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Probability Checklist

Probability is the language connecting quantum states to measurement outcomes. Quantum mechanics changes how probabilities are computed, but it does not remove the need to understand normalization, expectation values, variance, conditioning, and probability densities.

This checklist focuses on the classical probability skills needed before reading the Born rule, expectation values, density matrices, and measurement pages.

  • Normalize a finite probability distribution.
  • Normalize a probability density.
  • Distinguish probabilities from probability densities.
  • Compute expectation values for discrete and continuous variables.
  • Compute variances and standard deviations.
  • Use conditional probability.
  • Apply Bayes’ rule in simple cases.
  • Recognize independent and correlated variables.
  • Interpret a covariance.
  • Distinguish an ensemble distribution from a single outcome.
  • Check that probabilities are nonnegative and sum or integrate to one.

The Born rule assigns probabilities to measurement outcomes. Expectation values are averages over possible outcomes, not necessarily values obtained in a single trial. Variance measures the spread of a prepared state’s outcome distribution. Density operators describe mixtures and subsystems. Open systems, quantum information, and statistical mechanics all rely on probabilistic reasoning.

The recurring mistake is to treat a probability amplitude as a probability. Amplitudes can add and interfere; probabilities are nonnegative real numbers obtained after the appropriate quantum rule is applied.

You should be comfortable with:

TaskExample
Normalize probabilitiesp1+p2+p3=1p_1+p_2+p_3=1
Normalize a density∫abρ(x) dx=1\int_a^b \rho(x)\,dx=1
Compute an expectationE[X]=∑xx p(x)\mathbb E[X]=\sum_x x\,p(x)
Compute a varianceVar⁡(X)=E[X2]−E[X]2\operatorname{Var}(X)=\mathbb E[X^2]-\mathbb E[X]^2
Use conditional probabilityP(A∣B)=P(A∩B)/P(B)P(A\mid B)=P(A\cap B)/P(B)
Distinguish density from probabilityP(a<X<b)=∫abρ(x) dxP(a<X<b)=\int_a^b \rho(x)\,dx
  1. Let a discrete random variable take values −1,0,1-1,0,1 with probabilities 1/4,1/2,1/41/4,1/2,1/4. Compute its expectation value and variance.
Solution

The expectation value is

E[X]=(−1)14+012+114=0.\mathbb E[X] =(-1)\frac14+0\frac12+1\frac14 =0.

The second moment is E[X2]=1/4+1/4=1/2\mathbb E[X^2]=1/4+1/4=1/2, so

Var⁡(X)=E[X2]−E[X]2=12.\operatorname{Var}(X) =\mathbb E[X^2]-\mathbb E[X]^2 =\frac12.
  1. Let ρ(x)=2x\rho(x)=2x on 0<x<10<x<1. Verify normalization and compute E[X]\mathbb E[X].
Solution

Normalization:

∫012x dx=1.\int_0^1 2x\,dx=1.

The expectation value is

E[X]=∫01x(2x) dx=2∫01x2 dx=23.\mathbb E[X] =\int_0^1 x(2x)\,dx =2\int_0^1 x^2\,dx =\frac{2}{3}.
  1. A test detects a condition with probability 0.90.9 if the condition is present and has false-positive probability 0.10.1 if it is absent. If the prior probability of the condition is 0.20.2, what is P(condition∣positive)P(\text{condition}\mid\text{positive})?
Solution

Bayes’ rule gives

P(C∣+)=P(+∣C)P(C)P(+∣C)P(C)+P(+∣¬C)P(¬C)=0.9⋅0.20.9⋅0.2+0.1⋅0.8=0.180.26=913.P(C\mid +) =\frac{P(+\mid C)P(C)} {P(+\mid C)P(C)+P(+\mid \neg C)P(\neg C)} =\frac{0.9\cdot0.2}{0.9\cdot0.2+0.1\cdot0.8} =\frac{0.18}{0.26} =\frac{9}{13}.
  1. Why is ρ(x)\rho(x) not itself the probability of finding a particle at exactly xx?
Solution

For a continuous variable, probabilities are assigned to intervals. The probability of finding XX in [a,b][a,b] is ∫abρ(x) dx\int_a^b\rho(x)\,dx. The density ρ(x)\rho(x) can have units and can be larger than one; it becomes a probability only after integration over a region.

Use these pages when a checklist item is weak:

  • W. Feller, An Introduction to Probability Theory and Its Applications, Vol. 1, 3rd ed., Wiley, 1968.
  • S. Ross, A First Course in Probability, 10th ed., Pearson, 2018.
  • A. Papoulis and S. U. Pillai, Probability, Random Variables, and Stochastic Processes, 4th ed., McGraw-Hill, 2002.