\}
&=2\delta_{ij}I.
\end{aligned} [ σ i , σ j ] { σ i , σ j } = 2 i k ∑ ϵ ij k σ k , = 2 δ ij I .
The commutator closes on the three-dimensional span of the Pauli matrices.
The anticommutator collapses to the identity. These are the defining
relations behind the fundamental representation of the Lie algebra
s u ( 2 ) \mathfrak{su}(2) su ( 2 ) and an irreducible representation of the
three-generator complex Clifford relations.
Normalization conventions differ by factors of two. The matrices
T i = σ i 2 T_i=\frac{\sigma_i}{2} T i = 2 σ i
satisfy
[ T i , T j ] = i ∑ k ϵ i j k T k . [T_i,T_j]
=i\sum_k\epsilon_{ijk}T_k. [ T i , T j ] = i k ∑ ϵ ij k T k .
Keep the chosen generators explicit when comparing formulas. See
Commutators and Anticommutators
and SU(2) .
Write
σ = ( σ x , σ y , σ z ) \boldsymbol{\sigma}
=(\sigma_x,\sigma_y,\sigma_z) σ = ( σ x , σ y , σ z )
and, for a ∈ R 3 \mathbf a\in\mathbb R^3 a ∈ R 3 ,
a ⋅ σ = a x σ x + a y σ y + a z σ z . \mathbf a\cdot\boldsymbol{\sigma}
=a_x\sigma_x+a_y\sigma_y+a_z\sigma_z. a ⋅ σ = a x σ x + a y σ y + a z σ z .
The multiplication table implies
( a ⋅ σ ) ( b ⋅ σ ) = ( a ⋅ b ) I + i ( a × b ) ⋅ σ . (\mathbf a\cdot\boldsymbol{\sigma})
(\mathbf b\cdot\boldsymbol{\sigma})
=
(\mathbf a\cdot\mathbf b)I
+i(\mathbf a\times\mathbf b)
\cdot\boldsymbol{\sigma}. ( a ⋅ σ ) ( b ⋅ σ ) = ( a ⋅ b ) I + i ( a × b ) ⋅ σ .
Consequently,
[ a ⋅ σ , b ⋅ σ ] = 2 i ( a × b ) ⋅ σ , { a ⋅ σ , b ⋅ σ } = 2 ( a ⋅ b ) I . \begin{aligned}
[
\mathbf a\cdot\boldsymbol{\sigma},
\mathbf b\cdot\boldsymbol{\sigma}
]
&=
2i(\mathbf a\times\mathbf b)
\cdot\boldsymbol{\sigma},\\
\{
\mathbf a\cdot\boldsymbol{\sigma},
\mathbf b\cdot\boldsymbol{\sigma}
\}
&=
2(\mathbf a\cdot\mathbf b)I.
\end{aligned} [ a ⋅ σ , b ⋅ σ ] { a ⋅ σ , b ⋅ σ } = 2 i ( a × b ) ⋅ σ , = 2 ( a ⋅ b ) I .
Setting b = a \mathbf b=\mathbf a b = a gives
( a ⋅ σ ) 2 = ∥ a ∥ 2 I . (\mathbf a\cdot\boldsymbol{\sigma})^2
=\lVert\mathbf a\rVert^2I. ( a ⋅ σ ) 2 = ∥ a ∥ 2 I .
These identities extend bilinearly to complex coordinate vectors, but then
a ⋅ b \mathbf a\cdot\mathbf b a ⋅ b means the bilinear dot product
∑ i a i b i \sum_i a_i b_i ∑ i a i b i , not the Hermitian inner product
∑ i a i ∗ b i \sum_i a_i^*b_i ∑ i a i ∗ b i .
The four matrices σ μ \sigma_\mu σ μ , with μ ∈ { 0 , x , y , z } \mu\in\{0,x,y,z\} μ ∈ { 0 , x , y , z } , are orthogonal in
the Hilbert–Schmidt inner product:
tr ( σ μ † σ ν ) = 2 δ μ ν . \operatorname{tr}
(\sigma_\mu^\dagger\sigma_\nu)
=2\delta_{\mu\nu}. tr ( σ μ † σ ν ) = 2 δ μν .
Useful trace identities include
tr ( σ i σ j ) = 2 δ i j , tr ( σ i σ j σ k ) = 2 i ϵ i j k , tr ( σ i σ j σ k σ ℓ ) = 2 ( δ i j δ k ℓ − δ i k δ j ℓ + δ i ℓ δ j k ) . \begin{aligned}
\operatorname{tr}(\sigma_i\sigma_j)
&=2\delta_{ij},\\
\operatorname{tr}(\sigma_i\sigma_j\sigma_k)
&=2i\epsilon_{ijk},\\
\operatorname{tr}
(\sigma_i\sigma_j\sigma_k\sigma_\ell)
&=
2\bigl(
\delta_{ij}\delta_{k\ell}
-\delta_{ik}\delta_{j\ell}
+\delta_{i\ell}\delta_{jk}
\bigr).
\end{aligned} tr ( σ i σ j ) tr ( σ i σ j σ k ) tr ( σ i σ j σ k σ ℓ ) = 2 δ ij , = 2 i ϵ ij k , = 2 ( δ ij δ k ℓ − δ ik δ j ℓ + δ i ℓ δ j k ) .
The four-factor identity follows by multiplying the first two matrices,
multiplying the last two, and using trace orthogonality.
Every M ∈ M 2 ( C ) M\in M_2(\mathbb C) M ∈ M 2 ( C ) has a unique expansion
M = m 0 I + m ⋅ σ , M=m_0I+\mathbf m\cdot\boldsymbol{\sigma}, M = m 0 I + m ⋅ σ ,
where m 0 , m x , m y , m z ∈ C m_0,m_x,m_y,m_z\in\mathbb C m 0 , m x , m y , m z ∈ C . Trace orthogonality extracts the
coefficients:
m 0 = 1 2 tr M , m i = 1 2 tr ( σ i M ) . \begin{aligned}
m_0
&=\frac12\operatorname{tr}M,\\
m_i
&=\frac12\operatorname{tr}(\sigma_iM).
\end{aligned} m 0 m i = 2 1 tr M , = 2 1 tr ( σ i M ) .
For
M = ( a b c d ) , M=
\begin{pmatrix}
a&b\\
c&d
\end{pmatrix}, M = ( a c b d ) ,
the coordinates are
m 0 = a + d 2 , m x = b + c 2 , m y = c − b 2 i , m z = a − d 2 . \begin{aligned}
m_0&=\frac{a+d}{2},
&
m_x&=\frac{b+c}{2},\\
m_y&=\frac{c-b}{2i},
&
m_z&=\frac{a-d}{2}.
\end{aligned} m 0 m y = 2 a + d , = 2 i c − b , m x m z = 2 b + c , = 2 a − d .
The matrix M M M is Hermitian exactly when m 0 m_0 m 0 and all three components of
m \mathbf m m are real. Thus
{ I , σ x , σ y , σ z } \{I,\sigma_x,\sigma_y,\sigma_z\} { I , σ x , σ y , σ z }
is a complex basis for all 2 × 2 2\times2 2 × 2 matrices and a real basis for the
Hermitian ones.
Using the Pauli-vector square,
( m 0 I + m ⋅ σ ) ( m 0 I − m ⋅ σ ) = ( m 0 2 − m ⋅ m ) I . \begin{aligned}
&(m_0I+\mathbf m\cdot\boldsymbol{\sigma})
(m_0I-\mathbf m\cdot\boldsymbol{\sigma})\\
&\qquad
=
\bigl(m_0^2-\mathbf m\cdot\mathbf m\bigr)I.
\end{aligned} ( m 0 I + m ⋅ σ ) ( m 0 I − m ⋅ σ ) = ( m 0 2 − m ⋅ m ) I .
Therefore
det M = m 0 2 − m ⋅ m . \det M
=m_0^2-\mathbf m\cdot\mathbf m. det M = m 0 2 − m ⋅ m .
For a Hermitian matrix, m ∈ R 3 \mathbf m\in\mathbb R^3 m ∈ R 3 , so the eigenvalues are
λ ± = m 0 ± ∥ m ∥ . \lambda_\pm
=m_0\pm\lVert\mathbf m\rVert. λ ± = m 0 ± ∥ m ∥ .
If det M ≠ 0 \det M\ne0 det M = 0 ,
M − 1 = m 0 I − m ⋅ σ m 0 2 − m ⋅ m . M^{-1}
=
\frac{
m_0I-\mathbf m\cdot\boldsymbol{\sigma}
}{
m_0^2-\mathbf m\cdot\mathbf m
}. M − 1 = m 0 2 − m ⋅ m m 0 I − m ⋅ σ .
This is the 2 × 2 2\times2 2 × 2 adjugate formula written in Pauli coordinates. For a
general complex m \mathbf m m , no complex conjugation appears in
m ⋅ m \mathbf m\cdot\mathbf m m ⋅ m .
Let n ∈ R 3 \mathbf n\in\mathbb R^3 n ∈ R 3 be a unit vector and define
σ n = n ⋅ σ . \sigma_{\mathbf n}
=\mathbf n\cdot\boldsymbol{\sigma}. σ n = n ⋅ σ .
Then
σ n † = σ n , σ n 2 = I . \sigma_{\mathbf n}^\dagger
=\sigma_{\mathbf n},
\qquad
\sigma_{\mathbf n}^2=I. σ n † = σ n , σ n 2 = I .
Its eigenvalues are ± 1 \pm1 ± 1 , and its spectral projectors are
P ± ( n ) = 1 2 ( I ± n ⋅ σ ) . P_\pm(\mathbf n)
=\frac12
\left(
I\pm\mathbf n\cdot\boldsymbol{\sigma}
\right). P ± ( n ) = 2 1 ( I ± n ⋅ σ ) .
They obey
P ± 2 = P ± , P + P − = 0 , P + + P − = I , σ n = P + − P − . \begin{aligned}
P_\pm^2&=P_\pm,\\
P_+P_-&=0,\\
P_++P_-&=I,\\
\sigma_{\mathbf n}&=P_+-P_-.
\end{aligned} P ± 2 P + P − P + + P − σ n = P ± , = 0 , = I , = P + − P − .
This provides a basis-free way to diagonalize any non-scalar Hermitian
2 × 2 2\times2 2 × 2 matrix:
M = λ + P + ( m ^ ) + λ − P − ( m ^ ) , M
=\lambda_+P_+(\widehat{\mathbf m})
+\lambda_-P_-(\widehat{\mathbf m}), M = λ + P + ( m ) + λ − P − ( m ) ,
where m ^ = m / ∥ m ∥ \widehat{\mathbf m}=\mathbf m/\lVert\mathbf m\rVert m = m / ∥ m ∥ .
Because σ n 2 = I \sigma_{\mathbf n}^2=I σ n 2 = I , even and odd powers separate:
e z σ n = ∑ r = 0 ∞ z 2 r ( 2 r ) ! I + ∑ r = 0 ∞ z 2 r + 1 ( 2 r + 1 ) ! σ n = cosh z I + sinh z σ n . \begin{aligned}
e^{z\sigma_{\mathbf n}}
&=
\sum_{r=0}^{\infty}
\frac{z^{2r}}{(2r)!}I\\
&\quad+
\sum_{r=0}^{\infty}
\frac{z^{2r+1}}{(2r+1)!}
\sigma_{\mathbf n}\\
&=
\cosh z\,I
+\sinh z\,\sigma_{\mathbf n}.
\end{aligned} e z σ n = r = 0 ∑ ∞ ( 2 r )! z 2 r I + r = 0 ∑ ∞ ( 2 r + 1 )! z 2 r + 1 σ n = cosh z I + sinh z σ n .
With z = − i θ / 2 z=-i\theta/2 z = − i θ /2 ,
exp ( − i θ 2 n ⋅ σ ) = cos θ 2 I − i sin θ 2 n ⋅ σ . \exp\left(
-\frac{i\theta}{2}
\mathbf n\cdot\boldsymbol{\sigma}
\right)
=
\cos\frac{\theta}{2}\,I
-i\sin\frac{\theta}{2}\,
\mathbf n\cdot\boldsymbol{\sigma}. exp ( − 2 i θ n ⋅ σ ) = cos 2 θ I − i sin 2 θ n ⋅ σ .
More generally, if
M = m 0 I + r σ n , M=m_0I+r\sigma_{\mathbf n}, M = m 0 I + r σ n ,
then the scalar part commutes with the traceless part and
e M = e m 0 ( cosh r I + sinh r σ n ) . e^M
=e^{m_0}
\left(
\cosh r\,I
+\sinh r\,\sigma_{\mathbf n}
\right). e M = e m 0 ( cosh r I + sinh r σ n ) .
The limiting case r = 0 r=0 r = 0 is simply e m 0 I e^{m_0}I e m 0 I . See
Matrix Functions and Exponentials
for the general matrix construction.
Define
U ( n , θ ) = exp ( − i θ 2 n ⋅ σ ) . U(\mathbf n,\theta)
=
\exp\left(
-\frac{i\theta}{2}
\mathbf n\cdot\boldsymbol{\sigma}
\right). U ( n , θ ) = exp ( − 2 i θ n ⋅ σ ) .
This matrix is unitary with determinant one. Conjugation rotates Pauli
coordinates:
U ( n , θ ) ( a ⋅ σ ) U ( n , θ ) † = ( R n ( θ ) a ) ⋅ σ , U(\mathbf n,\theta)
(\mathbf a\cdot\boldsymbol{\sigma})
U(\mathbf n,\theta)^\dagger
=
\bigl(R_{\mathbf n}(\theta)\mathbf a\bigr)
\cdot\boldsymbol{\sigma}, U ( n , θ ) ( a ⋅ σ ) U ( n , θ ) † = ( R n ( θ ) a ) ⋅ σ ,
where Rodrigues’ formula is
R n ( θ ) a = a cos θ + ( n × a ) sin θ + n ( n ⋅ a ) ( 1 − cos θ ) . \begin{aligned}
R_{\mathbf n}(\theta)\mathbf a
&=
\mathbf a\cos\theta
+(\mathbf n\times\mathbf a)\sin\theta\\
&\quad+
\mathbf n(\mathbf n\cdot\mathbf a)
(1-\cos\theta).
\end{aligned} R n ( θ ) a = a cos θ + ( n × a ) sin θ + n ( n ⋅ a ) ( 1 − cos θ ) .
The half-angle in U U U and the full angle in R n R_{\mathbf n} R n are both
essential. Their group-theoretic meaning is developed in SU(2) ;
the physical spin action belongs to
Spin Rotations .
Consider the Hermitian matrix
H = ( 3 1 − i 1 + i 1 ) . H=
\begin{pmatrix}
3&1-i\\
1+i&1
\end{pmatrix}. H = ( 3 1 + i 1 − i 1 ) .
Its Pauli coordinates are
H = 2 I + σ x + σ y + σ z . H=2I+\sigma_x+\sigma_y+\sigma_z. H = 2 I + σ x + σ y + σ z .
Thus m = ( 1 , 1 , 1 ) \mathbf m=(1,1,1) m = ( 1 , 1 , 1 ) and
∥ m ∥ = 3 \lVert\mathbf m\rVert=\sqrt3 ∥ m ∥ = 3 . Without solving a characteristic polynomial,
λ ± = 2 ± 3 . \lambda_\pm=2\pm\sqrt3. λ ± = 2 ± 3 .
The spectral projectors are
P ± = 1 2 [ I ± σ x + σ y + σ z 3 ] , P_\pm
=\frac12
\left[
I\pm
\frac{
\sigma_x+\sigma_y+\sigma_z
}{\sqrt3}
\right], P ± = 2 1 [ I ± 3 σ x + σ y + σ z ] ,
so
H = ( 2 + 3 ) P + + ( 2 − 3 ) P − . H=(2+\sqrt3)P_+
+(2-\sqrt3)P_-. H = ( 2 + 3 ) P + + ( 2 − 3 ) P − .
The determinant is
det H = 2 2 − 3 = 1 , \det H=2^2-3=1, det H = 2 2 − 3 = 1 ,
and the inverse follows immediately:
H − 1 = 2 I − σ x − σ y − σ z = ( 1 − 1 + i − 1 − i 3 ) . \begin{aligned}
H^{-1}
&=2I-\sigma_x-\sigma_y-\sigma_z\\
&=
\begin{pmatrix}
1&-1+i\\
-1-i&3
\end{pmatrix}.
\end{aligned} H − 1 = 2 I − σ x − σ y − σ z = ( 1 − 1 − i − 1 + i 3 ) .
For q q q two-dimensional factors, define a Pauli string
Σ μ = σ μ 1 ⊗ ⋯ ⊗ σ μ q , μ r ∈ { 0 , x , y , z } . \begin{aligned}
\Sigma_{\boldsymbol{\mu}}
&=
\sigma_{\mu_1}\otimes\cdots\otimes\sigma_{\mu_q},
\\
\mu_r
&\in\{0,x,y,z\}.
\end{aligned} Σ μ μ r = σ μ 1 ⊗ ⋯ ⊗ σ μ q , ∈ { 0 , x , y , z } .
There are 4 q 4^q 4 q such matrices, exactly the complex dimension of
M 2 q ( C ) M_{2^q}(\mathbb C) M 2 q ( C ) . Tensor-product trace factorization gives
tr ( Σ μ † Σ ν ) = 2 q δ μ ν . \operatorname{tr}
\left(
\Sigma_{\boldsymbol{\mu}}^\dagger
\Sigma_{\boldsymbol{\nu}}
\right)
=
2^q\delta_{\boldsymbol{\mu}\boldsymbol{\nu}}. tr ( Σ μ † Σ ν ) = 2 q δ μ ν .
Hence every 2 q × 2 q 2^q\times2^q 2 q × 2 q matrix has the expansion
M = ∑ μ c μ Σ μ , c μ = 1 2 q tr ( Σ μ M ) . M
=
\sum_{\boldsymbol{\mu}}
c_{\boldsymbol{\mu}}
\Sigma_{\boldsymbol{\mu}},
\qquad
c_{\boldsymbol{\mu}}
=
\frac{1}{2^q}
\operatorname{tr}
\left(
\Sigma_{\boldsymbol{\mu}}M
\right). M = μ ∑ c μ Σ μ , c μ = 2 q 1 tr ( Σ μ M ) .
The formula is useful in spin systems and quantum information, but its matrix
ordering depends on the tensor-factor convention. See
Tensor Products .
Pauli Group and Stabilizers adds the phase-rich group, signed commuting constraints, stabilized-sector counting, and finite error-signature audits; this page retains the one-qubit matrix calculus and Pauli-string operator basis.
The matrices themselves are mathematical objects. Several physical uses add
different layers of interpretation:
spin-1 / 2 1/2 1/2 components use S i = ℏ σ i / 2 S_i=\hbar\sigma_i/2 S i = ℏ σ i /2 ;
two-level Hamiltonians use a scalar term plus a Pauli vector;
one-qubit density operators use a trace-one positive Pauli expansion;
spin rotations use the SU(2) exponential;
Pauli strings provide operator bases for many two-level factors.
Those applications should not be conflated. In particular, a Pauli matrix is
dimensionless, while a spin component carries units of angular momentum.
The canonical two-level dynamics treatment is
Pauli-Matrix Hamiltonians .
For a computed 2 × 2 2\times2 2 × 2 matrix, extract Pauli coefficients by traces and
reconstruct the matrix. The relative residual
ϵ = ∥ M − m 0 I − m ⋅ σ ∥ ∥ M ∥ \epsilon
=
\frac{
\lVert
M-m_0I-\mathbf m\cdot\boldsymbol{\sigma}
\rVert
}{
\lVert M\rVert
} ϵ = ∥ M ∥ ∥ M − m 0 I − m ⋅ σ ∥
should be consistent with numerical precision.
For a nominally Hermitian matrix, inspect the imaginary parts of
m 0 , m x , m y , m z m_0,m_x,m_y,m_z m 0 , m x , m y , m z . Small imaginary components may be roundoff; large ones
signal a genuinely non-Hermitian input or an inconsistent convention.
Before comparing Pauli-string coefficients from two codes, verify factor
order, basis order, and the sign convention for σ y \sigma_y σ y .
Reversing the signs of the off-diagonal entries in σ y \sigma_y σ y .
Forgetting that σ i σ j \sigma_i\sigma_j σ i σ j changes sign when distinct indices are
reversed.
Dropping the factor of two in Pauli commutators.
Using a Hermitian inner product instead of the bilinear dot product in the
complex Pauli-vector multiplication identity.
Applying Pauli-coordinate eigenvalue formulas to a non-Hermitian matrix
while treating the coordinates as real.
Confusing σ i \sigma_i σ i with the dimensionful spin operator
ℏ σ i / 2 \hbar\sigma_i/2 ℏ σ i /2 .
Using θ \theta θ instead of θ / 2 \theta/2 θ /2 in the SU(2) exponential.
Assuming the basis ordering of a Pauli string is implicit.
Applying scalar functions entry by entry rather than through the matrix
algebra.
Verify directly that
σ x σ y = i σ z , σ y σ x = − i σ z . \sigma_x\sigma_y=i\sigma_z,
\qquad
\sigma_y\sigma_x=-i\sigma_z. σ x σ y = i σ z , σ y σ x = − i σ z .
Use these products to compute
[ σ x , σ y ] [\sigma_x,\sigma_y] [ σ x , σ y ] and { σ x , σ y } \{\sigma_x,\sigma_y\} { σ x , σ y } .
Solution
Direct multiplication gives
σ x σ y = ( i 0 0 − i ) = i σ z , σ y σ x = ( − i 0 0 i ) = − i σ z . \begin{aligned}
\sigma_x\sigma_y
&=
\begin{pmatrix}
i&0\\
0&-i
\end{pmatrix}
=i\sigma_z,\\[4pt]
\sigma_y\sigma_x
&=
\begin{pmatrix}
-i&0\\
0&i
\end{pmatrix}
=-i\sigma_z.
\end{aligned} σ x σ y σ y σ x = ( i 0 0 − i ) = i σ z , = ( − i 0 0 i ) = − i σ z .
Therefore
[ σ x , σ y ] = 2 i σ z , { σ x , σ y } = 0. \begin{aligned}
[\sigma_x,\sigma_y]
&=2i\sigma_z,\\
\{\sigma_x,\sigma_y\}
&=0.
\end{aligned} [ σ x , σ y ] { σ x , σ y } = 2 i σ z , = 0.
Decompose
M = ( 1 2 − i 2 + i 3 ) M=
\begin{pmatrix}
1&2-i\\
2+i&3
\end{pmatrix} M = ( 1 2 + i 2 − i 3 )
in the Pauli basis and find its eigenvalues without expanding a
determinant.
Solution
The coefficient formulas give
m 0 = 2 , m x = 2 , m y = 1 , m z = − 1. \begin{aligned}
m_0&=2,
&
m_x&=2,\\
m_y&=1,
&
m_z&=-1.
\end{aligned} m 0 m y = 2 , = 1 , m x m z = 2 , = − 1.
Thus
M = 2 I + 2 σ x + σ y − σ z . M=2I+2\sigma_x+\sigma_y-\sigma_z. M = 2 I + 2 σ x + σ y − σ z .
The Pauli vector has norm
∥ m ∥ = 2 2 + 1 2 + ( − 1 ) 2 = 6 , \lVert\mathbf m\rVert
=\sqrt{2^2+1^2+(-1)^2}
=\sqrt6, ∥ m ∥ = 2 2 + 1 2 + ( − 1 ) 2 = 6 ,
so
λ ± = 2 ± 6 . \lambda_\pm=2\pm\sqrt6. λ ± = 2 ± 6 .
Derive the Pauli-vector identity
( a ⋅ σ ) ( b ⋅ σ ) = ( a ⋅ b ) I + i ( a × b ) ⋅ σ \begin{aligned}
(\mathbf a\cdot\boldsymbol{\sigma})
(\mathbf b\cdot\boldsymbol{\sigma})
&=
(\mathbf a\cdot\mathbf b)I\\
&\quad+
i(\mathbf a\times\mathbf b)
\cdot\boldsymbol{\sigma}
\end{aligned} ( a ⋅ σ ) ( b ⋅ σ ) = ( a ⋅ b ) I + i ( a × b ) ⋅ σ
from the component multiplication rule.
Solution
Set
X = ( a ⋅ σ ) ( b ⋅ σ ) X=(\mathbf a\cdot\boldsymbol{\sigma})
(\mathbf b\cdot\boldsymbol{\sigma}) X = ( a ⋅ σ ) ( b ⋅ σ ) .
Expanding both Pauli vectors gives
X = ∑ i , j a i b j σ i σ j = ∑ i , j a i b j δ i j I + i ∑ i , j , k a i b j ϵ i j k σ k . \begin{aligned}
X
&=
\sum_{i,j}a_i b_j\sigma_i\sigma_j\\
&=
\sum_{i,j}a_i b_j\delta_{ij}I\\
&\quad+
i\sum_{i,j,k}
a_i b_j\epsilon_{ijk}\sigma_k.
\end{aligned} X = i , j ∑ a i b j σ i σ j = i , j ∑ a i b j δ ij I + i i , j , k ∑ a i b j ϵ ij k σ k .
The Kronecker-delta term is
∑ i a i b i I = ( a ⋅ b ) I . \sum_i a_i b_i I
=(\mathbf a\cdot\mathbf b)I. i ∑ a i b i I = ( a ⋅ b ) I .
The coefficient of σ k \sigma_k σ k in the second term is
∑ i , j ϵ i j k a i b j = ( a × b ) k . \sum_{i,j}\epsilon_{ijk}a_i b_j
=(\mathbf a\times\mathbf b)_k. i , j ∑ ϵ ij k a i b j = ( a × b ) k .
Combining the terms proves the identity.
Let
U z ( θ ) = exp ( − i θ 2 σ z ) . U_z(\theta)
=
\exp\left(-\frac{i\theta}{2}\sigma_z\right). U z ( θ ) = exp ( − 2 i θ σ z ) .
Show that
U z ( θ ) σ x U z ( θ ) † = cos θ σ x + sin θ σ y . U_z(\theta)\sigma_xU_z(\theta)^\dagger
=
\cos\theta\,\sigma_x
+\sin\theta\,\sigma_y. U z ( θ ) σ x U z ( θ ) † = cos θ σ x + sin θ σ y .
Solution
The exponential formula gives
U z ( θ ) = c I − i s σ z , c = cos θ 2 , s = sin θ 2 . \begin{aligned}
U_z(\theta)
&=cI-is\sigma_z,\\
c&=\cos\frac{\theta}{2},\\
s&=\sin\frac{\theta}{2}.
\end{aligned} U z ( θ ) c s = c I − i s σ z , = cos 2 θ , = sin 2 θ .
Its adjoint is U z † = c I + i s σ z U_z^\dagger=cI+is\sigma_z U z † = c I + i s σ z . Therefore
U z σ x U z † = ( c I − i s σ z ) σ x ( c I + i s σ z ) = ( c 2 − s 2 ) σ x + 2 c s σ y . \begin{aligned}
U_z\sigma_xU_z^\dagger
&=
(cI-is\sigma_z)
\sigma_x
(cI+is\sigma_z)\\
&=
(c^2-s^2)\sigma_x
+2cs\,\sigma_y.
\end{aligned} U z σ x U z † = ( c I − i s σ z ) σ x ( c I + i s σ z ) = ( c 2 − s 2 ) σ x + 2 cs σ y .
Here
σ z σ x = i σ y , σ x σ z = − i σ y , \sigma_z\sigma_x=i\sigma_y,
\qquad
\sigma_x\sigma_z=-i\sigma_y, σ z σ x = i σ y , σ x σ z = − i σ y ,
and σ z σ x σ z = − σ x \sigma_z\sigma_x\sigma_z=-\sigma_x σ z σ x σ z = − σ x were used. The double-angle
identities c 2 − s 2 = cos θ c^2-s^2=\cos\theta c 2 − s 2 = cos θ and 2 c s = sin θ 2cs=\sin\theta 2 cs = sin θ complete the proof.
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